An electromagnetic wave with frequency 65.0hz travels in an insulating magnetic material that has dielectric constant 3.64 and relative permeability 5.18 at this frequency. the electric field has amplitude 7.20×10−3v/m.what is the intensity of the wave in a medium\?

Answers

Answer 1

Answer:

The intensity of the electromagnetic wave which travels in an insulating magnetic material in a medium is 5.766×10⁻⁸ W/m².

What is the intensity of the wave?

The intensity of a wave is the total power delivered per unit area. It can be given as,

$I=(P)/(A)$

It can also be given as,

$I=(E^2)/(2)\sqrt{(k\varepsilon_o)/(\mu_r\mu_o)}$

Here, ( $\mu_r$ ) is relative permeability, ( $\mu_0$ ) is physical constant, (k) is dielectric constant, (E) is the amplitude of electric field, and $\varepsilon_o$ is the permittivity of free space.

Here, the electromagnetic wave with frequency 65.0hz travels in an insulating magnetic material that has dielectric constant 3.64 and relative permeability 5.18 at this frequency.

As the electric field has amplitude 7.20×10−3v/m. Thus, put the values in the above formula to find the intensity as,

$I=((7.20*10^(-3))^2)/(2)\sqrt{(3.64*8.85*10^(-12))/(5.18*(4\pi*10^(-7)))}\nI=5.766*10^(-8)\rm W/m^2$

Hence, the intensity of the electromagnetic wave which travels in an insulating magnetic material in a medium is 5.766×10⁻⁸ W/m².

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Answer 2

Answer: Ans: Intensity = I = $5.8 * 10^(-8) W/m^2$

Explanation:
First you need to find out the speed of Electromagnetic wave:

Since
v = $\sqrt{ (1)/(\mu\epsilon) }$

v = $\sqrt{ (1)/(\mu_r\mu_ok\epsilon_o) }$
$\mu_r = 5.18 \n\mu_o = 4 \pi * 10^(-7) \nk = 3.64 \n\epsilon_o = 8.85 * 10^(-12)$

Plug in the values:
v = $\sqrt{ (1)/((5.18)(4\pi*10^(-7))(3.64)(8.85*10^(-12))) }$
v = $6.9 * 10^7$ m/s

Now that we have "v", we can use the following formula to find the intensity of wave:

$I = (k\epsilon_o*v*E_(max)^2)/(2)$

$I = ((3.64)(8.85*10^(-12))*(6.9*10^7)*(7.20*10^(-3))^2)/(2)$

Intensity = I = $5.8 * 10^(-8) W/m^2$

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(a) Determine the electric field strength between two parallel conducting plates to see if it will exceed the breakdown strength for air (3 ? 106 V/m). The plates are separated by2.98 mm and a potential difference of 5575 V is applied. (b) How close together can the plates be with this applied voltage without exceeding the breakdown strength?

Answers

Answer:

(a) 1.87×10⁶ V/m

(b) 1.12 mm closer

Explanation:

(a)

Electric Field = Electric potential/distance.

E = V/d ................... Equation 1

Where E = Electric Field, V = Electric potential, d = distance.

Given: V = 5575 V, d = 2.98 mm = 0.00298 m.

Substitute into equation 1

E = 5575/0.00298

E = 1.87×10⁶ V/m

(b)

without exceeding the breakdown strength,

make d the subject of equation 1

d = V/E.............. Equation 2

Given: E = 3×10⁶ V/m, V = 5575 V

Substitute into equation 2

d = 5575/3000000

d = 1.86 mm.

the plate will be = 2.98-1.86 = 1.12 mm closer

Is the magnet in a compass a permanent magnet or an electromagnet?

Answers

the needle of a compass is a permanent magnet and the north indicator of the compass is a magnetic north pole. the north pole of a magnet lines up with the magnetic field so a suspended compass needle will rotate it lines up with the magnetic field. Answer permanent magnet

Light has wavelength 600 nm in a vacuum. it passes into glass, which has an index of refraction of 1.5. what is the frequency of the light inside the glass

Answers

Light has wavelength 600 nm in a vacuum ,the frequency of the light is 2 × $10^(-13)$ Hz.

What is wavelength?

The separation between such a wave motion's crests and troughs would be known as the wavelength of photons.

What is frequency ?

The total number of waves that pass a specific location in a predetermined amount of time is known as frequency.

Calculation of frequency

Given data:

wavelength = 600 nm = 600 × $10^(-9)$ m

index of refraction = 1.5.

Frequency can be calculated by using the formula:

v = f × wavelength

f = wavelength / v

Where, f = Frequency , v is velocity.

put the given data in above equation.

f = wavelength / v

f = 600 × $10^(-9)$ m / 3 × $10^(8)$

f = 200 × $10^(-15)$ .

f = 2 × $10^(-13)$

Therefore, the frequency of the light is 2 × $10^(-13)$ Hz.

