PHYSICS HIGH SCHOOL

The conductive tissues of the upper leg can be modeled as a 40- cm-long, 12-cm-diameter cylinder of muscle and fat. The resistivities of muscle and fat are 13 Ω m and 25 Ω m, respectively. One person’s upper leg is 82% muscle, 18% fat. What current is measured if a 1.5 V potential difference is applied between the person’s hip and knee?

Answers

Answer 1
Answer:

Answer:

current = 0.0027 A

Explanation:

the resistivity of upper leg

\rho = 0.82 (13) + 0.18(25) = 15.16 ohm . m

Resistance of upper leg

R = (\rho L)/(A)

   = (\rho L)/(\pi R^2)

  = (15.16 * 0.40)/(\pi [(0.12)/(2)]^2)

  = 551.27 ohm

currenti = (V)/(R)

current = (1.5)/(551.27)

current = 0.0027 A

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