Speed of the motor cycle is given as
distance that he moved off from the ramp is given as
now we know that
now we can use this to find the height
so its height will be 75 cm from ground
The height of the ramp is approximately 0.748m.
To find the height of the ramp, we can use the equations of motion. Since the motorcycle leaves the ramp horizontally, the horizontal distance traveled is equal to the initial horizontal velocity multiplied by the time of flight.
Using the equation x = vt, where x is the horizontal distance traveled, v is the initial horizontal velocity, and t is the time of flight, we can solve for t.
For this problem, the horizontal distance is 40.0m and the initial horizontal velocity is 103m/s. Substituting these values into the equation, we get t = x/v = 40.0m / 103m/s = 0.388s.
Next, to find the height of the ramp, we can use the equation h = (1/2)gt^2, where h is the height of the ramp and g is the acceleration due to gravity (approximately 9.8m/s^2). Substituting the value of t we found into the equation, we get h = (1/2)(9.8m/s^2)(0.388s)^2 = 0.748m.
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B:science
C: scientific methods
D: technology
E: controlled variables
Controlled variables are the factor that remains at the same phases of an experiment.
Anything kept constant or constrained in a research study is referred to as a control variable. Despite not being relevant to the study's objectives, this variable is controlled because it might have an impact on the results.
Variables can be controlled either directly by maintaining their value throughout a study (for example, by maintaining a constant room temperature in an experiment) or indirectly by using techniques like randomization or statistical control (e.g., to account for participant characteristics like age in statistical tests).
Hence, controlled variables are that variables which are kept at the same phases of an experiment.
To learn more about controlled experiment, refer the link:
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the controlled varaibles aka E. because the control group is Group of subjects in the experiment that experimental group as compared to
force of gravitation between two different masses is given by
here in first case we will have
Newton
another case we have
Newton
another case we have
Newton
so the force will be maximum in last case when two 2 kg mass is placed at 1 m distance and minimum force is in second case when 1kg and 2kg mass is placed at 2 m distance
Answer:
The two components of displacement vector are:
Explanation:
Given:
The magnitude of displacement is 760 m.
The direction of the displacement vector is 35° North of East.
North of East means that the vector is between North and East and makes an angle of 35° with the east direction.
Now, there are two components of this displacement vector. One component is along the East direction and the other perpendicular to the East direction which is the North direction.
Component along the East direction is given as:
Component along the North direction is given as:
Therefore, the two components that are mutually perpendicular to each other are 622.56 m East and 435.92 m North.
In physics, the vector components of a displacement of 760 meters at an angle of 35 degrees north of east are approximately 622 meters eastward and 435 meters northward.
The displacement vector you're describing is associated with a movement that falls under the umbrella of vector algebra, a common topic in physics. We're given a magnitude (760 m) for the vector and a direction (35° north of east).
We decompose, or break down, this displacement vector into its component along the east (x-direction) and north (y-direction). This splitting of vectors into components is useful when dealing with multiple vectors as it simplifies calculations.
For the eastward component (x-component, or horizontal), we use the cosine of the given angle. For the Northward component (y-component, or vertical), we use the sine of the given angle. The formulas are as follows:
Calculating these gives us roughly x = 622 m eastward and y = 435 m northward. These are the vector components of your original displacement vector.
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