??What's the balance ??

Answers

Answer 1

Answer: I think the answer is A because the balance after 4 years is not on their and so we are trying to find the balance after three years. And after 3 years the balance is 805

Answer 2

Answer: I believe it's A.
Hope this helps.

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1.(02.01)
Solve -4(x + 1) – 3 = -3(x – 4). (1 point)
O
-19
19
2.

Answers

Answer:

x = -19

Step-by-step explanation:

hope this help :)

Answer:

$\boxed {x = -19}$

Step-by-step explanation:

Solve for the value of $x$ :

$-4(x + 1) - 3 = -3(x - 4)$

-Use Distributive Property to both sides of the equation:

$-4(x + 1) - 3 = -3(x - 4)$

$-4x - 4 - 3 = -3x + 12$

-Combine like terms:

$-4x - 4 - 3 = -3x + 12$

$-4x - 7 = -3x + 12$

-Take $-3x$ and add it to $-4x$ :

$-4x - 7 + 3x = -3x + 3x + 12$

$-x - 7 = 12$

-Add both sides by $7$ :

$-x - 7 + 7 = 12 + 7$

$-x = 19$

-To make the variable $x$ positive, divide both sides by $-1$ :

$(-x)/(-1) = (19)/(-1)$

$\boxed {x = -19}$

Therefore, the value of $x$ is $-19$ .

Need help... will mark brainliestWhat is the average daily temperature for all ten years? ____degrees

Answers

Answer:

53.6°

Step-by-step explanation:

Pretty much just add all the (y)s together then divide by 10.

50+52+51+54+53+57+54+54+55+56=536

536/10 =53.6

the average temperature is 53.6°

8x-9y=11 Solve for y.

Answers

8x-9y=11
-9y=-8x+11
9y=8x-11
y=8/9x-11/9
sorry, thats as simplified as it can get with 2 variables in the equation

Answer:

y = 8/9x + -11/9

Step By Step:

Let's solve for y. 8x−9y=11

Step 1:

Add -8x to both sides.

8x−9y+−8x=11+−8x

−9y=−8x+11

Step 2:

Divide both sides by -9.

-9y/-9 = -8+11/-9

y = 8/9x + -11/9

A car rents for $45.00 per day plus 21 cents per mile. You are on a daily budget of $66.00 per day. What mileage will allow you to stay within your budget?

Answers

45+.21m is less than or equal to 66
-45 from both sides

.21m is less than or equal to 21
/.21 from both sides

m is less than or equal to 1000

you can go no more than 1,000 miles.

In this triangle, the product of sin B and tan C is _____ , and the product of sin C and tan B is _______.

Answers

In this triangle, the product of sin B and tan C is c/a or cos B, and the product of sin C and tan B is b/a cos C. We determine these as follows:

sin B tan C = b/a (c/b) = c/a

sin C tan B = c/a (b/c) = b/a

Hope this answers the question. Have a nice day.

Answer

part 1 = c/a

part 2 = b/a

Sine is the ratio of opposite to hypotenuse respect to as agiven angle while tangent is the ratio of opposite to adjacent lengths of agiven angle.

Part 1

Sine = opposite/hypotenuse

SinB = b/a

Tangent = opposite/adjacent

TanC = c/b

SinB × TanC = b/a×c/b

= c/a

Part 2

SinC = c/a

TanB = b/c

SinC×TanB= c/a×b/c

=b/a

Write a story problem using mixed numbers that need to be scaled up. The problem should
have at least five mixed numbers that will be scaled up. Be sure to show all your work, explain your
steps in your solution (including changing improper fractions to mixed numbers), and write a complete
answer to your problem. Your answer should include units for the mixed numbers, if needed.

Answers

[Insert generic name here] is trying to bake a yellow cake because [reasons]. This recipe will make one whole cake.

$3(1)/(4)\ cups\ of\ flour\n 2(1)/(2)\ teaspoons\ of\ baking\ soda\n (1)/(2)\ teaspoon\ of\ salt \n 1(3)/(4)\ cups\ of\ sugar \n (2)/(3)\ cup\ of\ butter \n 2\ eggs\n 1(1)/(2)\ teaspoons\ of\ vanilla\ \n 1(1)/(4)\ cups\ of\ milk$

He wants to make three cakes instead of one. How much of each item should be used in the new (scaled-up) recipe?

$3(1)/(4)*3=9(3)/(4)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ cups\ of\ flour\n 2(1)/(2)*2=4(2)/(2)=4+1=5\ \ \ \ \ teaspoons\ of\ baking\ soda\n (1)/(2)*3=(3)/(2)=1(1)/(2)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ teaspoons\ of\ salt \n 1(3)/(4)*3=3(9)/(4)=3+2(1)/(4)=5(1)/(4)\ cups\ of\ sugar$

$(2)/(3)*3=(6)/(3)=2\ \ \ \ \ \ cups\ of\ butter\n 2*3=6 \ \ \ \ \ \ \ \ \ \ \ \ eggs\n 1(1)/(2)*3 = 3(3)/(2) = 4\frac{1}2\ teaspoons\ of\ vanilla\ \n 1(1)/(4)*3=3(3)/(4)\ \ \ \ \ \ \ \ cups\ of\ milk$

I don't know exactly how your teacher wants you to write out the work, but I have it pretty simple there. It's not like math is tailored to a specific process; any sort of reasonable work should do.

Good luck!

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