The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
No , the y-values of a data set cannot have both a common difference and a common ratio at the same time.
An arithmetic progression is a sequence of numbers in which each term is derived from the preceding term by adding or subtracting a fixed number called the common difference "d"
Thus nth term of an AP series is Tn = a + (n - 1) d
d = common difference = Tₙ - Tₙ₋₁
Sum of first n terms of an AP: Sₙ = ( n/2 ) [ 2a + ( n- 1 ) d ]
A geometric progression is a sequence in which each term is derived by multiplying or dividing the preceding term by a fixed number called the common ratio.
The nth term of a GP is aₙ = arⁿ⁻¹
Given data ,
A common difference means that the difference between any two consecutive y-values in the data set is the same. For example, if the first y-value is 3 and the common difference is 2, then the second y-value would be 5 (3 + 2), the third y-value would be 7 (5 + 2), and so on. This creates a linear relationship between the y-values.
And , a common ratio means that the ratio between any two consecutive y-values in the data set is the same. For example, if the first y-value is 3 and the common ratio is 2, then the second y-value would be 6 (3 x 2), the third y-value would be 12 (6 x 2), and so on. This creates an exponential relationship between the y-values.
Hence , a linear relationship and an exponential relationship are different, it is not possible for the y-values of a data set to have both a common difference and a common ratio at the same time.
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the ratio 7:22 represents the ratio of students who prefer doing their homework before school to all students that do their homework
A. 29% B. 31% C. 45% D. 69%
Answer:
a = 5
Step-by-step explanation:
Joe walked a distance of 1.5 miles across the park to get to school.
And the difference in their 2 round trips is 1.2 miles.
Pythagoras' Theorem states that the square of the hypotenuse side of a right-angled triangle is equal to the sum of the squares of the other two sides.
We can use the Pythagorean theorem to find the distance that Joe walked today.
Let's call this distance d.
Since Joe walked a straight path across the park, the distance he covered can be represented by the hypotenuse of a right triangle, with Main Street and Washington Avenue as the legs.
Now,
d² = 1.2² + 0.9²
d² = 1.44 + 0.81
d² = 2.25
d = 1.5
Therefore, Joe walked a distance of 1.5 miles across the park to get to school.
To find the difference in distance between the two round trips, we can subtract the distance that Joe usually walks from the distance he walked today, and double the result, since he has to walk back home.
Hence,
2 × (-1.5 + 1.2 + 0.9) = 1.2 miles
Therefore, the required distance is 1.2 miles.
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