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v = f lambda

in vac ... 3X10^8 = 600x10^-9xf

in glass speed slower, poss 2/3 that of vacuum

A charge of uniform volume density (40 nC/m3) fills a cube with 8.0-cm edges. What is the total electric flux through the surface of this cube?

Answers

Answer:

The flux through the surface of the cube is $2.314\ Nm^(2)/C$

Solution:

As per the question:

Edge of the cube, a = 8.0 cm = $8.0* 10^(- 2)\ m$

Volume Charge density, $\rho_(v) = 40 nC/m^(3) = 40* {- 9}\ C/m^(3)$

Now,

To calculate the electric flux:

$\phi = (q)/(\epsilon_(o))$ (1)

where

$\phi$ = electric flux

$\epsilon_(o) = 8.85* 10^(- 12)\ F/m$ = permittivity of free space

Volume Charge density for the given case is given by the formula:

$\rho_(v) = (Total\ charge, q)/(Volume of cube, V)$ (2)

Volume of cube, $V = a^(3)$

Thus

$V = (8.0* 10^(- 2))^(3) = 5.12* 10^(- 4)\ m^(3)$

Thus from eqn (2), the total charge is given by:

$q = \rho_(v)V = 40* {- 9}* 5.12* 10^(- 4)$

$q = 2.048* 10^(-11)\ F = 20.48\ pF$

Now, substitute the value of 'q' in eqn (1):

$\phi = (2.048* 10^(-11))/(8.85* 10^(- 12)) = 2.314\ Nm^(2)/C$

1. What is the frequency of light waves with wavelength of 5 x 10-⁷ m?

Answers

Taking into account the definition of wavelength, frecuency and propagation speed, the frequency of light waves with wavelength of 5×10⁻⁷ m is 6×10¹⁴ Hz.

Definition of wavelength

First of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

Definition of frequency

On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

Definition of propagation speed

Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.

The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f× λ

All electromagnetic waves propagate in a vacuum at a constant speed of 3×10⁸ m/s, the speed of light.

Frequency of light waves with wavelength of 5×10⁻⁷ m

In this case, you know:

v= 3×10⁸ m/s
f= ?
λ= 5×10⁻⁷ m

Replacing in the definition of propagation speed:

3×10⁸ m/s = f× 5×10⁻⁷ m

Solving:

3×10⁸ m/s ÷ 5×10⁻⁷ m= f

f= 6×10¹⁴ Hz

In summary, the frequency of light waves with wavelength of 5×10⁻⁷ m is 6×10¹⁴ Hz.

Learn more about wavelength, frecuency and propagation speed:

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Answer:

Speed of light =m/s

wavelength = m

frequency = ?

we have

Speed = frequency × wavelength

$3* 10^8$ = frequency × $5 * 10^(-7)$

Frequency = $(3*10^8)/(5*10^(-7))=6*10^(14)$ hz

Before the development of quantum theory, Ernest Rutherford's experiments with gold atoms led him to propose the so-called Rutherford Model of atomic structure. The basic idea is that the nucleus of the atom is a very dense concentration of positive charge, and that negatively charged electrons orbit the nucleus in much the same manner as planets orbit a star. His experiments appeared to show that the average radius of an electron orbit around the gold nucleus must be about 10−1010−10 m. Stable gold has 79 protons and 118 neutrons in its nucleus. What is the strength of the nucleus' electric field at the orbital radius of the electrons?
What is the kinetic energy of an electron in a circular orbit around the gold nucleus?

Answers

Answer:

a) F = -1.82 10⁻¹⁵ N, b) K = 9.1 10⁻¹⁶ J

Explanation:

a) To calculate the force between the nucleus and the electrons, let's use the Coulomb equation

F = k q Q / r²

as the nucleus occupies a very small volume compared to electrons, we can suppose it as punctual

let's calculate

F = 9 10⁹ (-1.6 10⁻¹⁹) (79 1.6 10⁻¹⁹) / (10⁻¹⁰)²

F = -1.82 10⁻¹⁵ N

b) they ask us for kinetic energy

let's use Newton's second law

F = m a

acceleration is centripetal

a = v² / r

we substitute

F = m v² / r

v = √ (F r / m)

v = √ (1.82 10⁻¹⁵ 10⁻¹⁰ / 9.1 10⁻³¹)

v = √ (0.2 10⁻¹⁶)

v = 0.447 10⁸ m / s

kinetic energy is

K = ½ m v²

K = ½ 9.1 10⁻³¹ (0.447 10⁸)²

K = 0.91 10⁻¹⁵ J

K = 9.1 10⁻¹⁶ J

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