Find the probability of rolling two dice and getting two odd numbersA.50%
B.5.5%
C.25%
D.2.7%

Answers

Answer 1
Answer: One die has 6 numbers, 3 of which which are odd. That means each roll has a 50% chance of being odd.

To find the probability of rolling TWO odd numbers, we can multiply the 0.5 chance per roll by 2 to get:

0.5 * 0.5 = 0.25 or 25%

If you visualize the question, we have 4 possibilities:

Roll 1 is even and roll 2 is even.

Roll 1 is even and roll 2 is odd.

Roll 1 is odd and roll 2 is even.

Roll 1 is odd and roll 2 is odd.

Only 1 of the 4 possibilities results in both rolls being odd.


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1 1 pointAnswer each of the following. Write your final answers in the blanks provided.A building is 50 ft. high. At a distance away from the building, an architect observes that the angle of elevation to the top of the building is28° How far is the observer from the base of the building? Round to the nearest foot.
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Draw a sketch to help you solve this problem. Lucy had 3.2/3 kilograms of apples. She used some of the apples for a dessert. She has 1.1/3 kilogram of apples left.

How much of the apples did Lucy use for her dessert?

Answers

Lucy used 2 1/3 kilograms of apples for her dessert.

Get the whole fraction. 

3 2/3 = ((3*3) + 2) / 3 = 11/3
1 1/3 = ((3*1) + 1) / 3 = 4/3

Original weight of apples = 11/3
Remaining weight of apples = 4/3
weight of apples used = ?

Subtracting fractions:
Step 1. Make sure the denominator are the same

11/3 - 4/3

Step 2. Subtract the numerators and put the difference above the denominator

(11 - 4) / 3 = 7/3

Step 3. Simplify the fraction

7/3 = 2 1/3

The perimeter of a rectangle is 48 in. If the length is twice the width, what is the length of the rectangle?

Answers

Step one: We need to find the formula for perimeter. And we can't just say "count all the sides". How can we express it? It's length + length + width + width, right? Let's size that down a little bit. 2*length 2*width. We'll use w to express "width" and 2w to express "length".
2(w)+2(2w)=48.
6w=48.
w=8.
Since length is twice the width, 8*2 is 16. Length=16.

You can check it by substituting the different values for length and width into the equation 2w+2l=perimeter.
2(8)+2(16)=48. Is this true? Yep! So you know you're right.

What are the coordinates of the center of the circle if this is its equation:x2 + y2 - 16x + 6y +53 = 0

Answers

Hello,

x²-16x+y²+6y+53=0
==>x²-2*8*x+8² + y²+2*3*y+3²+53-64-9=0
==>(x-8)²+(y+3)²=20
Center is (8,-3) and radius =√20

Peter says, "If you subtract 14 from my number and multiply the difference by - 6, the result is - 90." What is Peter's number? Peter's number is​

Answers

Translating the phrases into algebraic equation, peter's number would be: 29.

Representing Word Problems with Algebraic Expressions

Let the unknown value be variable x, then translate the phrases given into algebraic expressions and solve for the unknown variable.

Let Peters number be x

  • Therefore:

-6(x - 14) = -90

Solve for x

-6x + 84 = -90

-6x = -90 - 84

-6x = -174

  • Divide both sides by -6

x = 29

Therefore, translating the phrases into algebraic equation, peter's number would be: 29.

Learn more about algebraic equation on:

brainly.com/question/2164351

Answer:

29

Step-by-step explanation:

i think this is helpful

1. Refer to the triangle below. If a = 3 and b = 6, A. Find the exact length of c in unsimplified radical form B. Find the exact length of c in simplified radical form C. Find c to the nearest hundredth

Answers

I'm assuming that the triangle is a right triangle wherein the Pythagorean theorem is applicable.

a² + b² = c²

c = √a²+b²
c = √3² + 6² 
c = √9 + 36
c = √45   unsimplified radical form
c = √9 * 5 
c = 3 √5  simplified radical form
c = 3 * 2.24
c = 6.71 value of c to the nearest hundredth

Please help me with this math question?? :)The measure of each exterior angle of a regular octogon is _____ the measure of each exterior agle of a regular hexagon.

A. Greater than
B. Less than
C. Equal to

Answers

\bf \textit{exterior angle of a regular polygon}\n\n\n\theta=\cfrac{360}{n}\qquad \begin{cases}\theta=\textit{the angle in degrees}\nn=\textit{number of sides}\end{cases}

now, an OCTAgon, has OCTA=8, sides
an HEXAgon, has HEXA=6, sides

check what their external angles are, and compare :)