HELP What function models the data shown on the graph?


f(x) = 2(x – 5)(x – 1)

f(x) = –2(x – 5)(x – 1)

f(x) = 2(x + 5)(x + 1)

f(x) = –2(x + 5)(x + 1)
HELP What function models the data shown on the graph? - 1

Answers

Answer 1
Answer: It looks like the parabola are going down, so  the coefficient should be negative,
B or C,
then we see that the parabola has x -intercepts (1,0) and (5,0)
these roots should be written as multiples 
x=1, so x-1=0
and 
x=5, so x-5=0,
so (x-1)(x-5) and negative first coefficient -2 at the same time. 
We can see only in the 
B. f(x) = –2(x – 5)(x – 1)
Answer 2
Answer:

Answer:

b

Step-by-step explanation:


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The following two-way table shows the data for the students of two different grades in a school:Based on the relative row frequency, the students of which grade are more likely to be members of the science club?
Grade 7
Grade 8
The students of both grades are equally likely to be members of the science club
No conclusion can be drawn about the chances of a student being a member of the science club

Answers

The correct answer is Grade 7. In Grade 7, 20/22 students were in the science club, while in Grade 8, 20/28 students were in science club. If we simplify these fractions and get a least common denominator, we can compare them to see which is larger.

Grade 7 = 10/11
Grade 8 = 5/7

Now that we've simplified the fractions, let's find a common denominator for both. In this case, I'm going to use 77.

Grade 7 = 70/77
Grade 8 = 55/77

Since 70 is greater than 55, it is more likely that the Grade 7 students will be in the science club.

Hope this helps!

Answer:

grade 7

Step-by-step explanation:

Can someone please help me with Geometry?

Answers

.
EF bisects m<EDG (given)

#1
so m<DEF = m<FEG = 88/2 = 44

#2.
if m<FED = 27 then m<GED = 27 * 2 = 54 

#3
m<DEF = 3x + 1
m<DEG = 5x + 19

2*( 3x + 1) = 5x + 19
6x + 2 = 5x + 19
6x -5x = 19 - 2
x = 17

#4
m<DEF = 5x - 3
m<FEG =2x + 15

5x -3 = 2x + 15
5x -2x = 15 + 3
3x = 18
x = 18/3
x = 6

#5.
m<FEG = 6x - 7
m<FED = 2x + 41

 6x - 7 =  2x + 41
6x - 2x = 41 + 7
4x = 48
x = 48/4
x = 12

m<DEG =  6x - 7 + 2x + 41 
=6(12) - 7 + 2(12) + 41
= 72 - 7 + 24 + 41
=130

#6
m<ABX = m<XBC
5x = 3x +10
5x - 3x = 10
2x = 10
x = 5

m<ABC = m<ABX + m<XBC
= 5x + 3x +10
= 8x + 10
= 8(5) +10
= 40 +1
= 50

#7
m<ABC = 2 * (m<ABX)
4x -12 = 2(24)
4x- 12 = 48
4x = 48 + 12
4x = 60
x = 60/4
x = 15

#8
m<ABC = 2 (m<CBX)
4x+16 = 2(3x+6)
4x+16=6x +12
6x - 4x = 16 -12
2x = 4
x = 2

#9
m<ABC = 3 (m<CBX)
5x+18 = 2(2x+12)
5x+18=4x+24
5x-4x=24-18
x =6

m<ABC = 5x+18 = 5(6) +18 = 30 + 18 = 48
hope you can read this. 

An adult’s dinner costs $7. A family of 3 adults and 2 children pays $31 for their dinners.1. How much does a child’s dinner cost?


2. If you were given $48 what combinations of adults and children could you bring to dinner? Provide at least two different examples and show your work.

Answers

Answer:

1. 10 dollars for each child

2. a. You could have 2 children and 4 adults.

2. b. I can't figure out another solution.

Sorry. :(((

Hope this helped, tho. :))

Compare using <, >, or =.
7 2/5_____ 7 3/8

Answers

7 2/5 as an improper fraction is 37/5 and 7 3/8 as an improper fraction is 59/8. Then we convert those two improper fractions into a decimal (by 100) and get  7 2/5 = 7.4 and 7 3/8 = 7.3, 7.4 is bigger than 7.3 so the answer is...

7 2/5 > 7 3/8

-28=7(x-7) What does x=

Answers

Answer:

-28=7(x-7)

First expand the terms on the right side

That is

-28 = 7x - 49

Group like terms

7x = -28 + 49

7x = 21

Divide both sides by 7

7x/7 = 21 /7

x = 3

Hope this helps

Answer:

so x=3

Step-by-step explanation:

-28=7(x-7)

opening the brackets by multiplying

-28=7x-49

adding 49 on both sides

-28+49=7x-49+49

21=7x

dividing 7 on both sides

21/7=7x/7

x=3

i hope this will help you :)

[71 – (8 2+ 5)] (2 + 3)+ 7 × [2 × (7 3+ 17)] – 72 [40 + (4 2– 6)] (5 – 3)+ 3 × (1 + 4 3– 15) – 150

Answers

Answer:

Step-by-step explanation:

2(3)+8. =6 + 8. = 35 x 102. = 3.5 x 10-1. 3.5 x 10". = 14 ... Substitute b with – 3 and solve. 3). A. 783. 5(-3)2-2(-3)+1. =5(9)+6+1. =45+7. =52 ... (4 – 5x) – (3 – 2x). (4 – 5x)+(-3+ 2x). _+(4 – 5x). +(-3+2x). 1- 3x.  to solve. ... (3r' -5+2x). “ - [(7x² +5)– (4x' – 5x)]. – L(7x² +5)– (4x' – 5x). =-|(7x² + 5) – 4x² + 5x].