A company knows that 30% of Customers who come to the store will check out the merchandise and then order it online because it is cheaper. The company wants to know the probability that it will take at least three customers to find one who shops on line. How could the company find out this information?

Answers

Answer 1

Answer: Let X be a discrete random variable with geometric distribution.
Let x be the number of tests and p the probability of success in each trial, then the probability distribution is:
P (X = x) = p * (1-p) ^ (x-1). With x = (1, 2, 3 ... n).
This function measures the probability P of obtaining the first success at the x attempt.
We need to know the probability of obtaining the first success at the third trial.
Where a success is defined as a customer buying online.
The probability of success in each trial is p = 0.3.
So:
P (X = 3) = 0.3 * (1-0.3) ^ (3-1)
P (X = 3) = 0.147
The probability of obtaining the first success at the third trial is 14.7%

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HELPPPPP PLEASEEEEEEEEEE PLS

Answers

Answer:

A) 2 with 9 as an exponent

Step-by-step explanation:

Work out 2.64x10^x4.12x10^-3/1.6x10^-2

Answers

Answer: Answer;-

0.006798x3⋅10−2+x

Step-by-step explanation:

The equation x + 3y=9 and the equation 2x+6y=18 are plotted on the same graph chart. All of the following points will lie on both graphs EXCEPTA. (9,0)
B. (0,3)
C. (6,1)
D. (12, -1)
E. (3,4)

Answers

im sorry all i know is that the lines are parallel and A and B are definitely on the line, i believe the answer is D

The distances (y), in miles, of two cars from their starting points at certain times (x), in hours, are shown by the equations below:Car A
y = 45x + 20
Car B
y = 35x + 60
After how many hours will the two cars be at the same distance from their starting point and what will that distance be?
3 hours, 200 miles
3 hours, 180 miles
4 hours, 200 miles
4 hours, 180 miles

Answers

Given the equations for cars A and B, we are to find the time when their distances would be the same. Since y is the distance, we have to equate both expressions in terms of y to solve for the time (x):

y = 45x + 20
y = 35x + 60

45x + 20 = 35x + 60
45x - 35x = 60 - 20
10x = 40
x = 4 ; after 4 hours, they will be at the same distance from the starting point.

Using the obtained value of x, we solve for the distance using either of the equations:

y = 45(4) + 20
y = 180 + 20
y = 200

y = 35x + 60
y = 35(4) + 60
y = 140 + 60
y = 200

Therefore, the correct answer is 4 hours, 200 miles

Answer:

4 hours, 200 miles

Step-by-step explanation:

Use the following figure to answer the question.When line t is perpendicular to both line l and line m, then lines l and m are parallel.

True
False

Answers

The answer would be true

Answer: True

Hope this helps.

1. Use a compass to draw a large circle.2. Without changing the compass setting, place the point of the compass on the circle and make a mark that intersects the circle.

3. Move the point of the compass to the mark you made and make another mark that intersects the circle.

4. Continue in this way around the circle until you come back to the first mark.

(Hint: The last mark might not coincide precisely with the first mark, but your drawing should look something like the sketch.)

5. Select one of the marks on the circle and use a straightedge to draw line segments connecting that mark to all the marks that are not next to it.

6. Repeat the process for each mark on the circle.

With the design you created in the previous question. Select a pair of adjacent compass marks on the circle. Then follow these instructions and answer the question. 1. Make a crease by folding the paper so that the two marks coincide with each other. When you open the paper, the crease will show you the midpoint along the circle between the two marks. 2. Repeat the process to find the midpoint between each pair of marks on the circle. 3. Use a straightedge to draw line segments connecting each midpoint to the midpoint that is next to it. What type of figure did you create?

Answers

So, the first shape is a pentagon, and the second figure, the one asked for, is a decagon (ten sided polygon), because each 'midpoint line' had two ends, which were factored in and doubled the amount of sides.

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