the simple interest I (in dollars) for a savings account is jointly proportional to the product of time (in years) and the principal P (in dollars). After 11 months the interest on a principal of $3970 is $86. What is the constant of the variation

Answers

Answer 1

Answer: Simple interest I is jointly proportional to the product of time in years and the principal, therefore; mathematically;
I α Pt
introducing a constant;
I = kPt; but I = $ 86, P = $ 3970, while t = 11/12 years
Thus; k = I/Pt
= 86/ 3970(11/12)
= 0.0236
Therefore, the constant of the variation is ≈ 0.024

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Answers

P(10, 7) = 10!/(10 - 7)!
P(10, 7) = 10!/3!
P(10, 7) = (10✖️9✖️8✖️7✖️6✖️5✖️4✖️3✖️2✖️1)/(3✖️2✖️1)
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A bag of marbles has twice as many blue marbles as green marbles, and the bag has at least 54 marbles in it. At least how many green marbles does it have?

Answers

$b\ \ \ \rightarrow\ \ \ the\ number\ of\ blue\ marbles\ng\ \ \ \rightarrow\ \ \ the\ number\ of\ green\ marbles\n\nb+g \geq 54\ \ \ and\ \ \ b=2g\n\n2g+g \geq 54\ \ \ \Leftrightarrow\ \ \ 3g \geq 54\ \ \ \Leftrightarrow\ \ \ g \geq 18\n\nAns.\ At\ least\ 18\ green\ marbles.$

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Answers

If you would like to complete the factorization, you can do this using the following step:

9g^2 + 30g + 25 = (3g + 5) * (3g + 5) = (3g + 5)^2

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