A(n) is a chemical substance used to treat, prevent, or diagnose a disease or alter one or more functions of the body.

Answers

Answer 1
Answer:

A(n) DRUG is a chemical substance used to treat, prevent, or diagnose a disease or alter one or more functions of the body.

Example: Tylenol (Acetaminophen), Is a Drug that is used to relieve pain, head aches, and reduce fever.

Hope It Helped. :)

Answer 2
Answer:

Answer:

A(n) is a chemical substance used to treat, prevent, or diagnose a disease or alter one or more functions of the body.

Explanation:


Related Questions

I need help please Which option is chemical change?
Is the answer 1 or 2? And why.
Which radioisotope is used for diagnosing thyroid disorders?(1) U-238 (3) I-131 (2) Pb-206 (4) Co-60
The element in Period 4 and Group 1 of the Periodic Table would be classified as aA. metal B. metalloid C. nonmetal D. noble gas
1. In general, the nucleus of a small atom is stable. Therefore, over very short distances, such as those in a small nucleus, a. the strong nuclear force is much greater than the electric force. b. the electric force is much greater than the strong nuclear force. c. the strong nuclear force equals the electric force. d. the strong nuclear force and the electric force are both attractive. 9. Uranium-238 undergoes alpha decay. Therefore, uranium-238 will a. remain stable. b. change into a different element altogether. c. emit neutral particles and no energy. d. none of the above

Will water come to the same temperature of the hot pan?

Answers

Answer:

Water becomes hot when the chemical potential of the water is equal to the chemical potential of the water at the same temperature as the pan.

What is the empirical formula for a compound if a sample contains 3.72g of P and 21.28g of Cl?

Answers

The empirical formula or simplest formula gives the smallest whole-number ratio of the atoms present in a compound.It gives the relative number of atoms of each element present in the compound.The ratio will be              3.72 : 21.28

Why is H2SO4 regarded as an ampholyte

Answers

I think sulfuric acid cannot be regarded as an ampholyte. Ampholytes are amphoteric molecules or that contains both acidic and basic groups. An amphoteric compound can react both as an acid and a base which sulfuric acid is not capable.

An important application of exponential functions is working with half-life of radioactive isotopes in chemistry. These isotopes emit particles and decay into stable forms, in doing so they lose mass over time. Half-life of an isotope is the time it takes for the amount to decay by half. For example, the half life of Bromine-85 is 3 minutes. This means if you start with 60g of Br-85, 3 minutes later 30g will remain. How much Br-85 will remain after 20 minutes?

Answers

Answer : The amount left after 20 minutes is, 0.592 grams.

Explanation :

Half-life of Bromine-85 = 3 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{3\text{ min}}

k=0.231\text{ min}^(-1)

Now we have to calculate the amount left after decay.

Expression for rate law for first order kinetics is given by:

t=(2.303)/(k)\log(a)/(a-x)

where,

k = rate constant

t = time taken by sample = 20 min

a = initial amount of the reactant  = 60 g

a - x = amount left after decay process  = ?

Now put all the given values in above equation, we get

20=(2.303)/(0.231)\log(60)/(a-x)

a-x=0.592g

Therefore, the amount left after 20 minutes is, 0.592 grams.

Which of the following observations led physicist James Chadwick to perform experiments that eventually led to the discovery of the neutron?A. Protons alone were not able to account for the density of an atoms nucleus.

B. Atomic nuclei possess shells similar to the electron shells of atoms.

C. Some atoms contained more protons than electrons.

Answers

The correct answer is letter C. James Chadwick confirmed the existence of neutrons.In his experiment, he was able to show that the particles that were ejected had no electrical charge but had almost the same mass as the proton. These particles were, of course, neutrons.

In the following reaction, how many grams of NaBr will react with 311 grams of Pb(NO3)2?pb(no3)2(aq)+2NaBr(g) -> PbBr2(s) + 2NaNO3(aq)
The molar mass of NaBr is 102.9 grams and that of Pb(NO3)2 is 331.21 grams.

Answers

Answer: 193.4 grams

Explanation: According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023* 10^(23) of particles.

Pb(NO_3)_2(aq)+2NaBr(g)\rightarrow PbBr_2(s)+2NaNO_3(aq)

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

{\text{Number of moles} of Pb(NO_3)_2}=(311g)/(331.21gmol)=0.94moles

According to stoichiometry

1 mole of Pb(NO_3)_2 reacts with 2 moles of NaBr

0.94 moles of Pb(NO_3)_2 will react with=(2)/(1)* 0.94=1.88moles of NaBr

Mass of NaBr=moles* {\text {molar mass}}=1.88* 102.9=193.4g

Answer:

193.24g

Explanation:

Step 1:

The balanced equation for the reaction. This is illustrated below:

Pb(NO3)2(aq) + 2NaBr(g) -> PbBr2(s) + 2NaNO3(aq)

Step 2:

Determination of the masses of Pb(NO3)2 and NaBr that reacted from the balanced equation. This is illustrated below:

Molar Mass of Pb(NO3)2 = 331.21g/mol

Molar Mass of NaBr = 102.9g/mol

Mass of NaBr from the balanced equation = 2 x 102.9 = 205.8g.

From the balanced equation,

Mass of Pb(NO3)2 that reacted = 331.21g

Mass of NaBr that reacted = 205.8g

Step 3:

Determination of the mass of NaBr that reacted with 311g of Pb(NO3)2. This is illustrated below:

From the balanced equation above,

331.21g of Pb(NO3)2 reacted with 205.8g of NaBr.

Therefore, 311g of Pb(NO3)2 will react with = (311x205.8)/331.21 = 193.24g of NaBr.

From the calculations made above, 193.24g of NaBr will react with 311g of Pb(NO3)2