Will baby oil and water form a solution

Answers

Answer 1
Answer: They will not form a solution because one is more dense than the other. 
Answer 2
Answer: Water has a greater density than oil. Baby oil and water wont form a solution.

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An isotope remains unchanged by the emission of a gamma ray, which is a(n) __________.

Answers

Answer:

The answer to your question is photon. An isotope remains unchanged by the emission of a gamma ray, which is a (an) photon123. A photon is a particle of light or electromagnetic radiation that has no mass and no electric charge4. A gamma ray is a type of photon that has the highest energy and frequency in the electromagnetic spectrum4. Gamma rays are emitted by the nuclei of some radioactive atoms when they undergo a nuclear rearrangement or decay4. Gamma ray emission causes no change in the number of particles in the nucleus, meaning both the atomic number and mass number remain the same23. Therefore, an isotope does not change its identity or mass when it emits a gamma ray, but only releases some excess energy as a photon. I hope this answer helps you understand the concept of gamma ray emission better.

In which type of reaction do two lighter nuclei combine to form one heavier nucleus?(1) combustion (3) nuclear fission
(2) reduction (4) nuclear fusion

Answers

Answer:

Nuclear Fusion

Explanation:

In nuclear fusion two lighter nuclei combine together in order to form one heavier nucleus.

For example, the energy generated from the Sun is made by nuclear fusion: Two hydrogen (H, atomic number 1) nuclei combine in order to form one helium  (He, atomic number 2) nucleus.

Nuclear fission is the opposite reaction, in which one heavier nucleus splits into two lighter nuclei.

A mixture which contains more than one phase is called .

Answers

A mixture that contains more than one phase is called heterogenous mixtures. Mixtures which have a single phase is called homogenous mixtures.

What are mixtures ?

Mixtures are the combination of two or more individual substances. They can be physically adhered or chemically bonded. Mixtures can be separated using physical techniques.

Broadly there are two types of mixtures, homogenous and heterogenous. The mixtures in which components are uniformly distributed and miscible each other forming a single phase is called homogenous mixtures.

Mixtures, in which each component is visible separately due to the immiscibility and phase separation is called heterogenous mixtures. Heterogenous mixtures can be easily separated into its components.

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This is a heterogeneous mixture. 

What does it mean if Keq = 1?a. Products and reactants are equally favored in the reaction.
b. Products are favored over reactants in the reaction.
c. Reactants are favored over products in the reaction.
d. All of the reactants have turned into products in the reaction.

Answers

Final answer:

If Keq equals 1, this means the reaction is at equilibrium and neither the reactants nor the products are favored. The concentrations of both remain constant over time.

Explanation:

When Keq = 1, it implies that the reaction is at equilibrium and neither the reactants nor the products are favored in the reaction. So, the correct answer to your question is option a: Products and reactants are equally favored in the reaction.

In this situation, the concentrations of products and reactants remain constant over time because the rate of the forward reaction equals the rate of the reverse reaction.

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Final answer:

For a chemical equilibrium, Keq = 1 indicates that neither reactants nor products are favored; rather, they are present in roughly equal amounts at equilibrium. So the correct answer is Option C.

Explanation:

If Keq = 1 for a chemical equilibrium, it means that products and reactants are equally favored in the reaction. In other words, neither the reactants nor the products are favored when the reaction reaches equilibrium. Equilibrium constants help us understand the extent to which a reaction occurs. When Keq is greater than 1, the concentration of products at equilibrium is greater than the concentration of reactants, suggesting a product-favored reaction. Conversely, when Keq is less than 1, the concentration of reactants is higher, indicating a reactant-favored reaction. When Keq is equal to 1, it implies that the concentrations of reactants and products are roughly equal at equilibrium, reflecting a state of balance in the chemical system.

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At the same temperature and pressure, 1.0 liter of CO(g) and 1.0 liter of CO2(g) haveA. equal masses and the same number of molecules
B. different masses and a different number of molecules
C. equal volumes and the same number of molecules
D. different volumes and a different number of molecules

Answers

Answer is C - equal volumes and the same number of molecules.

Explanation;

Let's assume that CO and CO₂ are ideal gases. Then we can use ideal gas law, PV = nRT

Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol⁻¹ K⁻¹) and T is temperature in Kelvin.

