The area of a bathroom floor measures 2 yards by 3 yards and each custom tile that makes up the flooring is 1 1/2 square feet. How many tiles are needed to cover the floor?

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Answer 1
Answer: The dimensions of the bathroom floor is given as 2 yards by 3 yards.
Then
The area of the bathroom floor in question = (2 * 3) square yards
                                                                     = 6 square yards
We already know that
1 square yard = 9 square feet
So
The area of the bathroom floor in question = (6 * 9) square feet
                                                                     = 54 square feet
Area covered by each custom tiles = 11/2 square feet
Then
Number of tiles required to cover the bathroom floor = 54/(11/2)
                                                                                     = (54 * 2)/11
                                                                                     = 108/11
                                                                                     = 9.81
So the number of tiles required to cover the bathroom flooring is 10. Since fraction of tiles cannot be bought, so 10 tiles are required.

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[71 – (8 2+ 5)] (2 + 3)+ 7 × [2 × (7 3+ 17)] – 72 [40 + (4 2– 6)] (5 – 3)+ 3 × (1 + 4 3– 15) – 150

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Answer:

Step-by-step explanation:

2(3)+8. =6 + 8. = 35 x 102. = 3.5 x 10-1. 3.5 x 10". = 14 ... Substitute b with – 3 and solve. 3). A. 783. 5(-3)2-2(-3)+1. =5(9)+6+1. =45+7. =52 ... (4 – 5x) – (3 – 2x). (4 – 5x)+(-3+ 2x). _+(4 – 5x). +(-3+2x). 1- 3x.  to solve. ... (3r' -5+2x). “ - [(7x² +5)– (4x' – 5x)]. – L(7x² +5)– (4x' – 5x). =-|(7x² + 5) – 4x² + 5x].

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