The half-life of cobalt-60 is 5.3 years. after __________ years, 1/4 of the original amount of cobalt-60 will remain.

Answers

Answer 1
Answer: The  number of  years  required  for 1/4  cobalt-60  to remain   after   decay  is calculated  as follows

  after  one  half life  1/2 of the original  mass isotope  remains

after  another half life 1/4  mass  of  original  mass  remains

therefore  if one  half  life is  5.3   years  then  the  years required

= 2  x 5.3years =  10.6   years
Answer 2
Answer:

Answer:

10.6

Explanation:APEX


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Answers

You can use the follwing equations.
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a)  pOH=-log10⁻¹²
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You can also use these equations:
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b) [H⁺]=(1.01×10⁻¹⁴)/10⁻²M
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You can use either method.  It does not really matter.
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