Write 120% as a fraction.

Answers

Answer 1

Answer: 6/5 because each 1 equals 20%. so 1/5=20%, 2/5=40%, 3/5=60% and so 5/5=100% so 6/5=120%. hopefully that helps.

Answer 2

Answer:

120% as a fraction in simplest form is 6/5.

What is a fraction?

In Mathematics and Geometry, a fraction simply refers to a numerical quantity (numeral) which is not expressed as a whole number. This ultimately implies that, a fraction is simply a part of a whole number.

In this exercise and scenario, we would convert the given percentage 120% into a fraction by dividing as follows;

120% = 120/100

By dividing both the numerator and denominator by 20, we have:

Fraction: 120/100 = 6/5.

Read more on fraction here: brainly.com/question/29367657

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Plzzzzz help............Twelve decreased by twice a number is the same as 8 times the sum of the number plus 4. What is the number?Is the equation 2x-12=8(x+4)

Answers

Okay, the equation would be 12 - 2x = 8(x + 4), you got close!

what i would do first is distribute to get rid of those evil parenthesis and make this all simple ^-^

So, we take 8 times x, and 8 times 4.

Our equation, is now 12 - 2x = 8x + 32

Now, what i would do, is simplify it. Get x to one side, and a whole number to the other. Well, for me it would be easier to keep the larger number on the right, and x on the left!

So we have to be fair, and keep it equal! So, i would start with.... subtracting 32. Since its a positive 32, to cancel it out we have to subtract 32, to get to zero! so, by subtracting 32 on both sides ( 12 - 32 and 32 - 32) we end up with -20 - 2x = 8x

Now looking at - 20 - 2x = 8x, i can see what i need to do. i need to get x to one side, and whole numbers to the other. There are no whole numbers on the right, just variables and coefficients, so i have to get that x away from the left!

So, im going to add 2x on both sides, to eliminate it! So we add 2x on the left to cancel it out, and add 2 x on the right to balance it out! We are now left with -20 = 10x

Now what we do is we get rid of that tag along right by the x! Yep, that little 10 there! He has to go!

How to we get rid of him? Well, he is being multiplied by the x! So, we have to do the opposite and divide to get him alone. So, we divide by 10 on both sides, and we are left with -2 = x!

Now, time to check your answer! Basically, you replace x with -2 in the equation! Here we go:

12 - 2(-2) = 8(-2 + 4)

First we should start with multiplying! when we multiply the -2 in the equation, we get 12 + 4 = 8(2), and we can finish that off by simplifying it to 12 + 4 = 16

when we simplify it and add 12 + 4, we get 16. So we are left with 16 = 16.

This equation is true, so we are right! -2 DOES equal x!

NEED HELP!!! State two numbers such that the lesser number is 25% less than the greater number.

Answers

10 and 7.5 as a quarter of 10 is 2.5 and your take that from 10

Question 1 A system of equations is shown below:
n = 3m + 6
n − 2m = 2

What is the solution, in the form (m, n), to the system of equations?

(−4, −6)
(−5, −9)
(2, 6)
(1, 8)

Question 2

The incorrect work of a student to solve an equation 2(y + 6) = 4y is shown below:

STEP1: 2(y + 6) = 4y
Step 2: 2y + 8 = 4y
Step 3: 2y = 8
Step 4: y = 4

Which of the following explains how to correct Step 2 and shows the correct value of y?

2 should be distributed as 2y + 12; y = 6
2 should be distributed as 2y + 12; y = 3
The equation should be y + 6 = 4y after division by 2; y = 2
The equation should be y + 6 = 4y after division by 2; y = 1

Question 3
The equation 3.3x − 6.6 = 2.7x can be transformed to form which of the following expressions?

6.0x = 6.6
0.6x = 6.6
6.0x = −6.6
0.6x = −6.6

Answers

Answer:

Part 1: The solution is (-4,-6)

Part 2: 2 should be distributed as 2y + 12; y = 6

Part 3: $\text{The solution is }0.6x=6.6$

Step-by-step explanation:

Part 1: Given the system of equations

$n - 3m = 6$ → (1)

$n - 2m = 2$ → (2)

Solving above two equations

Subtract 2 from 1, we get

$n-3m-(n-2m)=6-2$

$2m-3m=4$

$m=-4$

(1) ⇒ $n=3(-4)+6=-12+6=-6$

The solution is (-4,-6)

Option 1 is correct.

Part 2: The incorrect work of a student to solve an equation 2(y + 6) = 4y

we have to choose the correct step to solve value of y

Equation: 2(y + 6) = 4y

By distributive property

2y+12=4y

2y=12 ⇒ y=6

Hence, 2 should be distributed as 2y + 12; y = 6

∴ Option 1 is correct.

Part 3: Given the equation 3.3x − 6.6 = 2.7x

we have to solve

3.3x − 6.6 = 2.7x

Subtracting 2.7x both sides

$3.3x-2.7x=6.6$

$0.6x=6.6$

Option 2 is correct.

Question 1:
$n = 3m + 6 \nn - 2m = 2 \n \n\hbox{substitute 3m+6 for n in the second equation:} \n3m+6-2m=2 \nm+6=2 \ \ \ \ \ \ \ \ \ \ \ \ \ |-6 \nm=-4 \n \nn=3m+6=3 * (-4)+6=-12+6=-6 \n \n(m,n)=(-4,-6)$

The answer is (-4,-6).

Question 2:
$2(y + 6) = 4y \n2 * y + 2 * 6=4y \n 2y+12=4y \ \ \ \ |-2y \n12=2y \ \ \ \ \ \ \ \ \ \ \ |/ 2 \ny=6$

The answer is: 2 should be distributed as 2y + 12; y = 6.

Question 3:
$3.3x-6.6=2.7x \ \ \ \ |-2.7x \n0.6x-6.6=0 \ \ \ \ \ \ \ \ |+6.6 \n0.6x=6.6$

The answer is 0.6x=6.6.

PLEASE HELP MEDavid and Ronald both are making cubic gift boxes with varying volume. The side length of David's gift box for a given volume is given by the function below, where (x - 1) is the volume of the box, in cubic feet.

The side length, g(x), of Ronald's gift box for a given volume is shown in the table below, where x is the volume of the box, in cubic feet.

Whose gift box has the greater side length for a given volume?