PHYSICS HIGH SCHOOL

"a certain sprinkler releases water at the rate of 150 liters per hour. if the sprinkler operated for 80 minutes, how many liters of water will be released?"

Answers

Answer 1

Answer:

The amount of water released is mathematically given as

V=200l

What is the amount of water that will be released?

Question Parameters:

a certain sprinkler releases water at the rate of 150 liters per hour.

operated for 80 minutes,

hours in 80min is

h80=80 minutes × (1 hour /60 minutes)

h80= 1.3333 hours.

Generally, the equation for the volume of water is mathematically given as

V=flow rate/time

V=150/1.333

V=200l

Final answer:

When a sprinkler releases water at a rate of 150 liters per hour, it will release 200 liters of water in 80 minutes.

Explanation:

This is a basic math problem involving units of measure and time conversion. The sprinkler releases water at a rate of 150 liters per hour. If it operates for 80 minutes, you will need to first convert the 80 minutes to hours since the rate is provided in liters per hour. 80 minutes is equal to 1.33.. hours (80/60 = 1.33..). Now, to find out how many liters of water will be released, multiply the hours by the rate of release. So, 1.33.. hours * 150 liters per hour = 200 liters. Therefore, the sprinkler will release 200 liters of water in 80 minutes.

Learn more about Time Conversion here:

brainly.com/question/30761848

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Answers

Wow ! This is not simple, Shoot, and I give you a lot of credit
and an extra merit badge if you're generally keeping up with it.

I scratched my head for a few minutes, and I think I've got it.
Here's what I think is going on:

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Now look at the cluttered force diagram.
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How much work does she do ?

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Only 120 J of that energy showed up as increased kinetic energy
of the box. The other 240J of her hard-earned work was consumed
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I think that's it.

What I did was:

-- Find the work that Cat did.

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-- The difference ... the 'missing energy' ... was the work done
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Does this do anything for you ?

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