Test review ? Can you help me with solving 1-3 please

Answers

Answer 1

Answer: 1-3= -2 cause you basically subtract it how you normally would but then add a negative symbol infront of it

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Y= -2x-9 in standard form

If i travel 100 miles in 4 hours what is that unit rate

Answers

To find a unit rate you need to divide. We will divide 100 miles by 4 hours. What ever the answer is it will be your unit rate.

100 ÷ 4 = 25

CHECK OUR WORK:-

25 × 4 = 100

We were RIGHT!!!!!

So, 25 miles per hour.

Hope I helped ya!!

100 miles in 4 hours. The unit rate would be 25 miles per hour.

100miles / 4hrs = 25 miles per hour

Therefore, for every hour you travel, you will gain 25 miles. Or for every 25 miles you travel, you've spent 1 hour traveling it.

y = 25x
where y is the total miles traveled, 25 is the constant unit rate, and x is the number of hours traveled.

for example: you traveled for 8 hours and you want to know how long you've traveled while maintaining the rate of 25mph. Just use the formula

y = 25x
y = 25(8)
y = 200 miles. you have traveled 200 miles in 8 hours.

If f(x) = x2 - 2x and g(x) = 6x + 4, for which value of x does (f + g)(x) = 0?OOOO
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Answers

Answer:

x^2+4x+4

Step-by-step explanation:

f(x)=x^2-2x, g(x) =6x+4

(f+g)(x)=f(x)+g(x)

(f+g)(x)=x^2+4x+4

A table is 1 1/2 meters long.How many centimeters long is the table?

Answers

A meter is 100 cm. So, the final length is $1(1)/(2)*100=(3)/(2)*100=(300)/(2)=150$ cm.
150 cm.

The answer you are looking for is 150 centimeters

Fill in the following 5 statements and 5 reasons used to complete this proof.

Answers

Answer:

AD ≅ CD.

Step-by-step explanation:

Statement : consider triangles ADB and DBC.

1) AB = CD

2) ∠ABD = ∠DBC

3) DB = DB

4) ⇒ ΔADB and ΔDBC are congruent triangles.

5) AD = DC.

Reasons ;

1) given, AB = CB

2) given, DB bisects ∠ ABC

3) common side of both triangles

4) as two sides and one angle are equal in both triangles

5) congruent triangles

What is the simplest form of RootIndex 3 StartRoot 27 a cubed b Superscript 7 Baseline EndRoot?

Answers

Answer:

Step-by-step explanation:

If your on e2020 Then A is your answer

Can any one help me any of them especially (b)

Answers

b.) $x^{- (1)/(2) }(x^{ (3)/(2) }-x^2)=x^{- (1)/(2) }(x^{ (3)/(2) })-x^{- (1)/(2) }(x^2)}=x^{- (1)/(2) + (3)/(2) }-x^{- (1)/(2) +2}=x-x^{ (1)/(2)$

e.) $(1)/( √(x) ) (x^2- √(x) )= \frac{1}{ x^{ (1)/(2) } } (x^2-x^ (1)/(2) ) \n = x^{- (1)/(2) } (x^2-x^ (1)/(2) )=x^{- (1)/(2) }(x^2)-x^{- (1)/(2) }(x^ (1)/(2) )} \n =x^{- (1)/(2) +2}-x^{- (1)/(2) + (1)/(2) }=x^ (1)/(2) -x^0=x^ (1)/(2) -1$

I hope this helps you.