How to decrease £64 by 70%

Answers

Answer 1
Answer: you can do it in two ways, 

1st method,

64×70=4480
4480÷44.8
64-44.8=19.2

2nd method,
you have to find the common multiplier,
to find the common multiplier you have to decrease the percentage by 100 and divide it by 100,

100-70=30
30÷100=0.3

now you have to multiply 0.3 and 64,

0.3×64=19.2

either way, you'll get the answer, 19.2
hope this helps....

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Graph 4x^2 + y^2 = 9. What are its lines of symmetry?

Answers

4 x²  + y² = 9  / : 9
x² / (9/4) + y² / 9 = 1
This is an ellipse.  Equation is:  x²/a² + y²/b² = 1
a² = 9/4  ⇒ a = 3/2
b² = 9  ⇒ b = 3
The axis of symmetry are the x and y axis, or the lines: y = 0 and x = 0.
Graph is in the attachment. 

The lines of symmetry for the graph of equation 4x² + y² = 9 are the x-axis and the y-axis.

To determine the lines of symmetry of the graph of equation 4x² + y² = 9, we need to analyze the form of the equation.

The given equation represents an ellipse, as it contains terms for both x² and y².

Comparing this with the given equation 4x² + y² = 9, we can rewrite it as:

(2x)²/3² + y²/3² = 1

By comparing the equations, we can deduce that a² = 3² and b² = 3². This means that the major axis has a length of 2a = 2(3) = 6 and the minor axis has a length of 2b = 2(3) = 6.

Since the ellipse is symmetric with respect to both the x-axis and the y-axis, there are two lines of symmetry.

Learn more about ellipses here:

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The Length of a standard jewel case is 7cm more than its width. The area of the rectangular top of the case is 408cm. Find the length and width of the jewel Case

Answers

Answer:

The length of the case is 24 cm and its width is 17cm.

Step-by-step explanation:

The Length of a standard jewel case is 7cm more than its width.

Let the length be represented by L and the width be represented by W, this means that:

L = 7 + W

The area of the rectangular top of the case is 408cm². The area od a rectangle is given as:

A = L * W

Since L = 7 + W:

A = (7 + W) * W = 7W + W²

The area is 408 cm², hence:

408 = 7W + W²

Solving this as a quadratic equation:

=> W² + 7W - 408 = 0

W² + 24W - 17W - 408 = 0

W(W + 24) - 17(W + 24) = 0

(W - 17) (W + 24) = 0

=> W = 17cm or -24 cm

Since width cannot be negative, the width of the case is 17 cm.

Hence, the length, L, is:

L = 7 + 17 = 24cm.

The length of the case is 24 cm and its width is 17cm.

If a bicycle cost $70.50 but it's on sale for 47% off how much is the discount what is the sale price

Answers


first multiply the two terms together to find out how much money is being discounted

$70.50 x .47 = 33.135

now subtract that number from $70.50

$70.50 - 33.135 = $37.37

ANSWER: the discount is $33.14 & the sale price is $37.37

You are dealt one card from a 52-card deck. Find the probability that you are dealt: a numbered card or a spade

Answers

in 52-card deck there are 36 numbered card and 52/4=13 spade card
 so probability that you are dealt a  numbered card is 36/52 =9/13  a spade card is 13/52=1/4
So you start out with the 52 original cards. You know what 13 cards are spade shaped, and there are 10 numbered cards in each symbol. In total, 40 out of 52 cards are numbered, and 13 out of 52 are spade symbol. Now 10 out each symbol are numbered, start out with that. That equals 30 numbered cards. Now add the entire spade minideck, and you have 43 cards being the possibility. In numerical form, 43 out of the 52 cards are possible to be chosen. In fraction form, 43/52 will be your answer.

PQR is shown.
What are the missing side lengths in PQR?
Please try to show your work

Answers

The triangle is isosceles. It also has two 45 degree angles. That means the sides are "x" and the hypotenuse is sqrt(2)*x. If you do the math, the answer is 8.485

I NEED HELP PLEASEGeometry: Quadrilateral LMNO is reflected over the line as shown, resulting in quadrilateral CDAB. Given the congruency statement LMNO ≅ CDAB. What segment corresponds to ML? (Show your work or explain your reasoning).

Answers

Answer: We are given Quadrilateral LMNO is reflected over a line.

Also given Quadrilateral LMNO is congruent Quadrilateral CDAB, that is

LMNO ≅ CDAB.

Note: Reflection over a line represents mirror images of the figures.

From the given image we can see

LM is congruent to CD.

ON is congruent to BA.

LO is congruent to BC.

MN is congruent to AD.

Therefore,  DC segment corresponds to ML.

Hope i helped you out!