A typical oil control ring consists of _______ separate part(s). A. three
B. four
C. two
D. one

Answers

Answer 1

Answer: A. three

Oil spill can be very harmful to marine life because the chemical make up of oils can be poisonous to marine life. The oil can also affect the natural body temperature of marine animals especially to the small fish. Sea otters and sea birds are the most commonly affected by oil spills and those other marine animals that can be found in the shoreline. Heavy oils like the bunker oils used to fuel ships are the most harmful oil because when this oil stick to birds feathers, they may have an inability to warm themselves that could lead them to die.

Answer 2

Answer:

Answer:

Three

Explanation:

Oil control rings are designed differently than compression rings. A typical oil control ring consists of three separate pieces: two very thin metal rings called scrapers, and a spacer ring called an expander placed in the groove between them.

Related Questions

I'm really confused about waves and I can't identify the period, frequency, velocity etc in a word problem. Please give examples with units!!! I'm failing science rn!!
What is a main sequence star?definition please:)
Which of these is the most likely impact of solar prominence on Earth? A) rerouting of aircraft B) increase in severity of hurricanes C) long-term electrical power generation D) improvement in satellite communication
Different velocity-time graph lines are shown, displaying the behavior of multiple race carts along a linear track.Which description correctly identifies cart C?A) Has a positive acceleration and is speeding up. B) Moving with zero acceleration. C) Moving at a constant acceleration. D) Has a negative acceleration and is slowing down.
How to solve for vi in vf=vi+at?

Factors that influence the balance of earth's incoming and outgoing radiation are called _____.

Answers

The factors that influence the balance of Earth's incoming and outgoing radiation are called "radiative forcings." These forcings can include natural factors like volcanic eruptions and solar variations, as well as human activities such as greenhouse gas emissions.

A small object with mass m = 0.0900 kg moves along the +x-axis. The only force on the object is a conservative force that has the potential-energy function U(x)=−αx2+βx3, where α=2.00J/m2 and β=0.300J/m3. The object is released from rest at small x. When the object is at x = 4.00 m, what are its (a) speed and (b) acceleration (magnitude and direction)? (c) What is the maximum value of x reached by the object during its motion?

Answers

The conservation of mechanical energy allows to find the results for the questions of the motion of mass in a conservative force are;

a) the velocity at x = 4 m is: v = 16.9 m / s

b) The acceleration at x = 4m is: a = 17.8 m / s²

c) The maximum elongations is: x = 6.67 m

Given parameters

The potential energy U = - α x² + β x³ with α= 2 j/m² and β= 0.3 j/m³

The mass of the body m = 0.0900 kg

The distance x = 4.00 m

To find

a) The speed

b) The acceleration

c) The maximum value of the distance

The conservation of mechanical energy is one of the most important concepts in physics, stable that if there is not friction the mechanical energy remains constant at all points.

Em = K + U

Where Em mechanical energy, K the kinetical energy ang U the potential energy.

a) Let's find the velocity using the conservation of mechanical energy

Starting point. Where the mass is released.

Em₀ = U (0)

Final point. When for a distance of x = 4 m here we have potential and kinetic energy.

$Em_f$ = K + U (4)

They indicate that the only force is conservative, therefore mechanicalenergy is conserved

Em₀ = $Em_f$

0 = ½ m v² + U (4)

½ m v² = -U (4)

v² = 2 / m (αx² - β x³)

Let's calculate

v² = $(2)/(0.09)$ (2 4² - 0.3 4³)

v = $√(284.44)$

v = 16.9 m / s

b) Acceleration is requested at this point.

We use that potential energy and force are related

F = $- ( dU)/(dx)$

We carry out the derivatives

F = 2αx - 3βx²

Let's calculate

F = 2 2 4 - 3 0.3 4²

F = 1.6 N

Now we use Newton's second law that relates the net force with the product of the mass and the acceleration of the body.

F = ma

a = $(F)/(m)$

a = $(1.6)/(0.09)$

a = 17.8 m / s²

c) At maximum displacement.

Let's use conservation of mechanical energy

Starting point. Where x = 0 is released

Emo = U (0) = 0

Final point. Point of maximum elongation, kinetic energy is zero

$Em_f$ = U (xmax)

Energy is conserved

Em₀ = $Em_f$

$0 = U(x_(max))$

-αx² + βx³ = 0

x² (-α + βx) = 0

the solutions of this equation is:

x = 0

-α + βx = 0

x = $(\alpha)/(\beta )$

Let's calculate

x = $(2)/(0.3)$

x = 6.67 m

In conclusion using the conservation of mechanical energy we can find the results for the questions of the motion of mass in a conservative force are;

a) the velocity at x = 4 m is: v = 16.9 m / s

b) The acceleration at x = 4m is: a = 17.8 m / s²

c) The maximum elongations is: x = 6.67 m

Learn more here: brainly.com/question/2615468

Answer:

a) v= 284.44 $(m)/(s^(2))$

b) a=17.78 $(m)/(s^(2) )$

c) x=6.67m

Explanation:

a).

