Find the product mentally.
(z - 12)(z + 12)

Answers

Answer 1

Answer: (a-b)(a+b) = a² - b²

(z-12)(z+12) = z² - 12² = z² - 144

Your final answer is z² - 144.

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Flyball is a relay race for dogs. In each of the four legs of the relay, a dog jumps over hurdles, retrieves a ball from a fly box, and runs back over the hurdles. The distance of the relay race is 51 feet. The collie starts the course 0.3 second before the sheepdog. The collie is running 23.4 feet per second while the sheepdog is running 24 feet per second. a. Let t represent the time (in seconds) it takes the collie to un the last leg . Write and solve an equation to find the number of seconds after which the sheepdog would catch up with the collie.
Harrison mows lawns and rakes leaves for his summer and fall weekend jobs. He gets $10 an hour to mow lawns and $8 an hour to rake leaves. If, during September, Harrison mows for m hours and rakes for 12 hours, which expression represents the amount of money he makes
PLS HELP MEYour current test average in Science is an 81. You’ve taken 5 tests. You only have one test remaining. You can raise your average to an 85. t or f
To increase or decrease an amount by 30% what single multiplier would you use?
Evaluate the limit, if it exists. Show work.lim→5 2−3−10 / 2−10

How would you find the real solution, by using the quadratic formula.
x^2-4x+2=0

Answers

$x^2-4x+2=0 \n \na=1 \n b=-4 \n c=2 \n b^2-4ac=(-4)^2-4 * 1 * 2=16-8=8 \n \nx=(-b \pm √(b^2-4ac))/(2a)=(-(-4) \pm √(8))/(2 * 1)=(4 \pm √(4 * 2))/(2)=(4 \pm 2√(2))/(2)=(2(2 \pm √(2)))/(2)=2 \pm √(2) \n\boxed{x=2-√(2) \hbox{ or } x=2+√(2)}$

$x^2-4x+2=0\nx^2-4x+4-2=0\n(x-2)^2=2\nx-2=\sqrt2 \vee x-2=-\sqrt2\nx=2+\sqrt2 \vee x=2-\sqrt2$

The graph shows the ages of different concertgoers who have backstage passes.Which statement is true about the graph?

Answers

In the graph you can see that there are a couple of concertgoers that are way older than the rest.
the statement that is true about the graph would be : the two holders of the passes whose ages are above 40 make the means age higher than the median age

hope this helps

a triangle has area 49.5 cm^2. if the base of the triangle is 9 cm, what is the height of the triangle

Answers

The height of the triangle is 11 cm

What is a Triangle?

A triangle is a plane figure or polygon with three sides and three angles.

A Triangle has three vertices and the sum of the interior angles add up to 180°

Let the Triangle be ΔABC , such that

∠A + ∠B + ∠C = 180°

The area of the triangle = ( 1/2 ) x Length x Base

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

Given data ,

Let the height of the triangle be = h

The area of the triangle A = 49.5 cm²

The base of the triangle b = 9 cm

So , the area of the triangle is given by the equation ,

Area of the triangle = ( 1/2 ) x Length x Base

Substituting the values in the equation , we get

A = ( 1/2 ) x b x h

49.5 = ( 1/2 ) x 9 x h

Multiply by 2 on both sides of the equation , we get

9h = 99

Divide by 9 on both sides of the equation , we get

h = 99/9

h = 11 cm

Therefore , the value of h is 11 cm

Hence , the height of the triangle is 11 cm

To learn more about triangles click :

brainly.com/question/16739377

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Area of a triangle = (height * base ) / 2

height = (Area * 2) / base
height = (49.5 * 2) / 9
height = 99 / 9
height = 10 cm²

Tree pruning company A charges a one time $100 fee and $50 for each tree that they prune. Tree pruning company B charges a one time $80 fee and $60 for each tree that they prune.Let the variable t represent the amount trees pruned and c represent the cost. For how many pruned trees will the cost be the same for both companies?

Which system of equations can be used to solve this problem?

A. {c=150t
c=140t

B. {c=100−50t
c=80−60t

C.{c=100+50t
c=80+60t

D. {c=50+100t
c=60+80t

Answers

The answer to this question should be C

if you put the onetime fee as y intercept and rate as slope you will get the answer.

A: y=50x+100
B: y=60x+80

use desmos and the intersection is when the prices become the same

PLEASE HELP AND SHOW WORK PLS