Nuclear fusion ____.a. takes place in the sun
c. can be controlled in the laboratory
b. occurs at low temperatures
d. is used in medicine

Answers

Answer 1

Answer:

Nuclear fusion takes place inthe sun, letter A. The sun is a ball of hot gases. Initially, it containshydrogen and helium. When they fuse together, it forms carbon. After carbon,nitrogen, oxygen silicon follows until it forms a massive hot ball of gases. Thenet result is the fusion of four protons into one alpha particle with therelease of two positrons, two neutrons and energy.

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two identical freight cars roll without friction towards each other on a level track. one car rolls 2 m/s the other 1 m/s. after the cars collide they couple and roll together with a speed of

A long coaxial cable consists of an inner cylindrical conductor with radius a and an outer coaxial cylinder with inner radius b and outer radius c. The outer cylinder is mounted on insulating supports and has no net charge. The inner cylinder has a uniform positive charge per unit length λCalculate the electric field
(a) At any point between the cylinders a distance r from the axis and
(b) At any point outside the outer cylinder.
(c) Graph the magnitude of the electric field as a function of the distance r from the axis of the cable, from r = 0 to r = 2c.
(d) Find the charge per unit length on the inner surface and on the outer surface of the outer cylinder.

Answers

Answer:

Part a)

$E = (\lambda)/(2\pi \epsilon_0 r)$

Part b)

$E = (\lambda)/(2\pi \epsilon_0 r)$

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

Explanation:

Part a)

By Guass law we know that

$\int E. dA = (q)/(\epsilon_0)$

$E. 2\pi rL = (\lambda L)/(\epsilon_0)$

$E = (\lambda)/(2\pi \epsilon_0 r)$

Part b)

Outside the outer cylinder we will again use Guass law

$\int E. dA = (q)/(\epsilon_0)$

$E. 2\pi rL = (\lambda L)/(\epsilon_0)$

$E = (\lambda)/(2\pi \epsilon_0 r)$

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

Final answer:

The electric field between the cylinders is given by E = λ / (2πε₀r). The electric field outside the outer cylinder is zero due to the absence of net charge. Graph the electric field magnitude using the equation E = λ / (2πε₀r). The inner surface charge of the outer cylinder is -λ and the outer surface charge is 0.

Explanation:

To calculate the electric field between the cylinders at a distance r from the axis, you can use Gauss's Law. Since the charging is uniform, the electric field will also be uniform. Therefore, the electric field at any point between the cylinders is given by E = λ / (2πε₀r), where ε₀ is the permittivity of free space.

To calculate the electric field at any point outside the outer cylinder, you can use the principle of superposition. The electric field due to the outer cylinder is zero because it has no net charge. The electric field due to the inner cylinder can be calculated using the same formula as before.

To graph the magnitude of the electric field as a function of the distance r from the axis, you can plot the equation E = λ / (2πε₀r) for values of r ranging from 0 to 2c.

The charge per unit length on the inner surface of the outer cylinder is -λ, while the charge per unit length on the outer surface of the outer cylinder is 0. This is because the outer cylinder has no net charge and the inner cylinder has a uniform positive charge per unit length λ.

Learn more about Electric Field here:

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When a squid pushes against the water, the squid moves forward because the ______________ pushes against the _______________.

Answers

Answer:

water pushes against the squid

The Kelvin scale begins at zero and goes up, 0 Kelvin is also known as _________.

Answers

0 Kelvin is also known as Absolute Zero.

It is also the temperature of nil thermal motion.

This exists in the space surrounding a charged particle and exerts a force on other charged particles.

Answers

Gravitational field exists in the space surrounding a charged particle and exerts a force on other charged particles. Gravitational waves are ripples of waves travelling outward from the source. The more massive the orbit of two bodies, the more it emits gravitational wave. And everything around it that is near within the wave experiences a ‘pull’ toward the orbiting bodies.

Answer:

Nope,(not expert certified)

Electrical Field is the correct answer.

Explanation:

Support that P(e)=0.76,P(F)=0.45,and P(E and F)=0.32. What is P (E or F)?

Answers

The probability of (E and F) = P(e) times P(f) = 0.76 x 0.45 = 0.342 .

The probability of (e OR f) =

   1 - P(not e AND not f) =

   1 - P(not e) x P(not f) =

   1 - (1 - 0.76) x (1 - 0.32) =

   1 - ( 0.24 )   x   ( 0.68 ) = 1 - 0.1632 = 0.8368.

Two asteroids bump in space. The larger one has a mass of 3000 kg and the smaller one has a mass of 100 kg. If the force of the collision is 10,000 newtons on each asteroid, what are their accelerations?a. The larger one is unaffected by the collision, while the smaller one accelerates at 100 m/s2.
b. The larger one accelerates at 3.33 m/s2, while the smaller one accelerates at 100 m/s2.
c. The larger one accelerates at 100 m/s2, while the smaller one accelerates at 3.33 m/s2.
d. The ...

Answers

Answer:

B) The larger one accelerates at 3.33 m/s² while the smaller one accelerates at 100 m/s².

Explanation:

Parameters given:

Mass of larger asteroid = 3000 kg

Mass of smaller asteroid = 100 kg

Force of collision = 10000 N

Since both of them experience the collision force, we can find how that force causes them to accelerate by using the formula of force:

F = m*a

=> a = F/m

For the larger one,

a = 10000/3000 = 3.33 m/s²

For the smaller one,

a = 10000/100 = 100 m/s²

There's really no such thing as the force of a collision.

F = M A
A = F / M

If a 10,000N net force acts on a 3,000 kg object, then the object's
acceleration is (10,000N / 3,000kg) = 3-1/3 m/s² for as long as the
force on it persists, and zero after that.

If a 10,000N net force acts on a 100 kg object, then the object's
acceleration is (10,000N / 100kg) = 100 m/s² for as long as the
force on it persists, and zero after that.

Those appear to be the numbers in choice-b, but the description
of the event and the situation is misleading.

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