In a Venn diagram, the separate circles contain characteristics unique to each item being compared and the intersection contains characteristics that are common to both items being compared. Ernie is working on the Venn diagram below to compare the career pathways of Biotechnology Research and Development and Diagnostic Services.What else could Ernie put in the common section?

Collecting data and analyzing results
Designing and implementing systems
Maintaining and using diagnostic equipment
Designing and using laboratory equipment
Mark this and return

Answer:

v = 4,244,699 m/s = (4.245 × 10⁶) m/s

Explanation:

The electric force on the proton is given by

F = qE

where q = charge on the proton = (1.602 × 10⁻¹⁹) C

E = Electric field = 720,000 N/C

F = (1.602 × 10⁻¹⁹ × 720000)

F = (1.153 × 10⁻¹³) N

But this force will accelerate the proton in this magnetic field in a form of trajectory motion.

We can obtain the acceleration using Newton's first law of motion relation

F = ma

m = mass of a proton = (1.673 × 10⁻²⁷) kg

a = (F/m)

a = (1.153 × 10⁻¹³)/(1.673 × 10⁻²⁷)

a = 68,944,411,237,298 m/s²

a = (6.894 × 10¹³) m/s²

This acceleration directs the proton from the positive plate to the negative plate, covering a distance of y = 0.006 m (the distance between the plates)

Using Equations of motion, we can obtain the time taken for the proton to move from the rest at the positive plate to the negative one.

u = initial velocity of the proton = 0 m/s

y = vertical distance covered by the proton = 0.006 m

a = acceleration of the proton in this direction = (6.894 × 10¹³) m/s²

t = time taken for the proton to complete this distance = ?

y = ut + (1/2) at²

0.006 = 0 + [(1/2)×(6.894 × 10¹³)×t²]

0.006 = (3.447 × 10¹³) t²

t² = (0.006)/(3.447 × 10¹³)

t² = 1.741 × 10⁻¹⁶

t = (1.32 × 10⁻⁸) s

Then we can then calculate the minimum speed to navigate the entire length of the plates without hitting the plates.

v = ?

x = 0.056 n

t = (1.32 × 10⁻⁸)

v = (x/t)

v = (0.056)/(1.32 × 10⁻⁸)

v = 4,244,699 m/s = (4.245 × 10⁶) m/s

Hope this Helps!!!

Answer:

v = 9.09×10⁵m/s

Explanation:

Given

d = the distance between plates = 0.6cm = 0.006

E = Electric field strength = 720000N/C

m =mass of the proton = 1.67 ×10-²⁷ kg

The

Electric potential energy of the field is converted into the the kinetic energy of the proton.

So

qV = 1/2mv²

But V = Ed

So q(Ed) = 1/2mv²

v² = 2qEd/m

v = √(2qEd/m)

v = √(2×1.6×10-¹⁹×720000×0.006/1.67×10-²⁷)

v = 9.09×10⁵m/s

Answer:

Length

Time

Mass

Temperature

Energy

Direct Current (DC)

Frequency

Volume

Speed

Amount of substance

Luminous Intensity

Density

Concentration

Refractive Index

Work

Pressure

Power

Charge

Electric Potential

Entropy

Answer: Length axis f= 114.3 Hz, Width axis f=228.67 Hz

Explanation:

We are given that,

Length of tub= 1.5 m

Width of tub= 0.75 m

Sound speed= 343 m/s

Now, we are also given shower is closed.

So, frequency is given as:

f=

For length axis

Put v= 343 m/s, m=1 and L=1.5 m

f= 1 *

f= 114.3 Hz

For next resonant frequency, m=2

f= 2*

f= 228.67

For width axis

Put v= 343 m/s, m=1 and L= 0.75 m

f= 1*

f= 228.67 Hz

For next frequency, m=2

f= 2*

f= 457.34 Hz

Answer:

Force,

Explanation:

It is given that,

Length of the room, l = 4 m

breadth of the room, b = 5 m

Height of the room, h = 3 m

Atmospheric pressure,

We know that the force acting per unit area is called pressure exerted. Its formula is given by :

So, the total force on the floor due to the air above the surface is . Hence, this is the required solution.

Given :

A 5-kg moving at 6 m/s collided with a 1-kg ball at rest.

The ball bounce off each other and the second ball moves in the same direction as the first ball at 10 m/sec.

To Find :

The velocity of the first ball after the collision.

Solution :

We know, by conservation of momentum :

Putting all given values with directions ( one side +ve and other side -ve ).

Therefore, the velocity of first ball after the collision is 4 m/s after in opposite direction.

Hence, this is the required solution.

Answer:

Acceleration,

Explanation:

Given that,

Initial speed of a car, u = 45 km/h = 12.5 m/s

Final speed, v = 0 (as they comes to rest)

Distance, d = 18 m

We need to find the acceleration of the breaking car. Using third equation of motion as follows :

So, the acceleration of the braking car is .