CHEMISTRY HIGH SCHOOL

Which of the following is not an example of a mineral crystal shape? A. Calcite
B. Kryptonite
C. Quartz
D. Pyrite

Answers

Answer 1
Answer: B. Kryptonite. The reason for this is that it is a nonexistent compound, or if it exists it is manmade and only able to survive for a few second. The suffix -tie indicates that is a bonded with oxygen, which, since Krypton is a noble gas, is impossible. also, crystals are formed from ionic bonds, and since both krypton and oxygen are non-metals, a bond between them would be covalent.

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Which of the following aqueous solutions will have the lowest vapor pressure at 25 degrees Celsius?a. 1.0 M CH4
b. 1.0 M NaCl
c. 1.0 M AlCl3
d. 1.0 M BaCl2

Answers

The choices experiences colligative properties. These set of properties depend on the amount of solute dissolved in a solvent. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering. From the choices, the correct answer is A.

Answer : The correct option is, (C) 1.0 M AlCl_3

Explanation :

According to the relative lowering of vapor pressure, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component of the solution multiplied by the vapor pressure of that component in the pure state.

1.0 M means that the 1.0 moles of solute present in 1 liter of solution.

Formula used :

(\Delta p)/(p^o)=i* X_B

where,

p^o = vapor pressure of the pure component (water)

p_s = vapor pressure of the solution  

X_B = mole fraction of solute

i = Van't Hoff factor

As we know that the vapor pressure depends on the mole fraction of solute and the Van't Hoff factor.

So, the greater the number of particles of solute dissolved the lower the resultant vapor pressure.

(a) The dissociation of 1.0 M CH_4 is not possible because it is a non-electrolyte solute. So, the Van't Hoff factor will be, 1.

(b) The dissociation of 1.0 M NaCl will be,

NaCl\rightarrow Na^++Cl^-

So, Van't Hoff factor = Number of solute particles = Na^++Cl^- = 1 + 1 = 2

(c) The dissociation of 1.0 M AlCl_3 will be,

AlCl_3\rightarrow Al^(3+)+3Cl^(-)

So, Van't Hoff factor = Number of solute particles = Al^(3+)+3Cl^(-) = 1 + 3 = 4

(c) The dissociation of 1.0 M BaCl_2 will be,

BaCl_2\rightarrow Ba^(2+)+2Cl^(-)

So, Van't Hoff factor = Number of solute particles = Ba^(2+)+2Cl^(-) = 1 + 2 = 3

From this we conclude that, 1.0 M AlCl_3 has the highest Van't Hoff factor which means that the solution will exhibit the lowest vapor pressure.

Hence, the correct option is, (C) 1.0 M AlCl_3

Which is a basic funcional group that can accept H+ and become positively charged? A) CH ₃ B) OH C) NH₂ D) COOH

Answers

C) NH2

EXPLANATION:
the amino group (NH2) is a basic, or alkaline, group which can accept a proton (H+) and become positively charged.

What is the oxidation number of sulfur in hydrogen sulfide

Answers

H₂S ( hydrogen sulfide ):

H =  + 1

S ( Sulfur ) =  - 2

hope this helps!

Rita divides Avogadro’s number (approximately 6.022 mc002-1.jpg 1023) by 2.0550 to calculate the number of atoms in a sample. Which expression gives her result to the correct number of significant figures?

Answers

Here you have two numbers. Avogadro's number is given with four significant figures, while number 2.0550 is given with five significant figures. That means that your result must be shown with four significant figures. So, 6.022 * 10 ^ 23 / 2.0550 = 2.930 * 10 ^ 23, which has been rounded to four significant figures. Answer: 2.930 * 10 ^ 23

Answer:

Answer is B

Explanation: Trust

If a shell can hold a maximum of 32 electrons, what is the value of n?

Answers


In my textbook it says that the maximum number of electrons that can fit in any given shell is given by 2n². Which would mean 2 electrons could fit in the first shell, 8 could fit in the second shell, 18 in the third shell, and 32 in the fourth shell. However, I was previously taught that the maximum number of electrons in the first orbit is 2, 8 in the second orbit, 8 in the third shell, 18 in the fourth orbit, 18 in the fifth orbit, 32 in the sixth orbit. I am fairly sure that orbits and shells are the same thing.

If you make an electromagnet using a battery circuit and a steel nail, how can you increase its magnetic strength? A. replace the nail with a copper rod B. wrap more coils of wire around the nail C. use a longer nail D. remove the plastic insulation from the wire coil

Answers

The correct answer is (b.) wrap more coils of wire around the nail. If you make an electromagnet using a battery circuit and a steel nail, you can actually increase its magnetic strength by wrapping more coils of wire around the nail.
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