Three common STIs that sexually active people can contract

Answers

Answer 1
Answer: The TOP three most common STIs that sexually active people can contract is Chlamydia, Gonorrhoea, and Syphilis. 
Answer 2
Answer:

Answer: The three most common STIs: Chlamydia, Gonorrhoea, and Syphilis.


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Which event is most likely to decrease the amount of sunlight that reaches Earth's surface?A) An ice age.
B) An asteroid impact.
C) A catastrophic flood.
D) A prolonged drought.

Answers

B is the correct answer. A would have nothing to do with sunlight, also with c and d. B would cloud rhe skies, like what happened to the dinosaurs.

Answer:

b

Explanation:

The correct answer is an asteroid impact. An asteroid impact can send large amounts of debris into the atmosphere that blocks sunlight.

Can somebody come thru with the answer?

Answers

Do you need an answer to all of the questions?

Answer:

Do you need answer for all of them?

Explanation:

Does this diagram show complete or incomplete metamorphosis?Explain.y

Answers

Answer: Incomplete metamorphosis

Explanation:

Complete metamorphosis includes insects going through 4 stages (egg, larva, pupa, and adult)

Incomplete metamorphosis includes insects going through 3 stages (egg, nymph, and adult)

Which has a physical property? A. Reactivity
B. Burning point
C. Boiling point
D. Chemical stability

Answers

Boiling point. If you boil water it changes from a liquid to a gas, which is a physical change. The rest are chemical properties because the chemical make up of an object changes.

if a man is homozygous dominant for bent fifth finger and a woman is homozygous recessive. What is the probability that any offspring will have a bent fifth finger?

Answers

The probability that any offspring will have a bent fifth finger is 100% . All of their children will inherit one dominant allele from the man (B) and one recessive allele from the woman (b), resulting in the heterozygous genotype (Bb), which exhibits the dominant trait of a bent fifth finger.

Determining the probability of having offsprings with bent fingers

In a scenario where a man is homozygous dominant (BB) for a bent fifth finger trait, and a woman is homozygous recessive (bb) for the same trait, their offspring's probability of having a bent fifth finger can be determined.

Using a Punnett square, it's evident that all their offspring will inherit one dominant allele (B) from the man and one recessive allele (b) from the woman, resulting in a heterozygous genotype (Bb).

As the dominant allele (B) expresses the trait, the probability of any offspring having a bent fifth finger is 100% or 1, as all the children will exhibit this dominant trait.

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The probability of the offspring having a bent finger is 100% we can calculate this using a punnet square like one attached, where B is the dominant bent fifth finger and b is the recessive bent fifth finger, the man's genes are along the top and the woman's genes are along the side.

Describe at least two events during meiosis that increase the genetic diversity of the daughter cells produced.

Answers

1. crossing over allows for genetic recombination
2. the haploid nature means that every daughter cell will most likely be different, even not considering crossing over

Answer;

-Crossing over and random independent assortment.

The two events that increase the genetic diversity of the daughter cells produced are crossing over and random independent assortment.

Explanation;

-During prophase of meiosis I, the double-chromatid homologous pairs of chromosomes cross over with each other and often exchange chromosome segments, which resulting to recombination that creates genetic diversity by allowing genes from each parent to intermix, resulting in chromosomes with a different genetic complement.

-Additionally, when cells divide during meiosis, homologous chromosomes are randomly distributed during anaphase I, separating and segregating independently of each other, this results in gametes having unique combinations of chromosomes.