What value of x makes the equation true? PLZ HELP RIGHT THANK YOU

–7.12 = –4.8 + x



A.


–11.92


B.


–11.2


C.


–2.32


D.


2.32

Answers

Answer 1
Answer: so just remember tha tyou can do anything to an equation as long as you do it to both sides (except divide by 0) so
-7.12=-4.8+x
add 4.8 to both sides since -4.8+4.8=0 so it cancels
4.8-7.12=x
simplify
4.80-7.12=-2.32
-2.32=x
the naswer is C
Answer 2
Answer: -7.12 = -4.8 + x

-7.12 = x - 4.8

Add 4.8 on both sides

x = -7.12 + 4.8

x = -2.32

Your final answer is C. -2.32.

Related Questions

Tom saves $48.50 a month which is the best estimate of how much he will save at the end of the year? A.$300B.$350C.$400D.$600
What three numbers can you multiply to get 24?
PLEASEEEEEEEE HELPPPPPPPPPPPPPPPPPPPPPPPP MEEEEEEEEEEEEEEEEEEEE
Points, in case you need to ask a question.
Calculate the slope of the line going through A(-4,3) and B(0,6) PLEASE ANSWER

Please Help me Check the image below!!!!!

Answers

Answer:

First question:

The graph of  y=(3-2x)/(2-3x) has a vertical asymptote at x =  (2)/(3)and a horizontal asymptote at y =  (2)/(3)

Second question:

The graph of equation y=(1-3x)/(2+x) has a horizontal asymptote at y = -3 ⇒ C

Step-by-step explanation:

The vertical asymptotes will occur at the values of x for which make the  denominator is equal to zero

The horizontal asymptotes will occur if:

  • Both polynomials are the same degree, divide the coefficients of the highest degree terms
  • The polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote

First question:

y=(3-2x)/(2-3x)

- To find the vertical asymptote equate the denominator by 0

   to find the value of x

∵ The denominator is 2 - 3x

∴ 2 - 3x = 0

- Add 3x to both sides

∴ 2 = 3x

- Divide both sides by 3

(2)/(3) = x

The graph has a vertical asymptote at x =  (2)/(3)

To find the horizontal asymptote look at the highest degree of x in both numerator and denominator

∵ The denominator and the numerator has the same degree of x

- Divide the coefficient of x of the numerator and denominator

∵ The coefficient of x in the numerator is -2

∵ The coefficient of x in the denominator is -3

∵ -2 ÷ -3 = (2)/(3)

The graph has a horizontal asymptote at y =  (2)/(3)

The graph of  y=(3-2x)/(2-3x) has a vertical asymptote at x =  (2)/(3) and a horizontal asymptote at y =  (2)/(3)

Second question:

The graph has a horizontal asymptote at y = -3

means the numerator and the denominator has same highest degree and the coefficient of the highest degree in the numerator divided by the coefficient of the highest degree in the denominator equal to -3

  • In all answers the numerator and the denominator have the same highest degree
  • Lets look for the coefficients of x up and down to find which one gives quotient of -3

∵ In answer A the quotient is 1 because x up and down have

  coefficient 1

∵ In answer B the quotient is -(1)/(3) because the coefficient of x

   up is 1 and down is -3

∵ In answer D the quotient is -1 because the coefficient of x

   up is 3 and down is -3

∵ In answer C the quotient is -3 because the coefficient of x up

   is -3 and down is 1

The graph of equation y=(1-3x)/(2+x) has a horizontal asymptote at y = -3

Aaron and Maria collected shells one morning at the beach. Maria had 3 times as many as Aaron, but they would have the same number of shells if Aaron had found 8 more and Maria had found 6 less. How many shells did Aaron collect?

Answers

As per the concept of unitary method, Aaron collected 7 shells.

Let's assume that Aaron initially collected "A" shells, and Maria initially collected "M" shells.

According to the first piece of information, Maria had three times as many shells as Aaron: M = 3A.

