Can someone plz help me with the bottom part

Answers

Answer 1

Answer: 9.

2x +3 + x +9 = 180 => 3x + 12 = 180 => 3x = 168 => x = 56 => m(<ABD) = 2*56 +3 = 115.

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Which permanent teeth eruption usually occurs first? A. Central incisors. B. Lateral incisors. C. Cuspids (canines). D. First premolars (Bicuspids).

Answers

Answer: Letter A

Step-by-step explanation: because it is located at the front of the jaw and is the closest to the dental lamina, the source of tooth development in the jawbone

1. Write an algebraic expression for the word phrase ; the quotient of r and 12. A. r .12
B. r*12
C. r - 12
D r + 12

Answers

r ÷ 12 or r/12

Further explanation

Given the word phrase: the quotient of r and 12.

An algebraic expression for it is $\boxed{ \ r / 12 \ or \ r/12 \ or \ (r)/(12) \ }$

Notes:

The quotient is the ratio of two quantities to be divided or the number obtained by division. Synonyms for the quotient are proportion, ratio, or fractions.

An algebraic expression for the quotient of a and b is $\boxed{ \ a / b \ or \ a/b \ or \ (a)/(b) \ }$

'a' is called a dividend
'b' is called a divider
The quotient is the result derived after dividing the dividend by the divisor.

The quotient, a dividend, and a divisor represent the fundamental components of a division equation.

Another example:

A car requires 10 liters of fuel to travel 60 km. Determine the quotient of the distance of the car with fuel (in km/L).

The quotient (or ratio) is

$\boxed{ \ the \ distance / fuel \ consumption \ }$

$\boxed{ \ 60 \ km / 10 \ L \ }$

$\boxed{\boxed{ \ 6 \ km/L \ }}$

Consider the same method as follows.

$\boxed{ \ (the \ distance)/(fuel \ consumption) \ }$

$\boxed{ \ (60 \ km)/(10 \ L) \ }$

$\boxed{\boxed{ \ 6 \ (km)/(L) \ }}$

This means that the car can travel a distance of 6 km for every 1 L of fuel.

Kilometers per liter is a unit used to measure fuel economy and we see this as one example of the use of the quotient (or ratio).

Learn more

10 times as many as (blank) hundreds or 60 hundreds is (blank) thousands brainly.com/question/47704532
9 ten thousands divided by 10 in unit form brainly.com/question/4786449
100 is 1/10 of what? brainly.com/question/96535

Keywords: write an algebraic expression, for the word phrase, the quotient of r and 12, a dividend, a divisor, components of a division equation

in a bag containing 157 MM candies, there are 56 brown, 42 orange, 23 yellow, and 20 red candies. the rest of the m&m's in the bag are green. what percent are green

Answers

The percentage of green bags will be equal to 10.19%.

What is the percentage?

The percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.

Given that in a bag containing 157 MM candies, there are 56 brown, 42 orange, 23 yellow, and 20 red candies. the rest of the m&m's in the bag is green.

The number of green bags,

Number = 157 - 56 - 42 - 23 - 20

Number = 157 - 141

Number = 16

The percentage is,

P = 16 / 157

P = 0.1019

P = 10.19%

To know more about percentages follow

brainly.com/question/24304697

#SPJ2

If there are 157 candies, then that implies that all of the candies in the bag added together end up equaling 157. Thus, if you take the 157 and subtract all of the numbers other than green, that will give you the number of greens in the bag. 157-56-42-23-20=(number of greens). The number of greens is equal to 16. To find the percentage of greens, you take the number of greens in the bag, divide it by the total number of candies, then multiply the ending result by 100: (16/157)*100=0.10191*100=10.191 percent

A factory produces 90 packages of mixed nuts in 1 min. A quality control manager selected 8 of these 90 packages at random and then counted the number of nuts in each package. The manager recorded the results.31, 31, 32, 33, 35, 35, 35, 36

What is the estimated median number of nuts in all 90 packages?

Answers

the answer will be 34. trust me this is the answer

Answer:

Step-by-step explanation:

Did the test c:

Joe has eaten 2/5 of a pizza. Jane has eaten 1/8 of a pizza how many times more pizza has joe eaten than Jane

Answers

Well, the first thing you would do is find like denominators for each fraction.

Since the smallest common term between the two is 40, that will be your denominator for each. Then you would multiply the numerator by the number your denominator was multiplied to get to 40. So, you would end up with 16/40 because 5*8=40 and 2*8=16 and 5/40 because 8*5=40 and 1*5=5.

After that, you would just subtract them.

16/40 - 5/40 = 11/40 and as a decimal that is 0.275. So, Joe has eaten 0.275 more pizza than Jane.

Hope this helps! :)

A ball was kicked into the air from a balcony 20 feet above the ground, and the ball’s height above the ground, in feet, t seconds after the ball was kicked was 2h(t) = 20 − 16t + 32t. What was the maximum height, in feet, of the ball above the ground after it was kicked?

Answers

2h(t) = 20 - 16t + 32t

Not only is there something wrong with the way you've written the equation,
there's no way it could be true even after you fix the little mistake.

First let's divide each side by 2 :

h(t) = 10 - 8t + 16t

This is the equation of the height of a ball that starts from 10-ft above the ground, not 20, begins with 8 ft/sec of downward speed as soon as it's kicked, and what to do with that mysterious ' 16t ' at the end ? Well, if it were ' 16t-squared ', it very well could reflect the acceleration of gravity.

BUT ... since the '10' is positive, we know that the upward direction is the
positive direction for this problem, and then the sign of the acceleration term
can't be positive. That would mean that the ball is accelerating upward at the
rate of 32 ft/sec every second, and if we just wait a few minutes, that ball is on
its way to the moon !

-- If we accept the equation exactly as it's written in the question, then the ball
is kicked from an initial height of 10-ft, it has an upward speed of +8 ft/sec forever,
it never sinks lower than the initial 10-ft, and it has no maximum height.

-- If we make the last term ' 16t² ', then the ball is kicked from an initial height
of 10-ft, the kicker aims down and gives it an initial speed of 8 ft/sec DOWNward,
but it has an upward acceleration of 32 ft/sec every second, The lowest it ever gets
is 1-ft below the balcony, at exactly 0.25 second after the kick, then begins rising,
faster and faster. In this case also, the ball is headed for the moon, and has no
maximum height.

The question needs some serious work.

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