X + x - 5 greater than equal to 33

Answers

Answer 1

Answer: To write this inequality first lets write the word form. The determine the symbol, and write it out:-

x + x - 5 greater than or equal to 33

greater than or equal to sign is ≥.

lets write it out with the sign:-

x + x - 5 greater than or equal to 33.
x + x - 5 ≥ 33

If we were to write this in correct words it would be

A number plus a number minus five, is greater than or equal to thirty-three.

Hope I helped ya!! xD

Answer 2

Answer: $x+x-5 \geq 33\n\n2x -5 \geq 33\n\n2x -5 + 5 \geq 33 + 5\n\n2x \geq 38\n\n(2x)/(2) \geq (38)/(2)\n\n\boxed{\bf{x \geq17}}$

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Answers

The right answer for the question that is being asked and shown above is that:

The value in the x axis will be the Year.
The value in the y axis will be the Year Profit.

The increment on the x axis will as is.
The increment on the y axis can either be $50,000.

Which decimal is equivalent to 5/6

Answers

the answer is 0.8333.....

0.8333 or 83.333% your welcome

H(t) = -5t^2+20t+1 what time does the ball reach the same height it was kicked at again? When does the ball reach its max height? What is the max height?

Answers

h(t) = -5t² + 20t + 1
-5t² + 20t + 1 = 0
t = -(20) +/- √((20)² - 4(-5)(1))
      2(-5)
t = -20 +/- √(400 + 20)
      -10
t = -20 +/- √(420)
-10
t = -20 +/- 2√(105)
-10
t = -20 + 2√(105) t = -20 - 2√(105)
   -10    -10
t = 2 - 0.2√(105) t = 2 + 0.2√(105)
h(t) = -5t² + 20t + 1
h(2 - 0.2√(105)) = -5(2 - 0.2√(105))² + 20(2 - 0.2√(105)) + 1
h(2 - 0.2√(105)) = -5(2 - 0.2√(105))(2 - 0.2√(105)) + 20(2) - 20(0.2√(105)) + 1
h(2 - 0.2√(105)) = -5(4 - 0.4√(105) - 0.4√(105) + 0.04√(11025)) + 40 - 4√(105) + 1
h(2 - 0.2√(105)) = -5(4 - 0.8√(105) + 0.04(105)) + 40 + 1 - 4√(105)
h(2 - 0.2√(105)) = -5(4 - 0.8√(105) + 4.2) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(4 + 4.2 - 0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(8.2 - 0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(8.2) - 5(-0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -41 + 4√(105) + 41 - 4√(105)
h(2 - 0.2√(105)) = -41 + 41 + 4√(105) - 4√(105)
h(2 - 0.2√(105)) = 0 + 0
h(2 - 0.2√(105)) = 0
(t, h(t)) = (2 - 0.2√(105), 0)
or
h(t) = -5t² + 20t + 1
h(2 + 0.2√(105)) = -5(2 + 0.2√(105))² + 20(2 + 0.2√(105)) + 1
h(2 + 0.2√(105)) = -5(2 + 0.2√(105))(2 + 0.2√(105)) + 20(2) + 20(0.2√(105)) + 1
h(2 + 0.2√(105)) = -5(4 + 0.4√(105) + 0.4√(105) + 0.04√(11025)) + 40 + 4√(105) + 1
h(2 + 0.2√(105)) = -5(4 + 0.8√(105) + 0.04(105)) + 40 + 4√(105) + 1
h(2 + 0.2√(105)) = -5(4 + 0.8√(105) + 4.2) + 40 + 1 + 4√(105)
h(2 + 0.2√(105)) = -5(4 + 4.2 + 0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -5(8.2 + 0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -5(8.2) - 5(0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -41 - 4√(105) + 41 + 4√(105)
h(2 + 0.2√(105)) = -41 + 41 - 4√(105) + 4√(105)
h(2 + 0.2√(105)) = 0 + 0
h(2 + 0.2√(105)) = 0
(t, h(t)) = (2 + 0.2√(105), 0)

I DON'T NEED HELP ANY MORE THX FOR ALL THE NON EXISTENT ANSWERS REALLY APPRECIATE IT

Answers

yeah no problem wish I cudve helped u

What is the distance between the points ( 38,30) and (14,20)?

Answers

To find out the distance of two coordinates, we can use this equation.

Distance S = [ (y2-y1)^2 + x2-x1)^2 ] ^ 0.5

x1 , y1 = 38 , 30
x2 , y2 = 14 , 20

Distance S = [ (20-30)^2 + (14-38)^2 ] ^0.5
= [ 10^2 + (-24)^2 ] ^ 0.5
= [ 100 + 576 ] ^ 0.5
= 676 ^ 0.5
= 26

(24,10)

Hope this helps!

Four friends go to the movies and split the total cost between them the total is 17.28 for movie tickets and 13.68 for snacks how much should each of them pay ? A) 7.77
B)7.74
C)10.32
D)30.96

Answers

the answer is: D 30.96.

Hope this helps! (:

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