The coordinates of A, B,and C in the diagram are A(p,4), B(6,1), C(9,q). What equation correctly relates p and q?

Answers

Answer 1
Answer: I don't see any diagram. So, I'll just wing it.

Value of q:
p, 6, 9 ⇒ there is a difference of 3. The sequence increases by 3. So, it can be assumed that the p is equal to 3. A(p,4) ⇒ A(3,4)

Value of q:
4, 1, q ⇒ there is a difference of 3. The sequence decreases by 3. So, it can be assumed that q is equal to -2. C(9,-2)
 
        p        q
A     3        4     ⇒ 3 + 4 = 7
B     6        1     ⇒ 6 + 1 = 7
C     9       -2    ⇒ 9 + (-2) = 7

Notice that the sequence has an equation of p + q = 7.


Answer 2
Answer:

Answer:

C

Step-by-step explanation:

p+q=7


Related Questions

Seven divided by twice a number
How do you solve the problem 2x+3y=25,4x-y=15 for substitution
Which system of equations can be graphed to find the solution(s) to 4x2 = x2 – 7?
Translate the sentence into an inequality.Nine subtracted from the product of 5 and a number is at least -28
Suzy buys 2 shirts and 2 pairs of pants for 42 dollars at the store. Annette buys 3 shirts and 1 pair of pants for 37 dollars.Create a system of equations that can be used to solve for the cost of the shirts and pants.a2s + 2p = 373s + p = 42b2s + 2p = 37s + 3p = 42c2s + 2p = 423s + p = 37d2s + 2p = 42s + 3p = 37

Which equation is true?9x2 – 25 = (3x – 5)(3x – 5)
9x2 – 25 = (3x – 5)(3x + 5)
9x2 – 25 = –(3x + 5)(3x + 5)
9x2 – 25 = –(3x + 5)(3x – 5)

Answers

Answer : 9x^2 - 25 = (3x - 5)(3x + 5)

(1) 9x^2 - 25 = (3x - 5)(3x - 5)

Use FOIL method to mulitply (3x – 5)(3x – 5)

(3x - 5)(3x - 5) = 9x^2 - 30x + 25

(2) 9x^2 - 25 = (3x - 5)(3x + 5)

Use FOIL method to mulitply (3x - 5)(3x + 5)

(3x - 5)(3x - 5) = 9x^2 - 15x + 15x - 25 = 9x^2 - 25

(3) 9x^2 - 25 = -(3x + 5)(3x + 5)

Use FOIL method to mulitply -(3x + 5)(3x + 5)

-(3x + 5)(3x + 5) = -(9x^2 + 30x + 25) = -9x^2 -30x -25

(4) 9x^2 - 25 = -(3x + 5)(3x - 5)

Use FOIL method to mulitply -(3x + 5)(3x - 5)

-(3x + 5)(3x - 5) = -(9x^2 - 25) = -9x^2 + 25

So equation 2 is true

Hello,

Answer B


But this is not an equation!!!!! (only an expression)

You have $59.95 in your wallet and want to buy some new CDs. If the CDs are $11.99 each, what number of CDs, x, can you buy? Write and solve an inequality.

Answers

x - number of CDs;
An inequality is:
x · $11.99 ≤ $59.95
x ≤ $59.95 : $11.99
x ≤ 5
Answer:
5 CDs

Answer:

number of CDs can you buy is 5 or less than 5

Step-by-step explanation:

Here, x represents the number of CDs buy.

As per the statement:

If the CDs are $11.99 each

⇒Cost of x CDs  = 11.99x

It is also given that:

You have $59.95 in your wallet and want to buy some new CDs

11.99x \leq 59.95

We get an inequality:

11.99x \leq 59.95

Solve for x:

Divide both sides by 11.99 we have;

x \leq (59.95)/(11.99) = 5

x \leq 5

Therefore, number of CDs can you buy is : x \leq 5

2(3x+4y)=4x+12y
 solve

Answers

6x + 8y = 4x + 12y
6x - 4x = 12y - 8y
2x =  4y
x = 2y
is it x=2y?
Because  6x+8y=4x+12y
=>2x+8y=12y
and 2x=4y, so x=2y                         

What It Trigonometry ?

Answers

Trigonometry is a type of math dealing with the relations of the sides & angles of triangles & with the relevant functions of any angles.
Its a combination of geometry and algebra.

Nell's mortgage is $50,150 at 10 percent for 30 years. What is her monthly payment if she must pay $8.78 points per $1,000?a) $440.32
b) $439
c) $442.95
d) $385.89

Answers

Answer:

The correct option is a.

Step-by-step explanation:

It is given that Nell's mortgage is $50,150 at 10 percent for 30 years and she must pay $8.78 points per $1,000.

EMI on $1000 is $8.78, so EMI on $1 is

\text{EMI on }\$1=(8.78)/(1000)=0.00878

EMI on $50150 is

\text{EMI on }\$50150=0.00878* 50150=440.317\approx 440.32

Therefore the correct option is a.

The right answer for the question that is being asked and shown above is that:  "d) $385.89." Nell's mortgage is $50,150 at 10 percent for 30 years. Her monthly payment if she must pay $8.78 points per $1,000 is that of d) $385.89

Find the other endpoint of a line segment with the given midpoint and one endpoint.midpoint (11/2,17/2) and the endpoint is (2,9)

Answers

A(x_A;\ y_A);\ B(x_B;\ y_B)\n\nmidpoint\ AB:\left((x_A+x_B)/(2);\ (y_A+y_B)/(2)\right)


A(2;\ 9);\ B(x;\ y)\n\nmidpoint\ AB:\left((11)/(2);\ (17)/(2)\right)\n\n(2+x)/(2)=(11)/(2)\ and\ (9+y)/(2)=(17)/(2)\ \ \ \ \ |multiply\ both\ sides\ by\ 2\n\n2+x=11\ and\ 9+y=17\n\nx=11-2\ and\ y=17-9\n\nx=9\ and\ y=8\n\nAnswer:endpoint\ (9;\ 8).