Plz help me i need to know how to do this!!!

Answers

Answer 1

Answer:

Equivalent conversions:

1 atm = 760 mm Hg = 101.325 kPa

Dalton’s law is presented inthis formula, P = p1 + p2 + … +pn where p1, p2 to pn are the pressures of theindividual gases and the P is the total pressure.

Let p1 = CO2, p2 = O2 and p3 =N2

p1 = 125mmHg (1 atm/760 mmHg) =0.1645 atm

p2 = 22 kPa (1 atm/101.325 mmHg)= 0.2171 atm

P = p1 + p2 + p3

1.5atm = 0.1645 atm + 0.2171 atm+ p3

p3 = N2 = 1.1184 atm

Related Questions

What are 5 examples of gases found at home?
Explain how you know the numbers of atoms in your formula. Carbon Monoxide
A student made a copper bracelet by hammering a small copper bar into the desired shape. The bracelet has a mass of 30.1 grams and was at a temperature of 21°C in the classroom. After the student wore the bracelet, the bracelet reached a temperature of 33°C. Later, the student removed the bracelet and placed it on a desk at home, where it cooled from 33°C to 19°C. The specific heat capacity of copper is 0.385 J/g•K.69 Explain, in terms of heat flow, the change in the temperature of the bracelet when the student wore the bracelet. [1] 70 Determine the number of moles of copper in the bracelet. [1] 71 Show a numerical setup for calculating the amount of heat released by the bracelet as it cooled on the desk. [1] 72 Explain, in terms of chemical activity, why copper is a better choice than iron to make the bracelet. [1]
Consider the solutions, 0.04 m urea [(NH2)2C=O)], 0.04 m AgNO3 and 0.04 m CaCl2. Which has (i) the highest osmotic pressure, (ii) the lowest vapor pressure, (iii) the highest boiling point?
The decomposition of ammonia gas (a process that occurs at high temps) is 2KH3(g) --> N2(g) 3H2(g). If a balloon was filled with 3.5L of ammonia gas and all of the gas decomposed, what would be the total volume of gas in the container? Assume the pressure and temp remains constant.

Consider the processes I) NaCl(s) −→ Na+(aq) + Cl−(aq) II) CaCO3(s) −→ CaO(s) + CO2(g) III) H2O(ℓ) −→ H2O(s) For which cases would entropy of the system increase as the given process proceeds left to right? 1. I, II, III 2. I, II 3. III only 4. I, III 5. II only 6. II, III 7. I only

Answers

Answer:

Option 2

In process I & II entropy of the system increases proceed from left to right.

Explanation:

Entropy is an extensive property of the system. It means it depends on the amount or quantity of the system

In case for process 1

since one mole sodium chloride dissolve in water and it dissociate into two ions i.e. Na⁺ and Cl⁻

For process 2

CaCO₃(s) → CaO(s) + CO₂(g)

Change in gaseous moles = (Product moles - reactant moles)

⇒ Δng = 1

Since Δng > 0 it means randomness increases of the system from left to right. So, ΔS > 0

Final answer:

Processes I (dissolving NaCl) and II (decomposition of CaCO3) show an increase in entropy, whereas process III (freezing water) shows a decrease. Therefore, the entropy of the system increases for processes I and II, not III.

Explanation:

The student has asked which processes have an increasing entropy as they proceed from left to right. Entropy is a measure of the disorder or randomness in a system, and changes in entropy can be predicted based on phases changes, the dispersion of matter, and the change in the number of particles in a system.

For the process of dissolving NaCl (s) into Na+(aq) and Cl-(aq), entropy increases due to the dispersion of the solid into ions, hence increasing the randomness of the system. Therefore, process I has an increasing entropy. In process II, we have CaCO3 (s) decomposing into CaO (s) and CO2 (g), leading to an increase in the number of gaseous molecules, which significantly increases entropy compared to the original solid state. Lastly, process III involves the transition of H2O (l) into H2O (s), which means that water is going from a more disordered liquid state to a more ordered solid state, decreasing the entropy of the system.

Considering these details, the entropy increases for processes I and II but decreases for process III. Therefore, the correct answer to the student's question is option 2, which indicates that entropy increases for processes I and II.

Learn more about Entropy Change here:

brainly.com/question/32484278

#SPJ3

You have a 1 L container of a gas at 20 C and 1 atm. Without opening the container, how could you tell whether the gas is chlorine or fluorine?a. measure the mass of the gas
b. measure the speed of the gas molecules
c. measure the volume of the container
d. measure the pressure of the gas in the container

Answers

Without opening the container, a. measure the mass of the gas. Once you get the mass of the gas, you can calculate its density because you already know its volume which has a value of 1 liter. To take the mass of the gas, make sure you don't include the mass of the container. It would be better to measure the container before putting the gas and after putting the gas, and then subtracting the values.

Given that ka for hclo is 4.0 x 10-8 at 25 °c, what is the value of kb for clo- at 25 c

Answers

The Ka of HClO is 4.0 x 10^-8 at 25 C. The dissociation of HClO is:

HClO + H2O ---> H+ + ClO - T = 25 C

Ka = 4.0 x 10^-8 = [H+][ClO-]/[HClO]

pH = -log[4.0 x 10^-8]
pH = 7.40
pOH = 14 - 7.40
= 6.60
Kb = 10^-6.6

How many moles in 28 grams of CO2

Answers

In the given question, in 28 grams of $\rm CO_2$ molecule 0.636 moles are present.

A mole is the amount of a substance which comprises exactly $6.022* 10^(23)$ 'elementary entities' of that substance.

To find the number of moles in 28 grams of $\rm CO_2$ , we first need to determine the molar mass of $\rm CO_2$ .

Molar mass of $\rm CO_2$ = 12.01 g/mol (carbon) + 2(16.00 g/mol) (oxygen)

= 44.01 g/mol

Now that we know the molar mass of $\rm CO_2$ , we can use the following formula to calculate the number of moles:

$\rm Number \ of\ moles = \frac {mass \ of \ sample\ (in \ grams) }{ molar\ mass}$

$\rm Number\ of\ moles = \frac {28 \ g }{44.01\ g/mol }$

= 0.636 mol

Therefore, there are 0.636 moles in 28 grams of $\rm CO_2$ .

Learn more about Mole here:

brainly.com/question/30892840

#SPJ6

That is approximately .63620 grams.

I found a type of rock in the woods it's kinda rough black with some purple like a lavender purple and i can break it into pieces what could it be?

Answers

It could be a lump of coal.
Since you can break pieces off, maybe charcoal ... the real thing, not a "briquet".
Do your hands get all black when you handle it ?

Polly is pushing a box across the floor with a force of 30 N. The force of gravity is –8 N, and the normal force is 8 N. Which value could describe the force of friction if Polly could not move the box?

Answers

The answer is -30 N

The explanation:

- to make the box move. so,the horizontal force must be greater than the frictional force.

-and when the horizontal force applied is 30 N. So, the box will remain stationary if the frictional force is equal in magnitude but opposite in direction to the horizontal force. means frictional force = -30 N

This is also being indicate that vertical force due to gravity is equivalent to the normal force when gravity force = 8 N and normal force =8 , meaning the box does not move vertically.

Read more on Brainly.com - brainly.com/question/4162941#readmore

the answer is -30*N.................