What are two numbers that multiply to -20 and add up to 1?

Answers

Answer 1
Answer:     xy = -20
x + y = 1

     x + y = 1
x - x + y = -x + 1
           y = -x + 1

                                                xy = -20
                                      x(-x + 1) = -20
                                  x(-x) + x(1) = -20
                                         -x² + x = 20
                                 -x² + x + 20 = 0
                   -1(x²) - 1(-x) - 1(-20) = 0
                              -1(x² - x - 20) = 0
                                        -1            -1
                                    x² - x - 20 = 0
                                    x = -(-1) ± √((-1)² - 4(1)(-20))
                                                          2(1)
                                    x = 1 ± √(1 + 80)
                                                    2
                                    x = 1 ± √(81)
                                                2
                                    x = 1 ± 9
                                             2
                                    x = 0.5 ± 4.5
                                    x = 0.5 + 4.5    or    x = 0.5 - 4.5
                                    x = 5          or         x  = -4
                         
  x + y = 1
  5 + y = 1
- 5        - 5
       y = -4
(x, y) = (5, -4)
         or
   x + y = 1
  -4 + y = 1
+ 4       + 4
         y = 5
   (x, y) = (-4, 5)

The two numbers that add up to 1 and multiply to -20 are -4 and 5.

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PLSSSS HELP IF YOU TRULY KNOW THISS

Answers

Answer: Use PEMDAS. 11^2 (11 times 11) = 121.

2^2 (2 times 2) = 4

121 x 4 = 484

Step-by-step explanation:

Using the Pemdas method, you can solve the equation.

Choose the equation below that represents the line passing through the point (-3,-1) with a slope of 4.A) y = 4x - 11
B) y = 4x + 11
C) y = 4x + 7
D) y = 4x - 7

Answers

Answer:

The answer is the option B

y=4x+11

Step-by-step explanation:

we know that

The equation of the line into slope point form is equal to

y-y1=m(x-x1)

in this problem we have

m=4

point(-3,-1)

substitute

y-(-1)=4(x-(-3))

y+1=4(x+3) ---> equation of the line into slope point form

isolate the variable y

y=4x+12-1

y=4x+11 ---> equation of the line into slope intercept form

Answer: B) y = 4x + 11

If f(x) = x2 + 2x + 3, what is the average rate of change of f(x) over the interval [-4, 6]? A. 51

B. 40

C. 31

D. 20

E. 4

Answers

Calculating the value of f(x) for the given interval.

For x = - 4, f(x) = f(- 4) = (- 4)^2 + 2 (- 4) + 3 = 11

For x = 6, f(x) = f(6) = (6)^2 + 2 (6) + 3 = 51

Now using formula for the calculation of average rate of change of f(x) over the given interval of [- 4, 6];

(f(b) – f(a)) / b – a = (f(6) – f(- 4)) / 6 – (- 4) = (51 -11) / 10 = 4

So option “E” is correct.

What is the math definition for 'counterexample'? When is counterexample used?

Answers

A counterexample is something that proves a statement, or equation, wrong. A counterexample is used in math when someone creates a theorem, writes an equation, or creates a new rule and someone proves it to be false.

For Example:
Let's say that I said an even number plus an odd number always equals an even number. A counterexample of that would be 4 + 5 = 9, because 9 is odd, therefore proving the statement wrong.

On the distant planet Cowabunga, the weights of cows have a normal distribution with a mean of 483 pounds and a standard deviation of 70 pounds. The cow transport truck holds 5 cows and can hold a maximum weight of 2840. If 5 cows are randomly selected from the very large herd to go on the truck, what is the probability their total weight will be over the maximum allowed of 2840

Answers

Answer: 0.0033

Step-by-step explanation:

Let x be a random variable that denotes the weights of cows.

Given: \mu = 483,\ \sigma=70

maximum weight can be hold= 2840 pounds.

Mean weight = (2840)/(5) = 568 pounds

The probability their total weight will be over the maximum allowed of 2840

= P(X>2840)

P((x-\mu)/((\sigma)/(√(n)))>(568-483)/((70)/(√(5))))\n\n=P(z>2.715)\n\n=1-P(z<2.715)\n\n=1-0.9967=0.0033

Hence, the required probability = 0.0033

The cost in dollars to produce x cups of lemonade is represented by the function C(x) = 10 + 0.20x. The revenue in dollars earned by selling x cups of lemonade is represented by the function R(x) = 0.50x. What is the minimum number of whole cups of lemonade that must be sold for the revenue to exceed the cost?

Answers

For the income to exceed the cost, a minimum of 34 complete cups of lemonade must be sold.

What is inequality?

Mathematical expressions with inequalities are those in which the two sides are not equal.

Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), larger than (or greater than or equal to), or not equal to signs are used in place of the equal sign.

The cost in dollars  C(x) = 10 + 0.20x.

The revenue in dollars, R(x) = 0.50x.

For revenue to outpace cost

R(x) > C(x)

0.50x > 10 + 0.20x

0.50x - 0.20x > 10

0.30x > 10

x > 10/0.30

x > 33.333

Hence, For the income to exceed the cost, a minimum of 34 complete cups of lemonade must be sold.

Learn more about inequality here:

brainly.com/question/28823603

#SPJ2

For revenue to exceed cost: R(x) > C(x)
0.50x > 10 + 0.20x
0.50x - 0.20x > 10
0.30x > 10
x > 10/0.30
x > 33.333

Therefore the minimum number of whole cups of lemonade that must be sold for the revenue to exceed the cost is 34.