What is 5(4c-2d)+2d-6(d-3c)

Answers

Answer 1

Answer: Hi

5(4c-2d) + 2d - 6(d-3c) = 20c - 10d + 2d - 6d + 18c

5(4c-2d) = 5(4c)+5(-2d) = 20c-10d
- 6(d-3c) = -6(d)-6(-3c) = -6d+18c

20c - 10d + 2d - 6d + 18c = 20c + 18c - 10d - 6d + 2d = 38c - 14d

20c+18c = 38c
-10d-6d+2d = -16d+2d = -14d

Answer: 38c-14d

Answer 2

Answer: 5(4c−2d)+2d−6(d−3c).Distribute:=(5)(4c)+(5)(−2d)+2d+(−6)(d)+(−6)(−3c)=20c+−10d+2d+−6d+18c.Combine Like Terms:=20c+−10d+2d+−6d+18c=(20c+18c)+(−10d+2d+−6d)=38c+−14d.

Expression

In mathematics, an expression is defined as a set of numbers and mathematical operations that is formed according to rules which is dependent on the context.

Given to us,

equation 1,

$g(t) = (2)/((t + 3))$

equation 2,

$g(\ \ ) = (2)/((4a + 3))$

Let's assume t=4a,

substituting the value of t in equation1, we get

$g(t) = (2)/((t + 3))$

$g(4a) = (2)/((4a + 3))$

As we can see we get equation 2 again, therefore, the value will be 4a.

Learn more about the expression:

brainly.com/question/13947055

Answer:

$g(4a) = (2)/(4a + 3)$

Step-by-step explanation:

Given the function is $g(t) = (2)/(t + 3)$ ........... (1)

Now, we are given that $g() = (2)/(4a + 3)$ .......... (2)

Now, the left hand side of both the above equations (1) and (2) are similar and the only change is that t is replaced by 4a.

Therefore, the equation (2) can be written as

$g(4a) = (2)/(4a + 3)$ (Answer)

Since we know that if $g(t) = (2)/(t + 3)$ then $g(k) = (2)/(k + 3)$ , where k is any real value.

One day after shopping at a department store Lenny discovered that he only had $13 left and his wallet he had entered the store with $81 in his wallet which equations could be used to find how much money Lenny spent (x)

Answers

Subtraction should be easy, 81 - 13 = 68, so he should have spent 68 dollars at the store.

When 40% of the girls left the school assembly, the ratio of the number of boys to girls became 3 to 4. If there were w girls when the assembly started, what was the total number of boys when the assembly started?

Answers

I am pretty sure the answer is 15 boys at the beginning of the assembly.
That would mean that there were 28 girls there, and if 40% of them left, which would mean that 8 left, leaving 20 girls. This would leave the assembly with a 3:4 ratio of boys to girls.

There were 15 boys at the beginning of the assembly and 28 girls

What are the side lengths of a rectangle if the area = 40 in and the perimeter = 48 in

Answers

4, 10, 4, 10. 10*4 gives area of 40. 10+10+4+4 gives 48 as shown in question

$a,b-the\ side\ lengths\ of\ a\ rectangle\n \na\cdot b=40\ [in^2]\ \ \wedge\ \ \ 2\cdot(a+b)=48\ [in]\n \n a+b=24\ \ \ \Rightarrow\ \ \ a=24-b\ \ \ \Rightarrow\ \ \ ab=(24-b)b=24b-b^2\n \nab=40\ \ \ \Rightarrow\ \ \ 24b-b^2=40\ \ \ \Rightarrow\ \ \ -b^2+24b-40=0\ /\cdot(-1)\n \nb^2-24b+40=0\ \ \Rightarrow\ \Delta=(-24)^2-4\cdot40=576-160=416=16\cdot 26\n \n$

$√(\Delta) =4 √(26) \ \ \ \Rightarrow\ \ \ b_1= (24-4 √(26) )/(2)=12-2 √(26)\ \Rightarrow\ a_1=12+2 √(26) \n \n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ b_2= (24+4 √(26) )/(2)=12+2 √(26)\ \Rightarrow\ a_2=12-2 √(26)$

Here are some numbers.5 4 3 9 7
Which of these numbers is:

a factor of 32?
a common factor of 12 and 21?

Answers

A factor is an integer multiplied with another integer to get the product.

Factors of 32 are 1, 2, 4, 8, 16, 32. Among the given choices, 4 is the factor of 32.

Factors of 12 are 1, 2, 3, 4, 6, 12
Factors of 21 are 1, 3, 7, 21
The common factors of 12 and 21 are 1 and 3. Among the given choices, 3 is the common factor of 12 and 21.

4 is a factor of 32
and 3 is a common factor of 12 and 21

What is the first step to solving the division problem below?Divide 8 into 62 to get 7.
Divide 8 into 62 to get 8.
Multiply 8 by 7 to get 56.
Multiply 8 by 8 to get 62.