An atom of element X has one more shell of electrons than an atom of beryllium, but it has one less valence electron than beryllium. Which element is element X?

Answers

Answer 1

Answer: Element X is sodium. Sodium has one less valence electron than beryllium and it has the electron configuration of 2,8,1, thus it has one more shell of electrons.

Answer 2

Answer:

Answer:

sodium

Explanation:

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Dalton hypothesized that atoms are indivisible and that all atoms of an element are identical. It is now known that _____. A. all of Dalton's hypotheses are correct
B. atoms of an element can have different numbers of protons
C. atoms are divisible
D. all atoms of an element are not identical but they must all have the same mass

Answers

Dalton hypothesized that atoms are indivisible and that all atoms of an element are identical. It is now known that atoms are divisible. The answer is letter C

Which of the following steps is important to critical thinking?

Answers

Answer:

utilizing facts

Explanation:

Critical thinking helps you come up with solutions to problems.

2. A sample of iron has the dimensions of 2.0 cm x 3.0 cm x2.0 cm. It has a mass of 94.0 grams. What is the density of
iron? (8 points)

Answers

Answer:

first change cm to m and g to kg so you will find the volume first which is 0.02 by 0.03 by 0.02 your answer is 0.000012 m . using the formula density=mass/volume take 0.094/ 0.00012 then divide

Consider the following balanced chemical equation. 4 KO 2 + 2 H 2 O ⟶ 4 KOH + 3 O 2 How is the rate of appearance of O 2 , Δ [ O 2 ] Δ t , related to the rate of disappearance of KO 2 ?

Answers

The appearance of Oxygen molecule is directly related or dependent to the rate of disappearance of potassium superoxide (KO2).

The rate of appearance of O2 is directly related to the rate of disappearance of KO2 because potassium superoxide (KO2) has oxygen molecule which is attached to the potassium so when the potassium reacts with water molecules, the potassium hydroxide (KOH ) and oxygen molecules is formed.

If the chemical reaction occurs then we get oxygen molecules so we can conclude that appearance of Oxygen molecule is directly related or dependent to the rate of disappearance of potassium superoxide (KO2).

Learn more: brainly.com/question/14917767

Answer : The rate of appearance of $O_2$ related to the rate of disappearance of $KO_2$ is,

$(d[O_2])/(dt)=-(3)/(4)(d[KO_2])/(dt)$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-(1)/(a)(d[A])/(dt)$

$\text{Rate of disappearance of B}=-(1)/(b)(d[B])/(dt)$

$\text{Rate of formation of C}=+(1)/(c)(d[C])/(dt)$

$\text{Rate of formation of D}=+(1)/(d)(d[D])/(dt)$

$Rate=-(1)/(a)(d[A])/(dt)=-(1)/(b)(d[B])/(dt)=+(1)/(c)(d[C])/(dt)=+(1)/(d)(d[D])/(dt)$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$4KO_2+2H_2O\rightarrow 4KOH+3O_2$

The expression for rate of reaction :

$\text{Rate of disappearance of }KO_2=-(1)/(4)(d[KO_2])/(dt)$

$\text{Rate of disappearance of }H_2O=-(1)/(2)(d[H_2O])/(dt)$

$\text{Rate of formation of }KOH=+(1)/(4)(d[KOH])/(dt)$

$\text{Rate of formation of }O_2=+(1)/(3)(d[O_2])/(dt)$

The overall rate expression is:

$\text{Rate of reaction}=-(1)/(4)(d[KO_2])/(dt)=-(1)/(2)(d[H_2O])/(dt)=+(1)/(4)(d[KOH])/(dt)=+(1)/(3)(d[O_2])/(dt)$

Now we have to determine the rate of appearance of $O_2$ related to the rate of disappearance of $KO_2$ .

$-(1)/(4)(d[KO_2])/(dt)=+(1)/(3)(d[O_2])/(dt)$

or,

$+(1)/(3)(d[O_2])/(dt)=-(1)/(4)(d[KO_2])/(dt)$

$(d[O_2])/(dt)=-(3)/(4)(d[KO_2])/(dt)$

Thus, the rate of appearance of $O_2$ related to the rate of disappearance of $KO_2$ is,

$(d[O_2])/(dt)=-(3)/(4)(d[KO_2])/(dt)$

Which of the following is a balanced chemical equation for the synthesis of NaBr from Na and Br2? A. 2Na + Br2 --> 2NaBr B. NaBr --> Na + Br2 C. 2NaBr --> 2Na + Br 2 D. 2Na + Br2 → NaBr

Answers

Answer:

A) 2Na + $Br_(2)$ = 2NaBr

Explanation:

As the problem says that you should find the balanced chemical equation for the synthesis of NaBr from Na and $Br_(2)$ , the reactants are Na and $Br_(2)$ and the product is NaBr, so it can be writen as:

Na + $Br_(2)$ = NaBr

Then you shoud balance the equation, it means that you should have the same number of each element in each part of the equation, so if you put a number 2 for the NaBr and the Na, the equation will be balanced:

2Na + $Br_(2)$ = 2NaBr

A. 2Na + Br2-->2NaBr.

HELPPP| WILL MARK BRAINLEST Rosalinda is thirsty and wants to make a glass of lemonade as quickly as possible. She needs to add sugar to lemon juice and water to make the lemonade. Which type of sugar should she use?
Group of answer choices

granulated sugar with fine grains

sugar formed into cubes

raw sugar with coarse grains

sugar from rock candy

Answers

Answer:

she use granulated sugar with fine grains as it is easily dissolved so she used in lemonade.

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