Each molecule of table sugar, C12H22O11, containsa.
0 atoms of carbon.
c.
6 atoms of carbon.
b.
1 atom of carbon.
d.
12 atoms of carbon.

Answers

Answer 1

Answer:

Answer : The correct option is, (d) 12 atoms of carbon.

Explanation:

The formula of given molecule of table sugar is, $C_(12)H_(22)O_(11)$

The given molecule is made up of three elements which are, carbon, hydrogen and oxygen.

In the given molecule of table sugar $C_(12)H_(22)O_(11)$ , there are 12 number of carbon atoms, 22 number of hydrogen atoms and 11 number of oxygen atoms.

From the given options we conclude that, the option (d) is the correct option. While the other options are incorrect.

Hence, the correct option is, (d) 12 atoms of carbon.

Answer 2

Answer: d, because C12 means there's 12 atoms of carbon.

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What is work?O A. Force times an object's displacement
B. The distance an object moves over time
C. The time it takes an object to move a certain distance
D. The force that distance makes
SUBMIT

Answers

Answer:

A:force times an object displacement

Explanation:

Answer Force time an object displacement explanation: Search Results
Featured snippet from the web
A force is said to do work if, when acting, there is a displacement of the point of application in the direction of the force. ... Work transfers energy from one place to another, or one form to another. The SI unit of work is the joule (J).

Calculate the massa of water produced if 1.00 gran of hydrogen is burned in 10.00 grams of oxygen(work as well pleaseee)

Answers

The first step to this question is finding the balanced chemical reaction.
H₂+1/2O₂⇒H₂O
Then you need to find the limiting reagent by finding the moles of each reactant then finding how much product each amount of reactants will form. The reactant that produces the least amount of product is the limiting reagent.
moles of H₂:
1g/(1g/mol)=1mol
moles of O₂:
10g/32g/mol=0.3125mol
moles of H₂O formed with amount of H₂:
1molH₂x(1molH₂O/1molH₂O)=1molH₂O
moles of H₂O formed with amount of O₂:
0.3125molO₂x(1molH₂O/0.5molO₂)=0.625molH₂O
Since less water is produced with the amount of oxygen given, oxygen is the limiting reagent and the moles of water formed from the oxygen is the moles of H₂O we will use to find the amount of H₂O produced.
0.625molH₂Ox18g/mol=11.25g H₂O

Which of the following is not a valid conversion factor? 1/100 centimeter 1mL/1cm^3 1kilometer/1000 meters 1meter/10 milimeters

Answers

1meter/10 milimeters which should be 1000 mm

1m=1000mm

International System of Units (SI Units) are organized body of measurements for physical quantity. They are set to be the norm or global norm scaling for every physical quantity which includes kilogram, meter, second, ampere, kelvin, candela and mole. These measurements then can increase or decrease by the power of ten, multiplied or divided. As said and explained, the SI is helpful in describing objects because
1. They give us the idea of how much matter is contained in that single substance or the current state the matter is in or how hot or cold. We measure and can quantify the quality of the specific matter.
2. SI Units are a global set of measurement hence, we can communicate with ease from western to eastern countries with these measurements without having problems in terms of portraying or displaying a set of physical quantities.

Answer:hello

Explanation:

Task masters

Is correct! It should be answer(4) or (D)

A rigid cylinder with a movable piston contains 50.0 liters of a gas at 30.0 degree C with a pressure of 1.00 atmosphere. What is the volume of the gas in the cylinder at STP?(1) 5.49 L (3) 55.5 L
(2) 45.0 L (4) 455 L

Answers

Charles law states that volume of a gas is directly proportional to temperature at constant pressure for a fixed amount of gas. the pressure at given conditions is 1.00 atm and the standard pressure at STP conditions too is 1.00 atm therefore pressure remains constant.
V1/T1 = V2/T2
the parameters for the first instance are on the left side and parameters at STP are on the right side of the equation.
T1 - temperature in kelvin - 273 + 30.0 °C = 303 K
T2 - standard temperature - 273 K
V1 - volume - 50.0 L
substituting the values in the equation
50.0 L / 303 K = V / 273 K V = 45.0 L
answer is 2) 45.0 L

Answer: The volume of the gas at STP is 45.0 L. hence the correct answer is option(2).

Explanation:

Initial volume of the gas, $V_1$ = 50.0 L