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Two identical metal spheres a and b are in contact. both are initially neutral. 1.0×1012 electrons are added to sphere a, then the two spheres are separated. you may want to review ( pages 639 - 641) . part a afterward, what is the charge of sphere a?

Answers

Answer 1

Answer:

The charge on the sphere A and sphere B after they are separated is $\boxed{ - 80\,{\text{nC}}}$ each.

Further Explanation:

Given:

The number of electrons transferred to sphere $A$ is $1.0 * {10^(12)}$ .

Concept:

The amount of charge carried by the electrons when reaches the spheres kept in contact with each other is first distributed equally on each sphere. Later as the spheres are moved away from one another, the charge on each sphere remains the same as it was when they were in contact.

The amount of charge on one electron is $- 1.6 * {10^( - 19)}\,{\text{C}}$ .

So, the amount of charge carried by the $1.0 * {10^(12)}$ electrons is given as.

$\begin{aligned}Q&= \left( {1.0 * {{10}^(12)}} \right)\left( { - 1.6 * {{10}^( - 19)}} \right)\n&= - 1.6 * {10^( - 7)}\,{\text{C}}\n\end{aligned}$

Since the charge is disturbed equally on the two sphere, so the amount of charge carried by each sphere s half of the total charge.

$\begin{aligned}{Q_A}&= \frac{{ - 1.6 * {{10}^( - 7)}}}{2}\n&= - 8 * {10^( - 8)}\,{\text{C}}\n &= - 8{\text{0}}\,{\text{nC}}\n\end{aligned}$

Thus, the amount of the charge carried by each sphere after separating from each other is $\boxed{ - 80\,{\text{nC}}}$ .

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Answer Details:

Grade: College

Chapter: Electrostatics

Subject: Physics

Keywords: Metal spheres, two identical, in contact, neutral, charged, electrons, charge on electron, charge on metallic sphere, charge of sphere A.

Answer 2

Answer:

The charge on the sphere A and sphere B after they are separated is $-80\mu C$ each

What is Charge?

Electric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field.

The amount of charge carried by the electrons when reaches the spheres kept in contact with each other is first distributed equally on each sphere. Later as the spheres are moved away from one another, the charge on each sphere remains the same as it was when they were in contact.

The amount of charge on one electron is $-1.6* 10^(-19) \ C$

So, the amount of charge carried by the electrons is given as.

$Q=(1* 10^(12))(-1.6* 10^(-19))$

$Q=-1.6* 10^(-7)\ C$

Since the charge is disturbed equally on the two sphere, so the amount of charge carried by each sphere s half of the total charge.

$Q_A=(-1.6* 10^(-7))/(2)$

$Q_A=-8* 10^(-8)\ C$

$Q_A=-80\ \mu C$

Thus, the amount of the charge carried by each sphere after separating from each other is $-80\mu C$

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A spinning wheel on a fireworks display is initially rotating in a counterclockwise direction. The wheel has an angular acceleration of -4.46 rad/s2. Because of this acceleration, the angular velocity of the wheel changes from its initial value to a final value of -31.4 rad/s. While this change occurs, the angular displacement of the wheel is zero. (Note the similarity to that of a ball being thrown vertically upward, coming to a momentary halt, and then falling downward to its initial position.) Find the time required for the change in the angular velocity to occur.

Answers

Answer:

The time for the change in the angular velocity to occur is 14.08 secs

Explanation:

From the question,

the angular acceleration is - 4.46 rad/s²

Angular acceleration is given by the formula below

$\alpha =(\omega -\omega _(o) )/(t - t_(o) )$

Where $\alpha$ is the angular acceleration

$\omega$ is the final angular velocity

$\omega _(o)$ is the initial angular velocity

$t$ is the final time

$t_(o)$ is the initial time

From the question

$\alpha$ = - 4.46 rad/s²

$\omega _(o)$ = 0 rad/s (starting from rest)

$\omega$ = -31.4 rad/s

$t_(o)$ = 0 s

Now, we will determine t

From $\alpha =(\omega -\omega _(o) )/(t - t_(o) )$ , then

$-4.46 = (-31.4 - 0)/(t - 0)$

$-4.46 = (-31.4)/(t)$

$t = (-31.4)/(-4.46)$

t = 7.04 secs

This is the time spent in one direction,

Since the angular displacement of the wheel is zero ( it returned to its initial position), then the time required for the change in the angular velocity will be twice this time, that is 2t

Hence,

The time is 2×7.04 secs = 14.08 secs

This is the time for the change in the angular velocity to occur.

