What is the correct noble gas configuration for oxygen?

Answers

Answer 1
Answer: Oxygen (O) is a chemical element which you're surely familiar with since you breathe it every second of your life. The noble gas configuration is [He] 2s2 2p4. This shows that there is a total of 8 electrons (two in the 1s orbital, another 2 in the 2s orbital and the rest in the 2p orbital)

Let me know if you need anything else. 

                           - Dotz :)

Related Questions

If you have 3.0 moles of argon gas at STP, how much volume will the argon take up?
Write the balanced equation for the equilibrium reaction for the dissociation ofsilver chloride in water, and write the K expression for this reaction. Then create an ICE chart. Since we know the equilibrium concentration of the silver ion, we can solve for Ksp.Does it agree with the literature value
What is colloidal solutions ​
What is the mass in grams of 1.9×1023 atoms of lead?
The pH of a solution prepared by mixing 50.0 mL of 0.125 M KOH and 50.0 mL of 0.125 M HCl is ________.

How do I name cycloalkanes?

Answers

Answer:

{ \tt{aromatic \: alkanes}} \n  \n { \underline{ \blue{ \tt{becker⚜jnr}}}}

1. Determine the number of sides of the cyclic compound.

2. Use IUPAC theory, determine the functional group and its position.

After clamping a barrette to a ring stand you noticed that the set up is tippy and unstable what should you do to stabilize the set up?

Answers

Move the buret clamp to a ring stand with a larger base.

ΔH is always positive for a ...........a. endothermic reaction
b. exothermic reaction
c. spontaneous reaction.
d. nonspontaneous reaction.

Answers

Answer:

a. endothermic reaction

Explanation:

In an endothermic reaction, heat is absorbed from the environment. This leaves the surrounding at a colder temperature compared to the system.

ΔH, the change in enthalpy is assigned a positive sign because the heat energy level of the final state is higher than that of the initial state.

Some examples are mostly dissolution substances in water.

What is the correct formula for phosphorus pentachloride? (a) PCl5 (b) P5Cl (c) P(ClO)5 (d) PO4Cl (e) PCIO

Answers

Answer:

(a) PCl_5

Explanation:

Hello,

In this case, such nomenclature expresses the amount of both phosphorous and chlorine atoms via prefixes for the sub indexes of each atom into the molecule, thus, as phosphorous is prefixless one infers that there is just one phosphorous and five chlorides since the prefix for such atom is penta. Therefore, the correct formula is:

PCl_5

Hence, the answer is (a)

Best regards.

Answer:

The correct formula for phosphorus pentachloride is a) PCl5

A sample of chlorine gas initially having a volume of 35.6 L was found to have a volume of 27.2 L at 15.6 atm. What was the initial gas pressure (in atm)? Assume constant temperature.

Answers

Answer: The inital pressure of the gas is 11.9 atm

Explanation:

To calculate the initial pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=?\nV_1=35.6L\nP_2=15.6atm\nV_2=27.2

Putting values in above equation, we get:

P_1* 35.6L=15.6* 27.2\n\nP_1=11.9atm

Thus inital pressure of the gas is 11.9 atm

Two samples of carbon tetrachloride were decomposed into their constituent elements. One sample produced 38.9 g of carbon and 463 g of chlorine, and the other sample produced 14.8 g of carbon and 144 g of chlorine. Part A Are these results consistent with the law of definite proportions?

Answers

Explanation:

Firstly, defining Law of definite proportion which states that in any chemical compound, the elements are the same and are in the same proportion by mass. It is also called Proust's law.

In sample A;

38.9 g of carbon

463 g of chlorine

In sample B;

14.8 g of carbon

144 g of chlorine.

Sample A, Ratio of mass of Carbon to mass of Chlorine

= 38.9 : 463

= 0.084

Sample B, Ratio of mass of Carbon to mass of Chlorine

= 14.8 : 144

= 0.103

These results above show that the ratio of the masses of Carbon to Chlorine in both samples A and B are not the same so therefore, the results are not consistent with the law of definite proportion.