PHYSICS HIGH SCHOOL

This theory suggests that for every big bang, there is a big crunch.oscillating universe theory
inflation theory
steady state theory
big bang theory

Answers

Answer 1

Answer:

Answer: oscillating universe theory

Explanation:

The oscillating universe theory is a modification of the famous big bang theory.
According to this theory, there are successive cycles of expansion and contraction that occurs in the universe and due to the contraction, the universe gets confined into a very small volume which has a large density.
When the universe gets confined in such a way then, it is said that a 'bounce' will occur and, it would thus oscillate between the big bang and the big crunch.
Thus, this theory states that for every big bang there is a big crunch.

Answer 2

Answer:

Final answer:

The Oscillating Universe Theory suggests that for every big bang there is a big crunch, imagining the universe as undergoing endless cycles of expansion and contraction.

Explanation:

The theory that suggests that for every big bang, there is a big crunch is known as the oscillating universe theory. This theory proposes that the universe undergoes endless cycles of expansion (Big Bang) and contraction (Big Crunch). It's like a ongoing cosmic heartbeat, where our universe alternatively expands and contracts.

The other three theories mentioned, the inflation theory, the steady state theory, and the big bang theory, each have their own illustrations of the universe's formation. None of them, however, necessarily involve the concept of a big crunch following a big bang.

Learn more about Oscillating Universe Theory here:

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You are standing 100 Meters away from your car when an alligator appears 20meters away from you on the opposite side and you start to run with a speed of 5m/s while the alligator's speed was 8m/s towards you. Will you reach your car before the alligator reaches you? Why?
What should you do if you get caught in quicksand
a 5 v battery is connected to a resistor which draws a 2 a current. What is the power used by this circuit
An observer notes that the pitch of a sound is becoming progressively lower. The observer can conclude that the sound is moving

Which is larger? 1 L or 1 m ³

Answers

1 m^3 =1000 L
1 L = 0.001 m^3

So 1m^3 is larger

What is the formula for calculating density?A. density=mass/volume
B. density=mass*volume
C. density=volume/mass
D. density=mass + volume

Answers

Density can be determined by themass of an object and how much it takes up space (volume). It is represented bythe formula D = M/V where D is the density in kg/m^3 or lb/ft^3, M is the massin kg or lb and V is the volume in m^3 or ft^3. The answer would be A. For example, you are given the mass of anobject of 40.5kg and a volume of 15m^3. Find its density.

D = M/V
D = (40.5 kg)/ (15 m^3)
D = 27/10 or2.7 kg/m^3

Answer:

My answer is A.

Explanation:

by using a density triangle, you would have to cover up the density and then it will show you, m over v. so that means you would have to divide.

Two boxes of masses m and 3m are stacked. The surface between the more massive box and the horizontal surface is smooth and the surface between the boxes is rough. If the less massive box does not slide on the more massive box, what is the static friction force on the less massive box?

Answers

Answer:

The friction coefficient is $(F)/(4mg)$ .

Explanation:

Given that,

Mass of first box = m

Mass of second box = 3m

Let the static friction force on the less massive box is $F_(1)$ .

Since the small box is not slide, they have the same acceleration.

We need to calculate the acceleration

Using balance equation

$F-F_(1)=3ma$ ....(I)

$F_(1)=ma$ ....(II)

Adding both the equation

$F=4 ma$

$a=(F)/(4m)$

Put the value of a in equation (II)

$F_(1)=m*(F)/(4m)$

$F_(1)=(F)/(4)$

We need to calculate the friction coefficient

Using formula of frictional force

$F=\mu mg$

$\mu=(F)/(4mg)$

Hence, The friction coefficient is $(F)/(4mg)$ .

If the less massive box does not slide on the more massive box, the static friction force on the less massive box is (D) F/4.
F = ma
F=(3m+m)a
a = F/4m

Here are the following choices:
A) F
B) F/2
C) F/3
D) F/4

Football player A has a mass of 210 pounds and is running at a rate of 5.0 mi/hr. He collides with player B. Player B has a mass of 190 pounds and is running in the same direction at 3.0 mi/hr. Which of the following statements is true?-The momentum of player A is equal to that of player B.
-The momentum of player A is greater than that of player B.
-The momentum of player A is less than that of player B.

Answers

Answer:

the momentum of player A is greater than player B.

Therefore, Option 2 is correct.

Step-by-Step explanation:

We have been given the velocity of the players and mass of the players.

Player A:

Velocity is 5m/hr

Mass 210 pounds

Player B:

Velocity is 3m/hr

Mass 190 pounds

We have a formula for momentum:

$p=mv$

p is momentum

m is mass

v is velocity

We will find momentums for both the players:

Momentum of player A:

on substituting the values we get:

$p=210\cdot 5=1050 pounds$

Momentum of player B:

on substituting the values we get:

$p=190\cdot 3=570 pounds$

Hence, the momentum of player A is greater than player B.

Therefore, Option 2 is correct.

The equation for momentum is p = mv where p is the omentum, m is the mass and v is the velocity. Calculating the momentum for each football player, player A will have a momentum of 1050 lb-mi/h and player B will have a momentum of 570 lb-mi/h. Therefore, momentum of player A is greater than that of player B.

Nuclear power plants produce _______.a. radioactive waste that must be stored properly
b. no waste
c. radioactive waste that can be released into local water supplies
d. air pollution

Answers

Nuclear power plants produce radioactivewaste that must be stored properly. It is very impossible for a nuclear power plantto have no waste at all since lots of chemicals are used to create the processas it gives energy to other machines. Radioactive waste can not be releasedinto local water supplies since the wastes are very radioactive and may causemutation to the fishes and bioaccumulation which will affect humans as well. Itwill also cause air pollution if the chemicals are not stored properly.

Nuclear power plants produce radioactive waste that must be stored properly in other to prevent pollution and health hazards.

What is nuclear power plants?

Nuclear power plant refer to the thermal power station in which power is generated and the the heat source is a nuclear reactor. In any thermal power stations, heat is used to generate steam that spin up steam turbine connected to a generator that produces electricity.

Therefore, Nuclear powerplants produce radioactive waste that must be stored properly.

check more about nuclear power plantsfrom the link below.

brainly.com/question/2005734

What environmental factors affect kinetic energy and diffusion?

Answers

There are several environmental factors that affect the kinetic energy and diffusion. The environmental factors are temperature, molecular size, and pressure, nature of the material and the concentration of the material. All the mentioned factors directly impact the kinetic energy and diffusion of a material or compound or fluid. Temperature can generally increase the kinetic energy of molecules within a compound or a substance. Increase or decrease of temperature changes the shape and nature of the material concerned. So these natural factors have a big influence on the kinetic energy and diffusion.

Answers
Temparature
Humidity (Amount of molecules in the air)

Explanation
Examples of environmental factors are, temperature, wind, pressure, humidity etc. Kinetic energy is the energy possessed by a body in motion.
This motion can be affected by factors such as rain and humidity since the make the medium more dense. It require more energy to move in a denser medium.
Diffusion is the movement of molecules from a region of high concentration to a region of low concentration. When temperatures are high the molecules get more energy and move more faster increasing the rate of diffusion.

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