A color change happens during an experiment mixing two liquids. Is this a physical change or chemical change?

Answers

Answer 1

Answer: The color change would only effect the appearance of the substance, so it would be a physical change.

Answer: physical change

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An analysis of an oxide of nitrogen with a molecular weight of 92.02 amu gave 69.57% oxygen and 30.43% nitrogen. What are the empirical and molecular formulas for this nitrogen oxide? Complete and balance the equation for its formation from the elements nitrogen and oxygen.

How would you be able to use the spectrum of each gas to establish its identity

Answers

You could compar and contrast the identities so you can compare them and identify them

What are the electrons is the outer shell of an atom called?What charge will elements in Group 2 form when they are involved in an ionic bond?

Answers

The answer to your first question is valence electrons. The answer to your second is positive.

How many moles of h2o are produced when 3.25 moles of o2 react in 2c2h6 + 7o2 ---> 4co2 + 6h2o

Answers

Answer:

2.78 moles of water are produced.

Explanation:

Given data:

Number of moles of H₂O produced = ?

Number of moles of oxygen react = 3.25 mol

Solution:

Chemical equation:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Now we will compare the moles of water with oxygen.

O₂ : H₂O

7 : 6

3.25 : 6/7×3.25 = 2.78 mol

Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron falls from the n = 7 to the n = 4 principal energy level. Recall that the energy levels of the H atom are given by En = –2.18 × 10–18 J(1/n2)

Answers

Answer:

The wavelength of the light emitted by electron fall will be 216.62 nm.

Explanation:

The change in the energy state of the matter can be obtained from the principal quantum number of the shells.

Energy of 4th shell - Energy of 7th shell = $\rm \Delta$ E

$\Delta$ E = $\rm 2.18\;*\;10^-^1^8\;J\;\left ( (1)/(n_f^2) \;-\;(1)/(n_i^2) \right )$

$\rm \Delta\;E\;=\;-2.18\;*\;10^-^1^8\;\left ((1)/(4^2) \;-\;(1)/(7^2) \right )$

$\rm \Delta\;E\;=\;-2.18\;*\;10^-^1^8\;*\;0.0421$

$\rm \Delta\;E\;=\;0.0917\;*\;10^-^1^8$ J

The wavelength can be calculated as:

$\rm \Delta\;E\;=\;(hc)/(\lambda)$

where, h is Plank's constant,

c is speed of light

$\lambda$ is the wavelength

$\rm 0.0917\;*\;10^-^1^8\;J\;=\;(6.626\;*\;10^-^3^4\;J.s\;*\;2.998\;*\;10^8\;m/s)/(\lambda)$

$\rm\lambda\;=\;216.62nm$ .

For more information, refer the link:

brainly.com/question/23023103?referrer=searchResults

Answer:

The wavelength of the light emitted by a hydrogen atom for the given transition is 2166 nm.

Explanation:

The energy of nth energy levels of the H atom is given as:

$E_n = -2.18 * 10^(-18) * (1)/(n^2) J$

Energy of the seventh energy level = $E_7$

$E_7=-2.18 * 10^(-18) * (1)/(7^2) J$

$E_7=-2.18 * 10^(-18) * (1)/(7^2) J=-4.4490* 10^(-20) J$

Energy of the seventh energy level = $E_4$

$E_4=-2.18 * 10^(-18) * (1)/(4^2) J$

$E_4=-2.18 * 10^(-18) * (1)/(16) J=-1.3625* 10^(-19) J$

Energy of the light emitted will be equal to the energy difference of the both levels.

$E=E_7-E_4=-4.4490* 10^(-20) J-(-1.3625* 10^(-19) J)$

$E=9.176* 10^(-20) J$

Wavelength corresponding to energy E can be calculated by using Planck's equation:

$E=(hc)/(\lambda )$

$\lambda =(hc)/(E)=(6.626* 10^(-34) Js* 3* 10^8 m/s)/(9.176* 10^(-20) J)=2.166* 10^(-6) m=2166 nm$

The wavelength of the light emitted by a hydrogen atom for the given transition is 2166 nm.

How many elements are in a set whole numbers between 3 and 15

Answers

The set of elements composed of whole numbers between 3 and 15 consists of 4, 5, 6,7,8,9, 10, 11,12,13,14. Counting these, the number of elements is 11.

The supercontinent that existed about 200 million years ago was named

Answers

This was Pangaea! (was named like this in 1912)

It started existing around 300 million years ago and started falling apart around 175 million years ago.

Answer:

Pangaea

Explanation:

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