What is the role of solid particles in the clouds?

Answers

Answer 1
Answer: Well,

The tiny, solid particles you find in the atmosphere serve as cloud condensation nuclei.

You see, in order for water to condense, the water must have a direct object, grammatically speaking.

Your answer: Tiny, solid particles in the atmosphere play a role in cloud formation by providing the object upon which water may condense to form clouds.

Hope this help!

Related Questions

Of course, I'll be the same like anyone else. mARkInG bRaInlESt iF cORrEcT
Compare relative age with absolute age.
How can Ethan best defend his conclusion?
Can somebody match the following ???
When Reggie stepped up to the plate and hit a .15 kg fast ball traveling at 36m/s the impact caused the ball to leave his bat with a velocity of 45m/s in the oppsite direction. If the impact lasted 0.0020s, what force did Reggie exert on the ball

15 POINTS! Yes, more science... What kind of tool can you use to view atoms and molecules up close?

Answers

Generally, molecules are hard to see up close, that is why models are made. So that people can see the structure of atoms and how the nucleus looks. 

Other then a model, an transmissional electron microscope is used to look at atoms up close. 
Well, its a microscope pretty much. But they are called "electron microscopes". But yea just a microscope. ...... oh yeah also a scanning tunneling microscope :)

Suppose a scientist made this model.what info did the scientist need to know in order to make the model

Answers


Suppose I wanted to answer this question about the model.
What info about the model would I need to know in order to
make any intelligent guess about the model ?

Hint: 
It would really help if I could SEE the model, or at least a photo of it.

Should rare earth metals continue to be used in magnets? How come?

Answers

I believe yes because then if some how someone discovers a new metal substance then we can judge wheather or not that substance is magnetic.
No because since they are rare they should find some other metal for this because they're rare so we are going to run out soon because we are using them for magnets.
P.S. if you can think of any thing else to put on go a headand do it because your answer could be yes for some reason

a ball is thrown horizontally from the roof of a building 45.0 m tall and lands 24.0 m from the base. What was the ball´s initial speed?

Answers

ball drops 45m under g=10m/s/s

45=1/2x10xt^2 ... application of kinematic equaion from rest

90/10=t^2

t=3

24.0 m in 3 secs => 8m/s no air resistance

Final answer:

The ball's initial speed is calculated using the principles of projectile motion. First, the time it takes for the ball to hit the ground is found using the vertical distance and acceleration due to gravity.  the initial speed to be approximately 7.9 m/s.

Explanation:

The problem describes a case of projectile motion, a common topic in physics. Since the ball is thrown horizontally, the initial vertical velocity of the ball is zero. We're given that the horizontal distance covered is 24.0 m and the vertical distance is 45.0 m.

Because the horizontal and vertical motions are independent, we can use the equations of motion to solve the problem. First, we have to find the time it takes for the ball to hit the ground. Using the equation of motion

"y = 0.5*g*t²",

where y = 45 m is the vertical distance, g = 9.8 m/s² is the acceleration due to gravity, and t is the time in seconds. Solving for t gives us the square root of (2*y/g), which is approximately 3.03 seconds.

Second, we use this time to find the initial speed of the ball. The horizontal distance covered x = 24.0 m is equal to the product of the time it's been travelling and its initial horizontal speed (v = x/t). Using the time from the previous step, we can find the initial speed to be approximately 7.9 m/s.

Learn more about Projectile Motion here:

brainly.com/question/29545516

#SPJ2

Why AA batteries run exactly 1.5V?

Answers


They don't.

Just for you, I pulled seven (7) AA cells out of a fresh pack from the
store, taped them down to my desk, collected a few other things,
and made these measurements:


AA Cell     Open     at 25 mA     Calc int R, Ω   
     #1         1.596      1.546                  3.285
     #2         1.601      1.551                  3.285
     #3         1.598      1.539                  3.876
     #4         1.578      1.548                  1.971
     #5         1.600      1.539                  4.008
     #6         1.598      1.526                  4.730
     #7         1.600      1.547                  3.482

The (open/unloaded) voltage of the cell is determined by
the cell's "chemistry" ... the actual chemicals and metals
it's constructed from ... that undergo the chemical reaction
to deliver current between the terminals when a conductor
is connected there.

-- The variation in voltage among these 7 cells is about  1.44% .

-- The variation in the internal resistance of these cells ... an
indication of how much current (amps) a cell can deliver ...
varies over a range of almost 140% .  I am surprised.

 We all run into a situation whenbatteries in our remotes, toys, keyboards/mice run out. If we don't know how tocheck a battery we might throw out a perfectly fine battery (especially when wehave a pile of them somewhere in the drawer).  

This electronics tip has to deal with checking common alkaline AA/AAA batteriesor AA/AAA rechargeable batteries for proper voltage with a voltmeter.

Disclaimer : some people might say that a battery should always be tested underload but I have found that in most common household applications this isinsignificant and will not change the results of the testing too much. 

A 4.0 kg bucket of water is raised from a wellby a rope.
The acceleration of gravity is 9.81 m/s?.
If the upward acceleration of the bucket is
2.8 m/s², find the force exerted by the rope
on the bucket of water.
1. 69.658
2. 52.84
3. 85.318
4. 70.86
5. 84.429

Answers

Explanation:

Draw a free body diagram of the bucket.  There are two forces:

Tension force T pulling up.

Weight force mg pulling down.

Sum of forces in the y direction:

∑F = ma

T − mg = ma

T = mg + ma

T = m (g + a)

Given m = 4.0 kg, g = 9.81 m/s², and a = 2.8 m/s²:

T = (4.0 kg) (9.81 m/s² + 2.8 m/s²)

T = 50.44 N