How does the scientific process generally begin?

Answers

Answer 1
Answer:

Answer : To develop a scientific process is a big task. Initially the scientist or the interested researcher may start with the following steps;

a) Start with an Unsolved question;

b) Conduct experiments;

c) Analyse from the observations of the experiments

d) From the conclusions create an theoretical hypothesis;

e) Check for reproducibility of the test results.

f) Write a thesis and submit to a scientific community.

Answer 2
Answer: There are several approaches. The most favourable one (in my opinion) is this one:
1. Asking a question
2. Doing a research (how to answer this question)
3. Creating a hypothesis (NOT a thesis!)
4. Experimenting (to prove the hypothesis)
5. Analysing results from the experiment
6. Writing a thesis

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Answers

Answer:

I think the Answer is B. Longitudinal waves

Calculate the wavelength of violet light with a frequency of 750×10 to the 12

Answers

The wavelength of violet light with a frequency of 750 × 10^12 Hz is  400 nanometers (nm).

Wavelength is the distance between two consecutive peaks or troughs of a wave, representing the length of one complete cycle of the wave. It is commonly used to describe the size or scale of various types of waves, including electromagnetic waves such as light.

To calculate the wavelength of light, you can use the formula:

wavelength = speed of light/frequency

The speed of light is approximately 3.00 × 10^8 meters per second.

Let's plug in the values:

frequency = 750 × 10^12 Hz

speed of light = 3.00 × 10^8 m/s

wavelength = (3.00 × 10^8 m/s) / (750 × 10^12 Hz)

Simplifying the expression:

wavelength = (3.00 / 750) × (10^8 / 10^12) m

wavelength = 4.00 × 10^-4 m

Therefore, the wavelength of violet light is approximately 4.00 × 10^-4 meters or 400 nanometers (nm).

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Wavelength (L) is equal to the Speed of Light (c) divided by the Frequency (f) ; L = c / f

L = (299,792,458 m/s) / (750E12 Hz) = 3.9972E-7 = 399.72E-9
or roughly 400 nanometers

A motorist traveling at 17 m/s encounters a deer in the road 39 m ahead. If the maximum acceleration the vehicle’s brakes are capable of is −7 m/s 2 , what is the maximum reaction time of the motorist that will allow her or him to avoid hitting the deer? Answer in units of s. 019 (part 2 of 2) 10.0 points If his or her reaction time is 1.21983 s, how fast will (s) he be traveling when (s)he reaches the deer? Answer in units of m/s.

Answers

Answer:

1.     t_reaction = 1.08 s

2.     v₀₁ = 16.365 m/s

Explanation:

1. This is a kinematics exercise, let's analyze the situation a bit, we can calculate the braking distance and the rest of the distance we can use to calculate the reaction time.

Braking distance

           v² = v₀² + 2 a x

when he finishes braking the speed is v = 0

            0 = v₀² + 2 a x

            x = -v₀² / 2a

            x = - 17²/2 (-7)

            x = 20.64 m

the distance for the reaction is

            d = x_reaction + x

            x_reaction = d - x

            x_reaction = 39 - 20.64

            x_reaction = 18.36 m

as long as it has not reacted the vehicle speed is constant

            v = x_reaction / t_reaction

            t_reaction = x_reaction / v

            t_reaction = 18.36 / 17

            t_reaction = 1.08 s

2. Let's find the distance traveled in the reaction time of t1 = 1.21983 s

       as the speed is constant

           v = x / t

           x₁ = v t₁

the distance traveled during braking is

           v² = v₀² + 2a x₂

           0 = v₀² + 2 a x₂

           x₂ = -v₀² / 2a

         

           v = v₀

the total distance is

         x_total = x₁ + x₂

         x_total = v₀ t₁ + v₀² / 2a

         39 = v₀ 1.21983 + v₀²/14

         v₀² + 17.08 vo - 546 =0

we solve the second degree equation

       v₀ = [ -17.08 ±√(17.08²  + 4  546) ]/2

       v₀ = [-17.08 ± 49.81 ]/2

       v₀₁ = 16.365 m/s

       v₀₂ = - 33.445 m/s

as the acceleration is negative the correct result is v₀₁ = 16.365 m/s

An object is moving to the right, and experiencing a net force that is directed to the right. The magnitude of the force is decreasing with time. The speed of the object is:A. increasingB. constant in timeC. decreasing

Answers

Answer:

The speed of the object is increasing.

F = M a       as long as the magnitude of the acceleration is acting towards the right there will be an acceleration towards the right

4 points Two cylindrical resistors R, and R2 made from the same material are connected in parallel in a circuit. Both resistors are at the same temperature when the circuit is operational. Resistor R, has length and diameter d. Resistor R has length 8l and has a diameter d/1. Determine by what factor is the resistance R greater than R.St. your answer as an integer with no decimal place. Type your answer...

Answers

To determine the factor by which the resistance of resistor R2 is greater than resistor R1, we can use the formula for resistance of a cylindrical resistor:

R = ρ * (L/A)

Where R is the resistance, ρ is the resistivity of the material, L is the length of the resistor, and A is the cross-sectional area of the resistor.

Since both resistors are made from the same material and are at the same temperature, the resistivity ρ is the same for both resistors.

Let's calculate the resistance for R1 and R2 separately.

For resistor R1 (length = L and diameter = d), the cross-sectional area A1 is given by:

A1 = π * (d/2)^2

For resistor R2 (length = 8L and diameter = d/1), the cross-sectional area A2 is given by:

A2 = π * ((d/1)/2)^2

Simplifying the equations:

A1 = π * (d/2)^2 = π * (d^2/4)

A2 = π * ((d/1)/2)^2 = π * (d^2/4)

As we can see, both resistors have the same cross-sectional area A.

Now, let's calculate the resistance for R1 and R2:

R1 = ρ * (L/A1) = ρ * (L / (π * (d^2/4)))

R2 = ρ * (8L/A2) = ρ * (8L / (π * (d^2/4)))

Simplifying the equations further:

R1 = (4ρL) / (πd^2)

R2 = (32ρL) / (πd^2)

Now, let's find the factor by which the resistance R2 is greater than R1:

Factor = R2 / R1 = ((32ρL) / (πd^2)) / ((4ρL) / (πd^2))

Canceling out common terms:

Factor = (32ρL * πd^2) / (4ρL * πd^2)

Factor = 32 / 4

Factor = 8

Therefore, the resistance R2 is 8 times greater than the resistance R1.

The resistance of second resistor R2, is 16 times greater than the resistance of the first resistor R1.

The resistance of a cylindrical resistor is given by R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area (which is πd²/4 for a cylinder). For R1, it has length L and diameter d. For R2, it has length 8L and diameter d/1. The resistance of R2 is therefore:

R2 = ρ(8L)/(π(d/1)²/4)

By comparing R2 to R1, we find that R2 is 16 times the resistance of R1.

The resistance of second resistor R2, is 16 times greater than the resistance of the first resistor R1.

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What is the power of a refrigerator with voltage 110 V and
current 0.8 A?

Answers

Answer: 88

Explanation: