Iron in the form of fine wire burns in oxygen to form iron (III) oxide. Write the balanced chemical equation.

Answers

Answer 1
Answer: 2Fe+3O_2=2Fe_2O_3

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Convert 1.50μm2 to square meters

Answers

1 micro meter = 10^(-6)  meters
1 μm ^2 = 1 μm*1μm = 10^(-6) *10^(-6) =  10^(-12) meters

1.5 μm^2 = 1.5 * 10^(-12) meters

μm^2 is a unit for surface. First you want to convert μm to meters which is unit for length and if you multiply units for length you get unit for surface.

What is the reaction between aspirin and hydrochloric acid

Answers

According to Bronsted-Lowry reaction- an acid is any substance that donates a proton (H+ ion) to another substance hence these two substance are acid aspirin (acetylsalicyclic acid) and hydrochloric acid (HCl). And there are two pairs - an acid with a corresponding conjugate base and a base with a corresponding conjugate acid. These pairs are called conjugate acid-base pairs.

The concentration of an acid or base is defined as the ratio of the amount ofO A. solvent to the amount of solute in a solution
O B. conjugate acid to conjugate base
O C. conjugate base to conjugate acid
OD. solute to the amount of solvent in a solution

Answers

Answer:

Option  C

Explanation:

A buffer  aqueous solution  consists of  

a) either a weak acid along with its conjugate base  

b) or a weak base along with its conjugate acid.  

This is used to prevent change in the pH of a solution whenever an acid or a base is added. The pH of a buffer depends upon the ratio of base to acid and this ratio is determined by the Ka value and Henderson-Hasselbalch equation. An ideal buffer has equal amounts of acid and conjugate base

Hence, option C is correct

In a reaction, chlorine accepts an electron to form Cl-. What is true about the atomic size of the chlorine ion?

Answers

Answer is: The atomic size of the chlorine ion is larger than the size of the chlorine atom.

Covalent radii of chlorine atom (Cl) is 0.099 nm and ionic radii of chlorine anion (Cl⁻) is 0.181 nm.

Difference between an chlorine atom and chlorine anion is the number of electrons that surround the nucleus.

Chlorine atom has 17 electrons and chlorine anion has 18 electrons.

When a neutral atom that has a charge of negative absorbs an electron, this tends to lessen the size of the ion. The larger the negative charge of the negatively charged element, the smaller the size of the ion will be. Hence the answer is that the ion will have a smaller size than the neutral atom

Which of the following reactions show a decrease in entropy? a. CaO(s) + H2O(l) Ca(OH)2 (s) b. 2H2O (l) 2 H2 (g) + O2 (g) c. H2CO3 (aq) CO2 (g) + H2O (l) d. 2KClO3 (s) 3O2 (g) + 2KCl (s)

Answers

The correct answer is a. CaO(s) + H2O(l) Ca(OH)2 (s)
Decreasing in entropy means that you have to get a solid from the liquid
therefore : CaO(s) + H2O(l) Ca(OH)2 (s)
This formula will make it absolutely clear 
(g) -\ \textgreater \ (l) -\ \textgreater \ (s) more molecules -\ \textgreater \ less molecules

Answer: The correct answer is Option a.

Explanation:

Entropy is defined as the measurement of randomness in a system.

Entropy increases as we move from solid state to liquid state to gaseous state and it decreases as we move from gaseous state to liquid state to solid state.

From the options above:

Option a:CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)

Entropy is getting decreased because liquid reactants are changing its state to solid state.

Option b:2H_2O(l)\rightarrow 2H_2(g)+O_2(g)

In this reaction, entropy is increasing because the state is changing from liquid to gaseous state.

Option c: H_2CO_3(aq.)\rightarrow CO_2(g)+H_2O(l)

In this reaction, entropy is increasing because the state is changing from liquid to gaseous state.

Option d:2KClO_3(s)\rightarrow 3O_2(g)+2KCl(s)

In this reaction, entropy is increasing because the state is changing from solid to gaseous state.

Hence, the correct answer is Option a.

Pick the answer that most likely represents the substances’ relative solubilities in water.(A) CH₃CH₂CH₂CH₃ < CH₃CH₂CH₂OH < HOCH₂CH₂OH
(B) CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃ < HOCH₂CH₂OH
(C) CH₃CH₂CH₂CH₃ < HOCH₂CH₂OH < CH₃CH₂CH₂OH
(D) HOCH₂CH₂OH < CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃
(E) HOCH₂CH₂OH < CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃

Answers

the naswer should be A

Answer:

83

Explanation:

eighty-three