What is the final concentration of a solution prepared by diluting 35.0 ml of 12.0 m hcl to a final volume of 1.20 l? what is the final concentration of a solution prepared by diluting 35.0 ml of 12.0 m hcl to a final volume of 1.20 l?

Answers

Answer 1

Answer: We know that, M1V1 = M2V2
(Initial) (Final)
where, M1 and M2 are initial and final concentration of soution respectively.
V1 and V2 = initial and final volume of solution respectively

Given: M1 = 12 m, V1 = 35 ml and V2 = 1.2 l = 1200 ml

∴ M2 = M1V1/V2 = (12 × 35)/ 1200 = 0.35 m
Final concentration of solution is 0.35 m

Answer 2

Answer:

Final answer:

The final concentration of the solution prepared by diluting 35.0 ml of 12.0 M HCl to a final volume of 1.20 L is 0.35 M.

Explanation:

The final concentration of a solution prepared by diluting 35.0 ml of 12.0 M HCl to a final volume of 1.20 L can be calculated using the formula for dilution: M1V1 = M2V2. In this formula, M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

Firstly, we convert the initial volume from ml to litres because the final volume is given in litres. So, 35.0 ml = 0.035 L. Therefore, the equation becomes: 12.0 M * 0.035 L = M2 * 1.20 L.

On rearranging the equation to solve for M2, the result is 0.35 M.

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Answers

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Answers

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