What is the value of a in the equation 3a + b = 54, when b = 9?

Answers

Answer 1

Answer: If you would like to solve the equation 3 * a + b = 54, when b = 9, you can calculate this using the following steps:

b = 9
3 * a + b = 54
3 * a + 9 = 54
3 * a = 54 - 9
3 * a = 45 /3
a = 45/3
a = 15

The correct result would be 15.

Answer 2

Answer: $3a+b=54\n\n Substitute\ b\ =\ 9\ into\ the\ equation.\n\n3a+(9)=54\n\nSubtract\ 9\ on\ both\ sides.\n\n3a=45\n\nDivide\ by\ 3\ on\ both\ sides.\n\n{\boxed{a=15}$

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Evaluate:
90 over
-10

Answers

Answer:

-9

Step-by-step explanation:

Answer:

-9

Step-by-step explanation:

There are 50 teens in a work program. The circle graph shows the percentage of workers who have 0, 1, 2, 3, and 4 siblings.How many teens in the program have no siblings?

Answers

so there are 50 teens total
16% have no sibblings

so we must find 16% of 50
16%=16/100=0.16

'of' can be translated as multiply so
0.16 times 50=8
there were 8 teens who have no sibblings

ok so there are 50 teens
16% of the 50 teens don't have any siblings
16% of 50 means you multiply
of means multiplication
you can't multiply 16*50
16% as a decimal is.16 ( 16/100=.16=16% )
so now you multiply .16*50=8
there are 8 teens out of 50 who have no siblings
hope this helps ;)

A bank account has an initial deposit of $14,000. After 8 years, the bank accounthas $18,000. Assuming that compounding interest is done annually and that no
withdrawals are taken, find the annual interest rate on the investment. If the interest is compounded annually what is the approximate interest rate on the investment?

Answers

Answer:

2.3%

Step-by-step explanation:

18000 = 15000( 1 + i)^8

Divide both sides by 15000

1.2 = (1 + i)^8

Take both sides to the 1/8 power

1.2^(1/8) = 1 + i

1.023051875220463 = 1 + i

Subtract 1 from both sides

i = 0.023051875220463

~ 2.3%

Find the zeros of the function by rewriting in intercept form.Y=2X^2-4x

y=2C^2-11X-21

I need the answer and the work please.

Answers

The intercept form is $y=a(x-p)(x-q)$ where p, q - the zeroes of a function.

1.
$y=2x^2-4x \ny=2x(x-2) \ny=2(x-0)(x-2) \n\hbox{the zeroes - }\boxed{x=0 \ and \ x=2}$

2.
$y=2x^2-11x-21 \ny=2x^2-14x+3x-21 \ny=2x(x-7)+3(x-7) \ny=(2x+3)(x-7) \ny=2(x+(3)/(2))(x-7) \n y=2(x-(-(3)/(2)))(x-7) \n\hbox{the zeroes - }\boxed{x=-(3)/(2) \ and \ x=7}$

What are the next 2 terms in this sequence? -26,-20,-14_, _?