Write the balanced equation for the equilibrium reaction for the dissociation ofsilver chloride in water, and write the K expression for this reaction. Then create an ICE chart. Since we know the equilibrium concentration of the silver ion, we can solve for Ksp.Does it agree with the literature value

Answers

Answer 1
Answer:

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:

Ksp=[Ag^+][Cl^-]

And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

       \ \ \ \ \ \ \ \ \ \ \ \ \ \ AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

I          -                   0             0

C        -                   +x           +x

E        -                    x             x

Which leads to the following modified equilibrium expression:

Ksp=x^2

Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.

Regards!


Related Questions

What volume will 12 g of oxygen gas (O2) occupy at 25 °C and a pressure of 53 kPa?
The theoretical yield for CuCO3.Cu(OH)2+2h2SO4 ®2CuSO4+2H2O+3CO2
For the reaction shown, find the limiting reactant for each of the initial quantities of reactants.4Al(s) + 302(g) —> 2Al2O3(s)Express your answer as a chemical formula. 1 mol Al; 1 mol O2 4 mol Al; 2.5 mol O2 12 mol Al; 10 mol O2 15.4 mol Al; 10.7 mol O2
A 0.2264 g sample of a pure carbonate, XnCO3(s) , was dissolved in 50.0 mL of 0.1800 M HCl(aq) . The excess HCl(aq) was back titrated with 24.90 mL of 0.0980 M NaOH(aq) . How many moles of HCl react with the carbonate
WORTH A LOT OF POINTS! just copy what on the picture for notes so i can copy and paste i do not feel like writing all of that down

Compare and contrast how observations and results can be used tosupport a conclusion to an experiment.

Answers

Answer:

by statistical analyses, especially by determining the p-value

Explanation:

In general, observations and results obtained from experimental procedures are subjected to a statistical test to check the robustness of the working hypothesis. The p-value is the most widely used statistical index in order to test such observations and results. The p-value is the statistical probability of obtaining extreme observed results when the null hypothesis is considered correct. A p-value lesser than 0.05 generally is considered statistically significant and then the null hypothesis can be rejected. In consequence, a very low p-value (which is obtained by statistical analysis of the observations and results), indicates that there is strong evidence in support of the alternative hypothesis.

How many moles of titanium (Ti) atoms are in 85.3 g of Ti?

Answers

Answer:

1.7820210165667731 your welcome :)

Explanation:

Which of the following describes a way in which chemistry affects how youuse a computer?
A. The colors in the computer display are the result of substances
that glow.
B. By clicking a mouse, you can select an object or text on a
computer screen.
C. Eye stress can be reduced by sitting a certain distance from the
Screen.
D. You are able to play video games by moving your body instead of a
joystick

Answers

A way in which chemistry affects how To use a computer is  The colors in the computer display are the result of substances that glow. Option A

In modern computers, the display technology commonly used is Liquid Crystal Display (LCD) or Light Emitting Diode (LED) technology. These displays rely on the principles of chemistry to produce the colors that we see on the screen.

In LCD screens, tiny liquid crystal cells are controlled by an electric current, which causes them to either block or allow the passage of light. Each cell represents a pixel on the screen, and by controlling the intensity of light passing through each pixel, different colors can be produced.

The liquid crystals used in LCD screens are organic compounds that exhibit unique optical properties, allowing them to manipulate light in a controlled manner.

LED screens, on the other hand, use arrays of light-emitting diodes to generate light. These diodes are made of semiconducting materials, often composed of compounds like gallium, arsenic, and phosphorus. When an electric current passes through these compounds, they emit light of a specific wavelength, resulting in the different colors displayed on the screen.

So, the colors we see on a computer display are a direct result of the chemical properties and behavior of the substances used in the LCD or LED technology. Chemistry plays a crucial role in the design and functionality of computer displays, enabling us to view vibrant and accurate colors while using our computers.

