The heat of combustion of propane, C3H8, is 2220 kJ/mol. The specific heat of copper is 0.385 J/g°C. How many grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C, assuming none of the heat is lost to the surroundings?
Answers
The heat of combustion (Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions.
3.05988g. grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C.
What is meant by heat of combustion?
- The heat of combustion (
Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions. In most cases, a hydrocarbon reacts with oxygen to produce carbon dioxide, water, and heat.
- The heat of combustion of a substance is the amount of energy released when a specific amount (e.g., 1 mol, 1g, 1 L) of the substance completely burns in oxygen. The heat of combustion is typically measured at 298K (25 C) and 101.3kPa.
- The energy released when a substance X completely burns with an excess of oxygen under standard conditions (25°C and 1 bar). It is the inverse of the enthalpy change for the combustion reaction in thermodynamic terms.
q=m*c*(change of T)
q=10000g(0.385J/g*c)*(65.0C-25.0C)or (338.2 K-298.2K)
q=154000J
154000J*(1 mol/2220 KJ)=69.36936 x mol
here's where I'm stuck
0.069369 mol
and i know that for every 1 mol there is 44.11g of C3H8.
0.069369 mol* (44.11g C3H8)/1mol = 3.05988g.
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Answer:
Explanation:
q = (mass) (temp change) (specific heat)
q = (10000 g) (40 °C) (0.385 J/g⋅°C) = 154000 J = 154 kJ
154 kJ / 2220 kJ/mol = 0.069369369 mol
0.069369369 mol times 44.0962 g/mol = 3.06 g (to three sig figs)
answer choice 4
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