How much heat is required to vaporize 50.0 g of water if the initial temperature of the water is 25.0◦c and the water is heated to its boiling point where it is converted to steam? the specific heat capacity of water is 4.18 j · ( ◦c)−1 · g −1 and the standard enthalpy of vaporization of water at its boiling point is 40.7 kj · mol−1?

Answers

Answer 1

Answer: Q = mCΔT
Q is heat, m is mass, C is specific heat, and ΔT is change in temp

First, find how much energy you need to raise the heat to 100C, or the boiling point
Q = (50g)(4.18)(75 degrees) = 15675 J or 15.675 kJ

Then you need 40.7 kJ extra for each mole of water to evaporate it
If you have 50 grams of water and there are 18 grams per mol
50g / 18g = 2.8 moles x 40.7 = 113 kJ extra

15.675 + 113 kJ = 128.7 kJ required

Answer 2

Answer:

Final answer:

The total heat required to heat 50 g of water from 25 °C to boiling and then vaporize it is approximately 128.821 kJ.

Explanation:

To calculate the total heat required to boil the water, we need to consider two steps: heating the water from its initial temperature to the boiling point, and then converting the water at its boiling point to steam.

Firstly, we calculate the heat needed to heat the water to the boiling point, using equation q = mcΔT: q1 = m * c * ΔT = 50.0 g * 4.18 J/(g • °C) * (100°C - 25°C) = 15675 J = 15.675 kJ
Next, amount of heat needed to vaporize the water at its boiling point can be found using the standard enthalpy of vaporization, ΔHvap = 40.7kJ/mol. But this value is per mole, so we need to convert grams of water to moles using the molar mass of water (18 g/mol). So, the number of moles of water is 50 g / 18 g/mol = 2.78 mol. The heat for vaporization, q2 = n * ΔHvap = 2.78 mol * 40.7 kJ/mol = 113.146 kJ.

Therefore, the total heat required to heat and vaporize the water is q = q1 + q2 = 15.675 kJ + 113.146 kJ = 128.821 kJ.

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Answers

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In this reaction, we have; KOH + HCl -----> KCl + H2O. The concentration of KOH was expressed to two significant figures.

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The precaution taken when KOH is dropped on the arm of a student is to apply plenty water over the affected area.

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