The temperature and the pressure of the both gases are same. Volume is also same as 1.0 L. R is a constant. So according to the formula, both gases have same number of moles. According to the Avogadro's constant, 1 mole has 6.022 x 10²³ particles.

number of molecules = Avogadro's constant x number of moles.

Hence, under the same conditions both gases have same number of molecules.

C is the correct answer. All gases have the same volume under the same conditions.. This is just their nature. And one liter of a gas has the same number of molecules of another gas

Directions: Write the name of the type of chemical reaction in the space provided.(Can be Synthesis Reaction, Decomposition Reaction, Combustion, Single Displacement Reaction or Double Displacement Reaction)

Answers

The given reactions are combination reaction, decomposition reaction, neutralization reaction, displacement reaction and double displacement reaction.

What is displacement reaction?

A displacement reaction is a chemical process during which a one more reactive element being replaced from its compound by a less reactive element.

What is combination reaction?

When A combination reaction occurs when one or more elements or compounds react together to generate a new chemical. Equations of the following kind are used to depict such reactions.

X+ Y→XY

6) Fe}(s)+3{O}_(2)(g)2{Fe}_(2) {O}_(3)(s), this reaction is a kind of combination reaction reaction.

7) {Zn}_(2)(s)+2 {HCl} (aq){ZnCl}_(2)(a q)+{H}_(2)(g)

This reaction is a kind of displacement reaction.

8) {MgCO}_(3)(a q)+2 {HCl}(a q)  →{MgCl}_(2)(a q)+{H}_(2) {O}(l)+{CO}_(2)(g).

This reaction is a kind of combustion reaction.

9) {NiCl}_(2)(s){Ni}(s)+{Cl}_(2)(g).

This reaction is a kind of decomposition reaction.

10) {C}(s)+6 {H}_(2)(g)+{O}_(2)(g)2 C}_(2) {H}_(6) {O}(s).

This reaction is a kind of combination reaction.

11) $\mathrm{C}_(12) \mathrm{H}_(22) \mathrm{O}_(11)(s) \rightarrow 12 \mathrm{C}(s)+11 \mathrm{H}_(2) \mathrm{O}(\mathrm{g})$ .

This reaction is a kind of dissociation reaction.

12) $2 \mathrm{LiI}(a q)+\mathrm{Pb}\left(\mathrm{NO}_(3)\right)_(2)(a q) \rightarrow 2 \mathrm{LiNO}_(3)(a q)+\mathrm{PbI}_(2)(s)$.

This reaction is a kind of double displacement reaction.

13) $\mathrm{CdCO}_(3)(s) \rightarrow \mathrm{CdO}(s)+\mathrm{CO}_(2)(g)$.

This reaction is a kind of decomposition reaction

14) $\mathrm{Cl}_(2)(g)+2 \mathrm{KBr}(a q) \rightarrow 2 \mathrm{KCl}(a q)+\mathrm{Br}_(2)(g)$.

This reaction is a kind of single displacement reaction.

15) $\mathrm{BaCl}_(2)(a q)+2 \mathrm{KIO}_(3)(a q) \rightarrow \mathrm{Ba}\left(\mathrm{IO}_(3)\right)_(2)(s)+2 \mathrm{KCl}(a q)$.

This reaction is kind of double displacement reaction.

16) $2 \mathrm{Mg}(s)+\mathrm{O} 2(\mathrm{~g}) \rightarrow 2 \mathrm{MgO}(s)$.

This reaction is a kind of combination reaction.

17) AgNO_(3) (aq) +KI(aq)KI(aq) + KNO_(3)(aq).

This reaction is a kind of double displacement reaction.

18) $2 \mathrm{Li}(s)+\mathrm{H}_(2) \mathrm{O}(b) \rightarrow 2 \mathrm{LiOH}(a q)+\mathrm{H}_(2)(g)$.

This reaction is a kind of single displacement reaction.

19) $\mathrm{C}(\mathrm{s})+\mathrm{O}_(2)(\mathrm{~g}) \rightarrow \mathrm{CO}_(2)(\mathrm{~g})$.

This reaction is a kind of combination reaction.

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