sla’s change in velocity is 30 m/s, and Hazel has the same change in velocity. Which best explains why they would have different accelerations?

Answers

Answer 1
Answer: Because acceleration depends not only on the change in velocity.
It also depends on the time during which the change occurs.
The formula is

Acceleration = (change in velocity) divided by (time for the change) .

Maybe Sla changed his velocity in 3 seconds, but Hazel
took all morning to change hers.  In that case, even though
the amounts of change were equal, the times were different,
so the quotients of (change/time) were different. 

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Recall Elmer Trett, who in 1994 reached a speed of 103m/s on his motorcycle. Suppose trett drives off a horizontal ramp at this velocity and lands a horizontal distance of 40.0m away from the edge of the ramp. What is the height of ramp?

Answers

Speed of the motor cycle is given as

v_x = 103 m/s

distance that he moved off from the ramp is given as

x = 40 m

now we know that

x = v_x * t

40 = 103* t

t = 0.39 s

now we can use this to find the height

h = v_i*t + (1)/(2)gt^2

h = 0 + (1)/(2)*9.8*0.39^2

h = 0.74 m

so its height will be 75 cm from ground

Final answer:

The height of the ramp is approximately 0.748m.

Explanation:

To find the height of the ramp, we can use the equations of motion. Since the motorcycle leaves the ramp horizontally, the horizontal distance traveled is equal to the initial horizontal velocity multiplied by the time of flight.

Using the equation x = vt, where x is the horizontal distance traveled, v is the initial horizontal velocity, and t is the time of flight, we can solve for t.

For this problem, the horizontal distance is 40.0m and the initial horizontal velocity is 103m/s. Substituting these values into the equation, we get t = x/v = 40.0m / 103m/s = 0.388s.

Next, to find the height of the ramp, we can use the equation h = (1/2)gt^2, where h is the height of the ramp and g is the acceleration due to gravity (approximately 9.8m/s^2). Substituting the value of t we found into the equation, we get h = (1/2)(9.8m/s^2)(0.388s)^2 = 0.748m.

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Which could be the factor that remains at the same phases of an experiment?A: observations
B:science
C: scientific methods
D: technology
E: controlled variables

Answers

Controlled variables are the factor that remains at the same phases of an experiment.

What is controlled variable?

Anything kept constant or constrained in a research study is referred to as a control variable. Despite not being relevant to the study's objectives, this variable is controlled because it might have an impact on the results.

Variables can be controlled either directly by maintaining their value throughout a study (for example, by maintaining a constant room temperature in an experiment) or indirectly by using techniques like randomization or statistical control (e.g., to account for participant characteristics like age in statistical tests).

Hence, controlled variables are that variables which are kept at the same phases of an experiment.

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the controlled varaibles aka E. because the control group is  Group of subjects in the experiment that experimental group as compared to

contrast the force of gravity between these pairs of objects: 1-kg mass and a 2-kg mass that are 1 m apart; a 1-kg mass and a 2-kg mass that are 2 m apart; and two 2=kg masses that are 1 m apart. helpppppp i dont understand.

Answers

force of gravitation between two different masses is given by

F = (Gm_1m_2)/(r^2)

here in first case we will have

F_1 = (G(1kg)(2kg))/((1m)^2)

F_1 = 2GNewton

another case we have

F_2 = (G(1kg)(2kg))/((2m)^2)

F_2 = (G)/(2)Newton

another case we have

F_3 =(G(2kg)(2kg))/((1m)^2)

F_3 = 4GNewton

so the force will be maximum in last case when two 2 kg mass is placed at 1 m distance and minimum force is in second case when 1kg and 2kg mass is placed at 2 m distance

The displacement vector from your house to the library is 760 m long, pointing 35° north of east. What are the components of this displacementvector?

Answers

Answer:

The two components of displacement vector are:

East:760\cos 35=622.56\ m\nNorth:760\sin 35=435.92\ m

Explanation:

Given:

The magnitude of displacement is 760 m.

The direction of the displacement vector is 35° North of East.

North of East means that the vector is between North and East and makes an angle of 35° with the east direction.

Now, there are two components of this displacement vector. One component is along the East direction and the other perpendicular to the East direction which is the North direction.

Component along the East direction is given as:

East:760\cos 35=622.56\ m

Component along the North direction is given as:

North:760\sin 35=435.92\ m

Therefore, the two components that are mutually perpendicular to each other are 622.56 m East and 435.92 m North.

Final answer:

In physics, the vector components of a displacement of 760 meters at an angle of 35 degrees north of east are approximately 622 meters eastward and 435 meters northward.

Explanation:

The displacement vector you're describing is associated with a movement that falls under the umbrella of vector algebra, a common topic in physics. We're given a magnitude (760 m) for the vector and a direction (35° north of east).

We decompose, or break down, this displacement vector into its component along the east (x-direction) and north (y-direction). This splitting of vectors into components is useful when dealing with multiple vectors as it simplifies calculations.

For the eastward component (x-component, or horizontal), we use the cosine of the given angle. For the Northward component (y-component, or vertical), we use the sine of the given angle. The formulas are as follows:

  • Eastward component=x = 760 m * cos(35)
  • Northward component=y = 760 m * sin(35)

Calculating these gives us roughly x = 622 m eastward and y = 435 m northward. These are the vector components of your original displacement vector.

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True or false day and night are caused by earths rotation

Answers

true because it is day in one part and night in the other
the answer is true! as the earth rotates it also orbits around the sun causing day and night.

WHAT IS THE IMPORTANCE OF THE TROPIC OF CANCER AND TROPIC OF CAPRICORN

Answers

The tropic of cancer and tropic of capricorn has inportance in geographical studies. They help to divide the oceans. They help to classify different countries ( as lying in and around of either of the zones). On classifying, we can also predict weather or atmospheric pressure over the country ( with respect to tropic of cancer or tropic of capricorn). Thus, it has important role in geography. 
they help the divide the world and describe the difference in weather patterns