A motorist traveling at 17 m/s encounters a deer in the road 39 m ahead. If the maximum acceleration the vehicle’s brakes are capable of is −7 m/s 2 , what is the maximum reaction time of the motorist that will allow her or him to avoid hitting the deer? Answer in units of s. 019 (part 2 of 2) 10.0 points If his or her reaction time is 1.21983 s, how fast will (s) he be traveling when (s)he reaches the deer? Answer in units of m/s.

Answers

Answer 1
Answer:

Answer:

1.     t_reaction = 1.08 s

2.     v₀₁ = 16.365 m/s

Explanation:

1. This is a kinematics exercise, let's analyze the situation a bit, we can calculate the braking distance and the rest of the distance we can use to calculate the reaction time.

Braking distance

           v² = v₀² + 2 a x

when he finishes braking the speed is v = 0

            0 = v₀² + 2 a x

            x = -v₀² / 2a

            x = - 17²/2 (-7)

            x = 20.64 m

the distance for the reaction is

            d = x_reaction + x

            x_reaction = d - x

            x_reaction = 39 - 20.64

            x_reaction = 18.36 m

as long as it has not reacted the vehicle speed is constant

            v = x_reaction / t_reaction

            t_reaction = x_reaction / v

            t_reaction = 18.36 / 17

            t_reaction = 1.08 s

2. Let's find the distance traveled in the reaction time of t1 = 1.21983 s

       as the speed is constant

           v = x / t

           x₁ = v t₁

the distance traveled during braking is

           v² = v₀² + 2a x₂

           0 = v₀² + 2 a x₂

           x₂ = -v₀² / 2a

         

           v = v₀

the total distance is

         x_total = x₁ + x₂

         x_total = v₀ t₁ + v₀² / 2a

         39 = v₀ 1.21983 + v₀²/14

         v₀² + 17.08 vo - 546 =0

we solve the second degree equation

       v₀ = [ -17.08 ±√(17.08²  + 4  546) ]/2

       v₀ = [-17.08 ± 49.81 ]/2

       v₀₁ = 16.365 m/s

       v₀₂ = - 33.445 m/s

as the acceleration is negative the correct result is v₀₁ = 16.365 m/s


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A 0.40-kg cart with charge 4.0 x 10-5 C starts at rest on a horizontal frictionless surface 0.50 m from a fixed object with charge 2.0 x 10-4 C. When the cart is released, it moves away from the fixed object. (a) How fast is the cart moving when very far (infinity) from the fixed charge

Answers

Answer:

26.82m/s

Explanation:

Given

Mass = m= 0.4kg

Initial Velocity = u = 0

Charge = 4.0E-5C

Distance= d = 0.5m

Object Charge = 2E-4C

First, we'll calculate the initial energy (E)

E = Potential Energy

PE = kQq / d

Where k = coulomb constant = 8.99E9Nm²/C²

Energy is then calculated by;

PE = 8.99E9 * 4E-5 * 2E-4 / 0.5

PE = 143.84J

Energy = Potential Energy = Kinetic Energy

K.E = ½mv² = 143.84J

½mv² = ½ * 0.40 * v² = 143.85

0.2v² = 143.85

v² = 143.85/0.2

v² = 719.25

v = √719.25

v = 26.81883666380777

v = 26.82m/s

Hence, the object is 26.82m/s fast when the cart moving is very far (infinity) from the fixed charge

What force keeps an object moving in a circle

Answers

A centripetal force does that.

Which statement is correct? a) 1 in. = 2.54 cm b) 7 in. = 17.68 cm c) 1 ft = 12 in. d) 74 in. = 1 yd

Answers

Answer:

a) 1 in. = 2.54 cm

Explanation:

Final answer:

The correct statement is a) 1 in. = 2.54 cm. To convert inches to centimeters, multiply the number of inches by the conversion factor 2.54 cm/1 in.

Explanation:

The correct statement is a) 1 in. = 2.54 cm.

To convert inches to centimeters, you can multiply the number of inches by the conversion factor 2.54 cm/1 in. For example, if you want to convert 7 inches to centimeters, you would multiply 7 in. by 2.54 cm/1 in. This gives you 17.78 cm, which is approximately equal to 17.68 cm (as stated in option b).

Option c) 1 ft = 12 in. and option d) 74 in. = 1 yd are also correct statements, but they are not directly related to the conversion between inches and centimeters.

Learn more about Conversion between inches and centimeters here:

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What is the magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge? 

Answers

In an electric field force,F= q₁q₂/4πε₀ r²  (coulomb's law)  as we know,F=qE  E=F/q
E=q/4πε₀ r²
here,r= 0.0075 m
       q= 0.0035 C
      1/4πε₀  = 9×10⁹
        E=  9×10⁹× 0.0035/(0.0075)²
          =5.6 ×10¹¹ N/C

Answer:

5.6x1011 N

Explanation:

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Answers

Answer:

b. Decreases

Explanation:

The total resistance of a series circuit is equal to the sum of the individual resistances:

R_T=R_1+R_2+...+R_n (1)

Therefore, as we add more lamps, the total resistance increases (because we add more positive tems in the sum in eq.(1).

The current in a circuit is given by Ohm's law:

I=(V)/(R_T)

where V is the voltage provided by the power source and R_T is the total resistance. We notice that the current, I, is inversely proportional to the total resistance: therefore, when more lamps are added to the series circuit, the total resistance increases, and therefore the current in the circuit decreases.

Discuss how the hardness or softness of the landing surface is related to the time required to stop the egg

Answers

Answer

To understand this concept it is necessary to understand Newton's Second Law

According to Newtons Second law applied force is equal to rate of change of momentum of a body.

Mathematically,

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On the other hand on the soft surface like a cotton, egg will not stop instantly but it will slow down for a few seconds and then stop due to which the time of impact will increase. Therefore the force on egg will be less and it won't break up.