The Alden Middle School girls' soccer team won 80% of its games this season.If the team won 12 games,how many games did it play? Solve the problem using at least two different methods.

Answers

Answer 1
Answer: 0.8g=12

g=12/0.8

Where 0.8 is 80% in fraction form (80/100), g is the number of games played and 12 is the games won.

0.8g=12
-----   ---
0.8    0.8
g=15

g=12/0.8
g=15

They played a total of 15 games.

Check:
0.8(15)
=12


Answer 2
Answer:

Final answer:

If the Alden Middle School girls' soccer team won 80% of games, i.e., 12 games, they played 15 games in total. This was determined using proportional relationship and direct calculations.

Explanation:

The subject of the student's question falls under Mathematics. Essentially, the student is asked to find the total number of soccer games Alden Middle School's girls team played given that they won 80% of these games, translating to 12 wins.

Method 1: Proportional Relationship If 12 games represent 80% wins, we can establish a proportional relationship: 12 (wins) / 80 (%) = x (total games) / 100 (%). Cross multiply to solve for x: 12*100=80*x and thus x = 15 games.

Method 2: Direct Calculation Knowing that 80% of games were won, divide the number of wins by this percentage to get the total games: 12 / 0.8 = 15 games. So the team played 15 games in total.

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Answers

yes thats your answer!!!:)
 

Leslie has two cups containing different colored paper clips. The first cup contains 7 pink paper clips and 3 blue paper clips. What is the probability that Leslie will randomly select a blue paper clip from the first cup and then randomly select an orange paper clip from the second cup

Answers

9 out of 20, 9:20 First cup 3:10 Send cup 6:10 Together 9:20 and can't be reduced

$900 deposited at an interest rate of 3% for 5 years

Answers

.03 times 900 is 27

27 times 5 is $135
I=PRT
P for Price/Principle amount
R for Rate
T for Time in years
I=$900×0.03×5       (3%=(3)/(100)=0.03)
 =$135
Interest=$135
If they want you to find how much is left by the end of the 5th year, you do this:
Original+Interest
$900+$135
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PLEASE HELP ME!!! 30 POINTS!!!As a part of the life cycle of plants, the plant must begin with an embryo. What statement best describes where the embryo can be found in flowering and non-flowering plants?

A. In a flowering plant, the embryo is in seeds found in the flower, and in non-flowering plants, the embryo is in seeds found in the cone.

B. In a non-flowering plant, the embryo is in spores found in the stem, and in a flowering plant, the embryo is in seeds found in the flower.

C. In a non-flowering plant, the embryo is in seeds in the leaves, and in a flowering plant, the embryo is in seeds found in the spores.

D. In a flowering plant, the embryo is in spores found in the flower, and in a non-flowering plant, the embryo is in seeds found in the spores.

Answers

Answer:

I have not read it but

Step-by-step explanation:

i think the A is right answer.

Find the distance cd rounded to the nearest tenth. c=(8,-3) and D=(-9,-6)

Answers

The distance CD rounded to the nearest tenth is approximately 17.3 units.

Here, we have to find the distance CD between points C(8, -3) and D(-9, -6), we can use the distance formula:

Distance CD = √[(x₂ - x₁)² + (y₂ - y₁)²]

where (x₁, y₁) are the coordinates of point C and (x₂, y₂) are the coordinates of point D.

Substitute the values:

Distance CD = √[(-9 - 8)² + (-6 - (-3))²]

Distance CD = √[(-17)² + (-3)²]

Distance CD = √[289 + 9]

Distance CD = √298

Now, round the result to the nearest tenth:

Distance CD ≈ 17.262

So, the distance CD rounded to the nearest tenth is approximately 17.3 units.

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  • Distance Formula: √((x_2-x_1)^2+(y_2-y_1)^2)

Plug the coordinates into the distance formula and solve as such:

CD=√((8-(-9))^2+(-3-(-6))^2)\nCD=√(17^2+3^2)\nCD=√(289+9)\nCD=√(298)\nCD\approx 17.3

Your answer is 17.3 units.

At the movies, tickets for a night show cost $9, and tickets for a day show cost $6.75. What percent is the discount you get for going to a day show?

Answers

I think it is 3.25%. That is what I had got when I had did my math