Which of the following variables do you need to know in order to calculate the partial pressure of a gas? (We are going to ignore water vapor here.) Check all that apply.
a. the volume of the container that the gas is in
b. the percentage of the gas
c. the percentage of the other gases that comprise the atmosphere
d. the total pressure in the atmosphere
Answers
Answer:
C.)
Explanation:
i said c because. idk i guessed sry
Related Questions
A motorist traveling at 17 m/s encounters a deer in the road 39 m ahead. If the maximum acceleration the vehicle’s brakes are capable of is −7 m/s 2 , what is the maximum reaction time of the motorist that will allow her or him to avoid hitting the deer? Answer in units of s. 019 (part 2 of 2) 10.0 points If his or her reaction time is 1.21983 s, how fast will (s) he be traveling when (s)he reaches the deer? Answer in units of m/s.
How do the speeds v0, v1, and v2 (at times t0, t1, and t2) compare?a: v0 = v1 = v2 > 0b: v0 = v2 > v1 = 0c: v0 = v2 > v1 > 0d: v0 > v1 > v2 > 0e: v0 > v2 > v1 = 0
You're conducting a physics experiment on another planet. You drop a rock from a height of 2.3 m and it hits the ground 1.1 seconds later. What is the acceleration due to gravity on this planet?A. 4.2 m/s2 B. 3.8 m/s2 C. 2.4 m/s2 D. 9.8 m/s2
Which one of the following sources produces the highest energy photons? A)a doctor's x-ray source B)a heat lamp in a restaurant C)a microwave oven D) gamma rays from a star radio E)waves from a local station
B. The entire universe.
C. All of these
D. Outside of the experiment, or reaction of interest.
Answers
Answer:
the awnser is A
Explanation:
the awnser is A
Answers
Answer: energy is released from the nuclei of atoms
Explanation:
Chemical energy is the energy stored in the bonds of molecules.
Nuclear energy is the energy stored in the nucleus of the atom.
Nuclear power plants use heat produced during nuclear fission to heat water which is produced by the splitting of heavy nucleus into lighter elements by release of energy.
The complete nuclear fission reaction is:
b. to listen for unlawful broadcasts from rogue nations
c. to listen for signals from outer space
d. to listen for sounds emitted from the ocean
Answers
Answers
The volume of a sample of copper of 98.2 g would be 10.95 ml if the density of copper is 8.96 g/mL.
What is density?
It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
Due to their superior electrical and thermal conductivities, remarkable resistance to corrosion, and simplicity of production, copper alloys are frequently employed. In general, copper alloys are not magnetic. Electrical wire, cable, contacts, and other components.
As given in the problem the density of copper is 8.96 g/mL, and we have to find the volume occupied by the sample of copper.
mass = density×volume
98.2 g = 8.96 g/mL×volume
volume =98.2/8.96
=10.95 ml
Thus, the volume of a 98.2 g sample of copper would be 10.95 ml.
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Answer:
Density=mass/volume.
8.96=98.2/volume.
volume=98.2/8.96=10.95982143 ~ 11cm^3.
Answers
Answer:
The two stars will look like a single point of light.
Explanation:
When the angular separation is smaller than angular resolution, the eye will not be able to resolve the stars thus they will appear like a point source of light.Angular resolution is one of the limit that our eyes can see. Angular resolution describes how much our eyes can distinguish two things apart which depends on the angle created by the incoming light rays from the two object. A smaller angle, very small angle for light rays to enter the eye thus little or no details for the eye to distinguish.
Final answer:
When two stars are closer together than the angular resolution of our eyes, they appear as a single point of light.
Explanation:
When the angular separation of two stars is smaller than the angular resolution of our eyes, they will appear as a single point of light to our eyes. This is because our eyes cannot distinguish the individual stars due to their close proximity. This is similar to how distant stars appear as pinpoints of light.
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