$U(x)=-\alpha *x^(2) +\beta*x^(3)\n\alpha=2(J)/(m^(2))\n\beta=0.3(J)/(m^(2))\nU(0)+V(0)=U(4)+V(4)\nU(0)=-\alpha *0^(2) +\beta*0^(3)=0\nU(0)=0\nV(0)=0\n0=U(4)+V(4)\nU(4)=-\alpha *4^(2) +\beta*4^(3)\nU(4)=-2*4^(2)+0.3*(4^(3))\nU(4)=-12.8 J\n0=-12.8J+V(4)\n12.8=(1)/(2)*m*(v_(4))^(2) \n v_(4)^(2) =(2*12.8J)/(0.09kg)\n v_(4)^(2)=284.44$

$v_(4)=√(284.44)\nv_(4)=16.8 (m)/(s)$

b).

$F_(x)=(dU)/(dt)\nF_(x)=2*\alpha*x-3*\beta *x^(2) \nF_(4)=2*2*4-3*0.3*(4)^(2)\nF_(4)=1.6N\nF_(4)=m*a\na=(F_(4))/(m)=(1.6N)/(0.09kg)\na=17.7 (m)/(s^(2) )$

c).

$F_(x)=m*ax\nax=(F_(x))/(m) \nax=(4x-0.9x^(2))/(0.09kg)\n(dVx)/(dt)= (4x-0.9x^(2))/(0.09kg)\n\int\limits^x_x {(1)/(0.09)*(4x-0.9x^(2)) } \, dx\n (Vx^(2) )/(2)=22.2x^(2) -3.3x^(3)$

Value x,0

$Vx^(2) =44.4x^(2) -6.6x^(3)\n Vx=\sqrt{44.4x^(2) -6.6x^(3)}$

Inside the square root is the value of maximum value of x

$44.4x^(2) -6.6x^(3)=0\nx^(2)(44.4-6.6x)=0\n x=0$ but that value is not real so:

$44.4-6.6x=0\n6.6x=44.4\nx=(44.4)/(6.6)\n x=6.67m$

Would a tiger be a consumer or producer?

Answers

Tigers don't produce anything useful, but they are the top of their food chain. They would e top predators, and top predators are always consumers.

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!On a spring scale that measures force, a reading shows the force of an object to be about halfway between 7 N and 8 N. Which of the following would be the most accurate measurement for the force?

A. 0.0075 N

B. 0.75 N

C. 750 N

D. 7.5 N

Answers

Obviously D. 7.5

Why?

Well, 7.5 is exactly between 7 and 8.

Why does the number 54,289.00 have seven significant figures and not five

Answers

the 2 spots after the decimal still counts toward the total the figures

thought it was 5 at first too. the 00 past the decimal at significant because it's expressing it is exactly to that point. sort of confusing.
say you measured a pencil with a ruler, and say it was 5" long roughly. you can only scientifically put down that the pencil is 5 inches not 5.0000 because your ruler doesn't go that many decimal places. when something is absolute is the only time you can add .0000000000000000000000 to it and it still be correct. an example of something that is absolute is like you have 10 fingers, 10 is absolute because it's exact 10.0000000000000000=10 fingers it's not any more and not any less.
Those two zeros are included after the decimal so they aqre significant. The rule is all final zeros after the decimal are significant
Since there is a decimal point present, start with the leftmost nonzero didgit. Count that digit and every other digit to the right of it.

Resonance always causes the object resonating to fall apart or be destroyed. true or false

Answers

The statement about "Resonance always causes the object resonating to fall apart or be destroyed" is false. Resonance always causes the object near it to vibrate more.

Answer:

False

Explanation:

Other Questions

At height h above the surface of Earth, the gravitational acceleration is What is h? Note: The radius of Earth is 6380 km.

Any formation in which groundwater Rises on its own under pressure is a

The bigger an object is the smaller the force of gravity. True or False

an input force of 50 Newtons is applied through a distance of 10 meters to machine with mechanical advantage of 3. If the work output for the machine is 450 newton x meters and this work is applied through a distnace of 3 meters, what is the output force of the machine