What is the maximum number of covalent bonds a carbon atom can form with other atoms?A. 1
B. 2
C. 4
D. 6

Answers

Answer 1
Answer: (C.) Each carbon atom in ethane forms 4
Answer 2
Answer: There is no such thing called a 'hexa-bond', as there is a quad-bond and a triple bond and so on...

A carbon atom cannot form a 6 covalent bond with another atom, the max is 4. 

Answer: 4

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Which element has an atom in the ground state with a total of three valence electrons

Answers

1) Aluminum
2) Lithium
3) Phosphorus

Calculate the atmospheric pressure if the boiling point of water is 81 degrees Celsius.

Answers

Answer : The atmospheric pressure of water if boiling at 81 °C will be 369 mmHg.


Explanation : The vapor pressure of boiling water can be calculated using the Antoine Equation:


log P = A - [(B)/( C + T) ],


where P is the pressure in mmHg,

A = 8.07131,

B = 1730.63

C = 233.426

and T = temperature in °C (81°C)


Substituting the given values, we get,

Log P = 8.07131− [(1730.63)/(233.426 + 81)]

Therefore, Log P =8.07131 − 5.5041 = 2.567.


Now, P = (10^(2.567) ) =369 mmHg.


Hence, the atmospheric pressure will be 369 mmHg.

To calculate the atmospheric pressure at a specific boiling point of water, we use the steam table or the Antoine equation. From steam table via interpolation, at 81 C, the pressure where saturation occurs is the atmospheric pressure. The atmospheric pressure is 369.7 mm Hg or 0.4864 atm.

The muscles in your body make up about percent of your body weight.

Answers

The muscles in our body make up for 38% - 54% in males and 28% - 39% in females.

Answer:

The answer is 40-50 percent I did it and it was correct.

Explanation:

I would not mind Brainliest pls.

Which type of pollution includes CFCs and smog?

Answers

Air pollution exist in two forms namely ozone and particle pollution. CFCs and smog are under the ozone form of pollution. Ozone type of pollution is mostly formed by reaction between the sunlight and the vapors that are emitted due to human activities. 

The is Answer is air

If 7.84 x 10^7 J of energy is released from a fusion reaction, what amount of mass in kilograms would be lost? Recall that c = 3 x 10^8 m/s.7.06 x 10^24

8.71 x 10^-4

8.71 x 10^-7

8.71 x 10^-10

Answers

Use the formula
E=mc^2

plug the values,

The amount of mass in kilograms would be lost is 8.71 x 10^-10

Answer : The mass lost would be, 8.71* 10^(-10)Kg

Solution : Given,

Energy released = 7.84* 10^(7)J=7.84* 10^(7)\text{ Kg }m^2/s^2

(1J=1\text{ Kg }m^2/s^2)

Speed of light 'c' = 3* 10^(8)m/s

Formula used :

E=m* c^2

where,

E = energy

m = mass

c = speed of light

Now put all the given values in the above formula, we get

7.84* 10^(7)\text{ Kg }m^2/s^2=m* (3* 10^(8)m/s)^2

m=8.71* 10^(-10)Kg

Therefore, the mass lost would be, 8.71* 10^(-10)Kg

In kinetics, the order of a reactionA)depends on the rate constant
B)can be deduced from the balanced equation for the reaction
C)must be measured experimentally
D)depends on the concentrations of reactants
E)is the inverse of the entropy of the system

Answers

I think it should be C.  You can't always look at the chemical equation of a reaction and tell what order the over all reaction will be.  To do this, you need to preform experiments that have some concentrations held constant while changing others to see how the concentrations affected the rate.  After enough trials with enough concentrations held constant and changed, you will be able to determine the order of each reactant which will give you the order of the overall reaction.

I hope this helps.  Let me know in the comments if anything is unclear.