________ found that electric and magnetic energy move in waves.

Answers

Answer 1
Answer:
James Clerk Maxwell is the answer

Related Questions

You need to get to class, 200 meters away, and you can only walk in the hallways at about 1.5 m/s. (if you run any faster, you’ll be caught for running). How much time will it take to get to your class?
Calculate the maximum kinetic energy of photoelectrons emitted from this plate when light of wavelength (λ) 520nm is directed at the metal surface.Work function (Ф) of the plate = 1.1 × 10⁻¹⁹ JPlanck's constant (h) = 6.63 × 10⁻³⁴ JsFrequency (f) = c ÷ λc = speed light in vacuum = 3.00 × 10⁸ms⁻¹Ekmax = hf - ΦWavelength must be in metres, so it'll be 590×10⁻⁹I've worked this out and gotten two different answers so I thought I'd check to see which one is right.
In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately 2.03 106 m/s.(a) Find the force acting on the electron as it revolves in a circular orbit of radius 5.35 10-11 m. whats the magnitude in N ? (b) Find the centripetal acceleration of the electron. whats the magnitude in m/s2
Which is the longer wavelength? A.) 10 cm B.) 10 m C.) 10 nm D.) 10 km
You put the wet leaves in the container and turn the crank to spin off the water. The radius of the container is 13.2 cm. When the cylinder is rotating at 1.63 revolutions per second, what is the magnitude of the centripetal acceleration at the outer wall?

Kuiper Belt objects are composed of which substances? Select all that apply.A. Iron
B. Silicon
C. Water
D. Methane
E. Ammonia

Answers

IM sure there is C, D, and E in kuiper belts, but not really sure of silicon and iron

a car is moving with a constant speed of 20 meters per second.What total distance does the car travel in 2 minutes

Answers

There are 120 seconds in two minutes, so to find the answer, you multiply 20 x 120 to get 2400 meters.

Final answer:

The car travels a total distance of 2400 meters in 2 minutes at a constant speed of 20 meters per second.

Explanation:

Distance is the measurement of space between two points, typically in terms of length or spatial separation. It is a fundamental concept used in various fields, including physics, geography, and mathematics.

To find the total distance travelled by the car in 2 minutes, you need to calculate the distance covered in 1 second and then multiply it by the number of seconds in 2 minutes.

Since the car is moving at a constant speed of 20 meters per second, the distance covered in 1 second is 20 meters.

To find the total distance, multiply 20 meters by 60 seconds (1 minute) and then again by 2 (number of minutes).

The total distance travelled by the car in 2 minutes is 2400 meters.

Learn more about distance travelled here:

brainly.com/question/34023763

#SPJ2

if a gas has a gage pressure of 156 kpa its absolute pressure is approximately .....A... 56 kPa ....B....100 kPa.......C......256 kPa....D...300 kPa.....

Answers

256 kPa because p-guage + p-absolute + p-atmospheric = 256

Answer:

C. 256 kPa

Explanation

An object moving in a circle at a constant speed is accelerating. Why?A. because it is going faster
B. because it has constant velocity
C. because its direction is changing
D. because the distance it is traveling is changing

Answers


"Acceleration" does NOT mean 'speeding up'.  It means any change
in the speed or direction of motion ... speeding up, slowing down, or
moving in a curve.

An object moving in a circle at a constant speed is accelerating, because
when you're moving along a circle, your direction is constantly changing.

A. Because it is going faster.

An blank
Used to determine the change of an object

Answers

The acceleration is used to determine the change of an object.

The speed of sound is 330.0 m/s and the wave length of a particular sound wave is 33.0 meters. Calculate the frequency of the sound wave. A)11,000 Hz B)10.0 Hz C) 0.10 Hz D)9.1 x 10-5 Hz

Answers

Answer:

B). f = 10.0 Hz

Explanation:

As we know the relation between frequency, wavelength and speed is given as

v = f \lambda

here we know that

v = 330 m/s

\lambda = 33 m

now in order to find the frequency of the sound we can use above relation as

f = (v)/(\lambda)

plug in all values in it

f = (330)/(33)

f = 10 Hz

v: velocity of wave
f: frequency 
L: wavelenght

v = fL => f = v/L => f = (330)/(33) => L = 10Hz