Now, according to the second piece of information, if Aaron had found 8 more shells and Maria had found 6 fewer shells, their final shell counts would have been the same. So, Aaron's final count would be A + 8, and Maria's final count would be M - 6.

Given that the final counts are equal, we can set up an equation:

A + 8 = M - 6.

Now, we can substitute the value of M from the first piece of information (M = 3A) into the equation above:

A + 8 = 3A - 6.

Next, let's solve for A:

8 + 6 = 3A - A,

14 = 2A.

Finally, we can find the value of A by dividing both sides of the equation by 2:

A = 14/2,

A = 7.

So, Aaron collected 7 shells.

To know more about unitary method here

brainly.com/question/28276953

#SPJ2

3A = M
A + 8 = M - 6
3A = M

A + 8 = 3A - 6
A + 14 = 3A
14 = 2A
A = 7

M = 3A
M = 3 x 7
M = 21

So overall Aaron had 7 shells, and Maria had 21. 

The entire exterior of a large wooden cube is painted red, and then the cube is sliced into n^3 smaller cubes (where n > 2). Each of the smaller cubes is identical. In terms of n, how many of these smaller cubes have been painted red on at least one of their faces?A. 6n^2
B. 6n^2 – 12n + 8
C. 6n^2 – 16n + 24
D. 4n^2
E. 24n – 24

Answers

Answer:

B. 6n^2-12 n +8

Step-by-step explanation:

Given,

The number of smaller cubes = n^3

So, the number of cubes that have no coloured faces.  = (n-2)^3,

Note : If a cube painted outside having side n is split into n³ cubes, then the volume volume that is not painted = (n-2)³

Thus, the remaining cubes that have been painted red on at least one of their faces

= Total cubes - cubes with no painted face

= n^3 -(n-2)^3

=n^3 - (n^3 - 8 - 6n^2 +12n)

=6n^2-12 n +8

Hence, OPTION B is correct.

A beach has to enclose a rectangular area, because some endangered species are nesting there. They have 200 feet of rope to rope off the area with. What is the maximum area that they can rope off?

Answers

Area is equal to length times width. The perimeter (the amount of rope) has to equal twice the length added to twice the width so we're left with:
A = l * w
200 = 2l + 2w
solve for either l or w
l = 100 - w
plug into the area equation to get one equation with two variables
A = w(100 - w)
A = -w^2 + 100w
take the derivative
A' = -2w + 100
set the derivative equal to zero
0 = -2w + 100
2w = 100
w = 50
This is the width that maximizes the area
with a width of 50, the length must also be 50 to have a perimeter of 200
therefore, they can rope up to 50 * 50 = 2500 ft^2

Final answer:

The maximum area that can be roped off with 200 feet of rope is 2500 square feet by making the roped off area a square.

Explanation:

The question deals with the optimization of area given a fixed perimeter, which involves the principles of geometry and algebra. Since the area needs to be roped off is a rectangle, and you have 200 feet of rope, your rectangle will have dimensions length (L) and width (W) such that 2L + 2W = 200.

To maximize the area of a rectangle given a fixed perimeter, the rectangle should be a square. So, for a maximum area, the length and width should be equal. Thus, each dimension (length and width) would be 200/4 = 50 feet.

Finally, to find the maximum area, we multiply the length by the width: 50 feet * 50 feet = 2500 square feet. So, the maximum area that they can rope off with 200 feet of rope is 2500 square feet.

Learn more about Optimization of Area here:

brainly.com/question/29759875

#SPJ3

Find the LCM of the set of polynomials.

4m^3p, 9mp^4, 18m^4p^2

Answers

The LCM would be m^3p

Answer:

mp3 your welcome

Step-by-step explanation:

smile all day

Solve this equation: x+21=20​

Answers

Hey there!

x+21=20

x=20-21

x=-1

Hope this helps you!

#HaveAnAmazingDay

GraceRosalia

Answer:

x=20-21

x= -1

hope helps... :)