Option A

For more such question on chemistry visit:

brainly.com/question/29886197

#SPJ8

The standard free energy change for a reaction in an electrolytic cell is always:_________ a. Positive
b. Negative
c. Zero
d. Impossible to determine

Answers

Answer: The standard free energy change for a reaction in an electrolytic cell is always positive.

Explanation:

Electrolytic cells use electric currents to drive a non-spontaneous reaction forward.

Relation of standard free energy change and emf of cell

\Delta G^o=-nFE^0_(cell)

where,

\Delta G^o = standard free energy change

  n= no of electrons gained or lost

F= faraday's constant

E^0_(cell) = standard emf

E^0_(cell)   = standard emf = -ve  , for non spontaneous reaction

Thus  \Delta G^o=(-ve)(-ve)=+ve

Thus standard free energy change for a reaction in an electrolytic cell is always positive.

how does the presence of a strong electrolyte in solution affect the colligative properties of a solution when compared to the same number of moles of a nonelectrolyte solute?

Answers

Answer:

  • lowered vapor pressure
  • higher boiling point

Explanation:

The colligative properties of a given solution can be defined as the properties of that solution that are dependent on the concentration of the molecules or ions of the solute in the solution, and not on the type or identity of that solute. Examples include:

1. vapor pressure lowering

2. boiling point elevation

3. freezing point depression

4. Osmotic pressure

In this case, vapor pressure would be lowered because with an electrolyte introduced into a solution, the number of solute particles would be larger because the solute particles dissociate into ions, thereby competing with the solvent molecules at the surface of the solution, which in turn reduces the rate at which the solvent evaporates and condenses. Vapor pressure is lower compared to a solution with the same number of moles of  nonelectrolyte solute.

The higher the number of ions in the solution, the greater the colligative properties of the solution will be impacted.

Final answer:

The presence of a strong electrolyte in solution affects the colligative properties differently than a non-electrolyte solute. Strong electrolytes dissociate into ions, increasing the number of particles in solution. This affects colligative properties such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.

Explanation:

The presence of a strong electrolyte in solution affects the colligative properties differently than the same number of moles of a non-electrolyte solute. This is because strong electrolytes dissociate into ions when dissolved in solution, while non-electrolytes do not. The dissociation of strong electrolytes increases the total number of particles in solution, which affects colligative properties such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.

For example, let's compare a solution of 1 mole of sodium chloride (NaCl) to a solution of 1 mole of sucrose (C12H22O11). The sodium chloride will dissociate into Na+ and Cl- ions, which means there are now 2 particles in solution (1 Na+ and 1 Cl-) instead of just 1 molecule of sucrose. This higher particle concentration will result in a greater depression of the freezing point and elevation of the boiling point compared to the sucrose solution.

In summary, the presence of a strong electrolyte increases the number of particles in solution, leading to greater deviations in colligative properties compared to the same number of moles of a non-electrolyte solute.

Learn more about Colligative properties here:

brainly.com/question/34190054

#SPJ3

A student adds solid KCl to water in a flask. The flask is sealed with a stopper and thoroughly shaken until no more solid KCl dissolves. Some solid KCl is still visible in the flask. The solution in the flask is A) saturated and is at equilibrium with the solid KCl B) saturated and is not at equilibrium with the solid KCl C) unsaturated and is at equilibrium with the solid KCl D) unsaturated and is not at equilibrium with the solid KCl

Answers

Answer:

Option (A) saturated and is at equilibrium with the solid KCl

Explanation:

A saturated solution is a solution which can not dissolve more solute in the solution.

From the question given above, we can see that the solution is saturated as it can not further dissolve any more KCl as some KCl is still visible in the flask.

Equilibrium is attained in a chemical reaction when there is no observable change in the reaction system with time. Now, observing the question given we can see that there is no change in flask as some KCl is still visible even after thorough shaking. This simply implies that the solution is in equilibrium with the KCl solid as no further dissolution occurs.

Other Questions