An experiment consists of drawing 1 card from a standard 52 card deck? What is the probability of drawing a queen?

Answers

Answer 1

Answer: 4/52, or 1/13, or 8 percent(not very accurate or precise). You take the number of queens in a deck(4) and put it over the total number of cards in a deck(52). This gives you a probability of 1 in 13 or about 8 percent

Answer 2

Answer: 4 out of 52 which is equal to 1/13

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A rectangle with an area of 12 square units, what are the demensions?

Answers

Answer:

area= base(length)*height(width)

possible dimensions

4 *3, 3*4

6*2, 2*6

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Scores on a recent national statistics exam were normally distributed with a mean of 82.2 and a standard deviation of 5.If the top 2.5% of test scores receive merit awards, what is the lowest score eligible for an award

Answers

Answer:

The lowest score eligible for an award is 92.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu = 82.2, \sigma = 5$

If the top 2.5% of test scores receive merit awards, what is the lowest score eligible for an award

The lowest score is the 100 - 2.5 = 97.5th percentile, which is X when Z has a pvalue of 0.975. So X when Z = 1.96. Then

$Z = (X - \mu)/(\sigma)$

$1.96 = (X - 82.2)/(5)$

$X - 82.2 = 5*1.96$

$X = 92$

The lowest score eligible for an award is 92.

Xpress 8.54545454545... as a rational number, in the form pq where p and q are positive integers with no common factors.

Answers

To express the repeating decimal 8.54545454545... as a rational number, we can use the concept of infinite geometric series. The rational number equivalent is 282/33.

To express the repeating decimal 8.54545454545… as a rational number, we can use the concept of infinite geometric series. Let x = 8.54545454545…, then multiplying x by 100 gives 100x = 854.54545454545…. Next, subtracting the original x equation from the 100x equation eliminates the repeating decimals, giving 99x = 846. Dividing both sides by 99 results in x = 846/99. Simplifying the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 3, gives the final answer: x = 282/33.

Learn more about Rational Numbers here:

brainly.com/question/24398433

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If you mean p/q, then this is how you do it:

$x = (846)/(99) = (94)/(11)$

Therefore your final answer is 94/11, where p is 94 and q is 11.

In a recent Super Bowl, a TV network predicted that 31 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 120 people who saw the commercials and found that 40 of them said they would watch one of the television shows. Suppose you have the following null and alternative hypotheses for a test you are running:1. H0: p = 0.53 Ha: p ≠ 0.53
2. H0: p = 0.53 Ha: p ≠ 0.53
Calculate the test statistic, rounded to 3 decimal places.

Answers

Answer:

-4.317

Step-by-step explanation:

The z test statistic for testing of 1-proportion can be computed as

$z=\frac{phat-p}{\sqrt{(pq)/(n) } }$

We know that

phat=x/n.

We know that x=40 and n=120.

Thus,

phat=40/120=0.3333

p=hypothesized proportion=0.53

q=1-p=1-0.53=0.47

So, required z-statistic is

$z=\frac{0.3333-0.53}{\sqrt{(0.53(0.47))/(120) } }$

$z=(-0.1967)/( 0.04556 )$

z=-4.317.

Thus, the required test statistic value for given hypothesis is z=-4.317.

Help please if you get it right then you get brainliest

Answers

Answer:

C. Australia and Antarctica were a single landmass in the past.

Step-by-step explanation:

The most likely explanation for why the fossils of this plant are found on these two continents is that Australia and Antarctica were a single landmass in the past.

This evidence is vastly supported by the theory of plate tectonics originally, the theory of continental drift.

Plate tectonics proposes that all land masses were once joined together as a single supercontinent called Pangaea.

The region of Antartica and Australia were once joined as a single continental mass.

The plant must have developed together at that time.

When the continents moved apart, they still had the fossils.

What is the value of the expression |5x+12| when x=5