(a) A woman climbing the Washington Monument metabolizes 6.00×102kJ of food energy. If her efficiency is 18.0%, how much heat transfer occurs to the environment to keep her temperature constant? (b) Discuss the amount of heat transfer found in (a). Is it consistent with the fact that you quickly warm up when exercising?

Answers

Answer:

492 kJ

Consistent

Explanation:

Q = Heat stored by woman from food = 600 k J

η = Efficiency of woman = 18% = 0.18

Q' = heat transferred to the environment

heat transferred to the environment is given as

Q' = (1 - η) Q

Inserting the values

Q' = (1 - 0.18) (600)

Q' = 492 kJ

Yes the amount of heat transfer is consistent. The process of sweating produces the heat and keeps the body warm

Final answer:

A woman climbing the Washington Monument metabolizes food energy with 18% efficiency, meaning 82% of the energy is lost as heat. When we calculate this value, we find that 492 kJ of energy is released as heat, which is consistent with the fact that people quickly warm up when exercising.

Explanation:

The woman climbing the Washington Monument metabolizes 6.00×10² kJ of food energy with an efficiency of 18%. This implies that only 18% of the energy consumed is used for performing work, while the remaining (82%) is lost as heat to the environment.

To calculate the energy lost as heat:

Determine the total energy metabolized, which is 6.00 × 10² kJ.
Multiply this total energy by the percentage of energy lost as heat (100% - efficiency), which gives: (6.00 × 10² kJ) * (100% - 18%) = 492 kJ.

The released heat of 492 kJ is consistent with the fact that a person quickly warms up when exercising, because a significant portion of the body's metabolic energy is lost as heat due to inefficiencies in converting energy from food into work.

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Write down the DE of motion of a particle moving under the influence of gravity and experiencing a resistive force. .

Answers

Answer:

The DE will be $(d^2x)/(dt^2)-(k)/(m)(dx)/(dt)-g=0$

Explanation:

We have to find differential equation under the influence of gravity and experiencing a resistive force

Let an object of mass m falling under the influence of gravity

So the force experience under gravity $=mg$

Le the a resistive force of magnitude kv opposes this gravity force, here k is constant and v is velocity.

So net force $F_(NET)=mg-kv$ -----eqn 1

$F_(NET)=ma$

So $ma=mg-kv$

We know that velocity is rate of change of position so $v=(dx)/(dt)$ , and acceleration is rate of change of velocity so $a=(d^2x)/(dt^2)$

Putting all these value in eqn 1

$m(d^2x)/(dt^2)=mg-k(dx)/(dt)$

$(d^2x)/(dt^2)-(k)/(m)(dx)/(dt)-g=0$

A spectroscope breaks light up into its colors, allowing scientists to analyze light from the solar system and universe. By studying the spectral line patterns, widths, strengths and positions, scientists can determine the speed, position, and _____ of celestial bodies.A) age
B) origin
C) rotation
D) temperature

Answers

It is D - temperature

Final answer:

A spectroscope analyses light to determine various parameters of celestial bodies. The missing parameter in this context is the 'temperature' of the celestial body (option D). The spectral lines, based on their pattern and strengths helps in determining this.

Explanation:

A spectroscope decomposes or breaks white light into its spectrum of colors, allowing scientists to study them and understand various aspects of celestial bodies. When scientists analyze the spectral line patterns, widths, strengths, and positions, they can discern essential parameters. These parameters include the speed and position of the celestial body, and more importantly, the correct answer to your question, its temperature (option D). This is because every element when heated, absorbs or emits light at characteristic wavelengths, that give us the 'spectral lines'. By studying these we can determine the temperature of the celestial body.

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A ball having a mass of 500 grams is dropped from a height of 9.00 meters what is its kinetic energy when it hits the ground

Answers

Answer:

where m = mass, g = acceleration due to gravity (9.8 m/s^2), h = height

Given m = 500g = 0.5 kg, h = 9 meters

0.5*9*9.8 = 44.1 joules

Explanation:

Answer:44.1

Explanation:

A centrifuge is a common laboratory instrument that separates components of differing densities in solution. This is accomplished by spinning a sample around in a circle with a large angular speed. Suppose that after a centrifuge in a medical laboratory is turned off, it continues to rotate with a constant angular deceleration for 10.0s before coming to rest.Part A

If its initial angular speed was 3890rpm , what is the magnitude of its angular deceleration? (|?| in revs/s^2 )

Part B

How many revolutions did the centrifuge complete after being turned off?